py_20250506

1 - 2# with raos, pao et vaos

Loustau, JM.
2023

white Bc1 Se2 Kf1 Rf5d4 Pg6 VAa3 ROd2h4 black Ra1 Kb1 Pe3a2b5c4 VAa8g3 PAc5

#2(9+9)
🨶a3, 🨼a8, g3: Vao
󼎜d2, h4: Rao
🨻c5: Pao

: chinese rose
For a movement without a capture, it moves in several successive Knight jumps rounded.
to perform a capture, a jumper is required on the course
: Pao is a chinese Rook which therefore needs a jumper to capture

: chinese Bishop

Solution

{

} 1.Rf5*c5 ? {(threatens} 2.Rc5*b5 # {)
} 1...b5-b4 ? 2.ROd2-d6 # {(mate thanks to the a3 jumper; c2 is now controlled thanks to the d4 jumper by Rao h4)
but} 1...BVg3-d6 ! {
} 1.RAd2-e4 ? {(threatens} 2.Rd4-d2 # {)
} 1...PAc5-c6 {(activating Vao a8)} 2.Rf5*b5 # {
but} 1...PAc5-d5 ! 2.Rd4-d2 BVa8*e4 {
} 1.RAd2-d6 ? {(threatens} 2.Rd4-e4 # {and not} 2.Rd4-d2 BVa8-e4 ! {)
} 1...PAc5-d5 2.Rd4-d2 # {
} 1...BVg3-e1 2.WVa3-b4 # {
} 1...PAc5*c1 2.Rf5*b5 # {
but} 1...PAc5-e5 ! {

} 1.RAd2-b7 ! {(threatens} 2.Rd4-d6 # {but neither} 2.Rd4-d2 + {nor} 2.Rd4-e4 + {due to} 2...BVg3-d6 {)
} 1...PAc5-d5 2.WVa3-d6 # {(another jumper for Rao b7)
} 1...BVg3-e1 2.Rd4-d2 # {(neither} 2.Rd4-d6 + ? {nor} 2.Rd4-e4 + ? BVe1-d2 ! {)
} 1...PAc5-e5 2.Rd4-e4 # {(and not} 2.WVa3-d6 + ? PAe5-e4 ! {)
} 1...PAc5*c1 2.Rf5*b5 # {

"3rd degree threat correction".
Threats are "played by the same white piece on the square previously occupied by the rear piece".
Judge B. Kampmann awarded this problem 2nd prize, having preferred a monstrosity with 31 units (24 of which were black!).
whom he "doesn't like personally [because] he's much too intellectual." !
The theme of the competition was "mate by passive piece",
in other words, the unit attacking the Black King is not the one that has just played.
An invitation to Chinese pieces !}

2 - serial h#4 Machiavellian

Bedoni, R.
2002

white Rc2 Ke1 black Pa3a2b2c3 Kh1

ser-h#4 machiavellian(2+5)

: a side can change the colour of one of its units (once only).

Solution

{

} 1.b2-b1=B 2.a2-a1=R 3.Ta1-a1[+wRa1] 4.Bb1-a2 0-0-0 # !

3 - h=2,5 anticipated chess

Bedoni, R.
2006

white Ka2 Pg6g7 black Ka7 Pg2 Sf8

h=2.5 anticipated chess(3+3)

anticipated chess : a King is also in check when it can be put in check.
For example 1 g8R would check.

Solution

{

} 1.g7-g8=B g2-g1=B 2.g6-g7 Bg1-b6 3.g7*f8=B {Stalemate.
Bc5 is "pinned".}

4 - h#2,5 2 solutions ghost rex inclusiv

Foster, G.
2016

neutral Kd3 Pd7f2 black Pd2

h#2.5 2sol. ghosts(0+1+3)

: a unit can also play from its starting (rebirth) square.
Not to be confused with "Ghost Circé".

Solution

{

} 1...nKd3-d4 2.nPf2-f1=nQ nPd7-d8=nB 3.nQf1-f3 nKd4*d2 # {
mate by double check: by the Bishop via c1 and the Queen via d1.

} 1...nKd3-d1 2.nPf2-f1=nS nPd7-d8=nR + {(check from a1)} 3.nRd8-e8 nSf1-a3 # {
battery mat, nNf1 unmasking nRh1 ;
e2 is controlled by Re8, and Pd2, the black pawn, cannot be taken by the neutral King, playing as the black King. !
And 3...nRh8 would not parry the check, the neutral Rook, playing as a White Rook, checking from a1

bicolour AUW.}

5 - s#6 2 solutions circe

Bryukhanov, I.
2019

white Bf1 Rb1b6 Sc5 Ka1 black Pa6 Ka3

s#6 2sol. Circe(5+2)

Solution

{

} 1.Rb1-c1 ! a6-a5 2.Sc5-a4 Ka3*a4[+wSb1] 3.Rb6-b3 Ka4*b3[+wRh1] 4.Rc1-c4 a5-a4 5.Rh1-h2 a4-a3 6.Rh2-b2 + a3*b2 # {

} 1.Bf1*a6[+bPa7] ! a7*b6 2.Rb1*b6[+bPb7] b7*a6[+wBf1] 3.Bf1-d3 a6-a5 4.Bd3-b1 a5-a4 5.Rb6-b3 + a4*b3[+wRh1] 6.Rh1-h4 b3-b2 #

6 - h#4,5 with set play parrain circe

Stun, J.
2019

white Pe4h4 black Kd3 Pg5

h#4.5 parrain circe(2+2)

: A captured unit makes an equipollent move with the next move played.

Solution

{

Set play :
} 1... ... 2.Kd3*e4 h4*g5[+wPd5] 3.Ke4*d5[+bPf6] g5*f6[+wPc6] 4.Kd5*c6[+bPe7] f6*e7[+wPb7] 5.Kc6*b7[+bPd8] e7*d8=Q[+wQa8] # {

} 1...h4-h5 2.Kd3*e4 h5-h6[+wPe5] 3.Ke4*e5 h6-h7[+wPe6] 4.Ke5*e6 h7-h8=Q[+wPe7] 5.Ke6-f7 e7-e8=Q # {

Diagonal-vertical echo.
Echo Mates.}

7 - h#2 2 solutions reverse anda

Tritten, P.
2019

white Bd1 Kc5 black Pe2c2d5e5a5 Kc3

h#2 2sol. reverse anda(2+6)

: any unit making a move that is not a direct check immediately becomes neutral.
If it is already neutral, it becomes white or black, depending on which side is playing it.

Solution

{

} 1.e2*d1=nQ Qd1*d5[+wQd5] 2.c2-c1=nB Qd5-c4 # {

} 1.e2-e1=nR Re1-e2[+wRe2] 2.c2-c1=nS Re2-c2 # {

AUW.}

8 - h#2,5 2 solutions einstein

Forslund, G.
2002

white Ra8h1 Kh2 black Ke7 Bf7a1 Pg6

h#2.5 2sol. Einstein(3+4)

: when you capture you progress (P-N-B-R-Q) and when you don't capture it's the other way round

Solution

{

} 1...Ra8*a1=Q 2.Ke7-f8 Qa1-h8=R + 3.Kf8-g7 Rh1-a1=B # {

} 1...Rh1*a1=Q 2.Ke7-e6 Qa1-e5=R + 3.Ke6-f6 Ra8-h8=B #

9 - h=3 mars circe

Winterberg, H.
1982

white Ka4 Rb1d1 black Kc3 Bf7

h=3 mars Circe(3+2)

: To capture, we virtually go through the initial square

Solution

{

} 1.Bf7-a2 Rd1-e1 2.Kc3-d2 Re1-g1 + 3.Kd2-e1 Ka4-b3 {pat

Note that} 1.Kc3-d2 {is illegal, not because of Rd1 but because of Ka4.
In picture :} 1...Ka4*d2 !

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