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Small delay in the report; cause of the great richness of the material proposed by the Master.
A little more assembly than usual for this parenthesis is fairy session.
We have noted the return of the great Ricou and of our composer (and solutionist), in the person of the immense Michel.
I take advantage of the intro to give you the date of the next session which will be held on the first Tuesday of the year, that is to say the January 3rd.
In the absence of the aforementioned, Master took the opportunity to deliver two remarkable compositions of a relatively new genre.
To warm up, a first composition
{Try : }
1.Kd1-e1 ? 2.Qb3-b4 3.Ra3-f3 4.Rf3-f1 5.Bb5-c4 6.Bc4-b3 7.Ke1-d1 8.Rf1-e1 9.Qb4-a3 10.Bb3-c2=P {(becomes pawn again, and so Black is free to play something other than} 10...Ba4*c2 #
{)}
1.Bb5-c6 2.Bc6-g2=P ! 3.g2-g4 4.g4-g5 5.g5-g6 6.g6-g7 7.g7-g8=Q 8.Qg8-g3 9.Qg3-e1 10.Qb3-c2 + Ba4*c2 #
: White plays n moves in a row and force Black to checkmate them in one move
: a promotion piece that returns to an initial pawn square becomes a pawn again
A small help :
the last moves could only be Ba2xQ(or B)b1+, ...Ka1xb1.
Ba2, remaining Bishop, was necessarily the original f1 Bishop and so Bb5 comes from a promotion.
Comments on some problems for New Year's Eve. Three #2. The first one solves itself in 3 seconds, at least when you have a certain practice. But that doesn't prevent you from enjoying it. The second shows a "reciprocal correction". A bit abstruse? All this will be clear when you have solved it, in just a little more time. The 3rd has a real JA ("apparent play"), i.e. motivated by a try. He may ask you for two more minutes.
The #3 shouldn't give you a headache either. It is a kind of praise for idleness. The #9 is a bit stronger, but the #10 is obvious: its purpose is to explain a useful rule to the beginner. A Gamnitzer s#5 is always a party. Very well, precisely between two "parties", during the recovery. I've saved the helpmates for the end, contrary to what I'm used to. Of the 4 solutions of the first one, one may embarrass you. One of the h#4 is easy, the other difficult: guess which one. Finally a long and lovely walk.
The fairies will be presented by the master-tabellion. Here's one of them, which had an unexpected success on a usually lethargic forum... as soon as interesting things are discussed. Following a conversation about the tournament which has just ended, I enclose a quick overview of the key game, emblematic example of the difference between human analysis and computer copies. For those who are decidedly resistant to the world of the problem, it will be a bit of reading for Christmas. See you in three weeks time for a course that will be back to "normal" on 3 January. Merry Christmas then. God bless you. And have a good time. AV
: White plays n moves in a row and force Black to checkmate them in one move
: a promotion piece that returns to an initial pawn square becomes a pawn again
A small help : if there was no Rb6, we could do 5.a8=Q+ QxQ stalemate, it must be eliminated beforehand (and it takes 39 moves!).
A problem that is completely understandable and therefore accessible, so look for it, you won't waste your time.
In the same thematic competition, here is the first prize.
2 - series s#48 reversible Promotion
Ofer COMAY & Mark ERENBURG11è Saké jesi, 20111st Prize
white Pb2g2 Kb6
black Qa8 Pd6e6b3 Kb8 Rc7c5f7 Sf4b5
a) : a capturing piece changes colour
b) : a captured piece is reborn on the original square of the capturing piece . .
: Prolonged Knight needing a jumper to perform his first movement (ex: NHb5 can go to f7 or h8).)
: moves to the Queen's lines needing a sautoir behind which it lands if that square is free or occupied by an opponent's piece.
{}
a) {}
1.Ke6*e5 WMf6-h5 2.Ke5-f4 MOg5-f7 #{}
b) {h#1.5}
1...Kd8-c7 2.BMg4*e5 WMf6-g8 #{}
c) {h#1}
1.BMg4*e5 WMf6-e8 #{}
d) {h#0,5}
1...WMf6*g4 #
: Crawling knight that first makes an orthogonal step and then a diagonal one .
The square of the first step must be empty
; Diagonal and then orthogonal creeping knight
A very nice problem.
{}
1.rWGe4-b4 ! {}
1...e6-e5
2.rWGb4-e1 e5-e4
3.Sc4-d6 +
rBGe8-e3
4.Sd2-f1 +
rBGe3-c3
5.Sd6-f5
e4-e3
6.Sf1-g3
e3-e2
7.Sf5-d4
rBGc3-e5 + 8.Sg3-e4 d3-d2 #
{It is checkmate because the squares c3 and e3 are controlled by the Royal Grasshopper e5}
: the capturing piece is reborn on its original square if it is free, otherwise the move is illegal.
: piece moving on the Queen's lines and needing a sautoir to capture
16 - h=10 coups - Ultra-Maximum with Grasshopper et Grasshopper-2
It remains for me to wish you all a good reading, to thank the Master for his course and his electronic report.
And to finish, have a good holiday season and start the course on January 3rd in good conditions.
Yours sincerely.
Le greffier
Master's rectifications
Problem 3: I think it is useful to specify that by "original square of the capturing piece", it is understood that the original square is determined by the finishing square. For example, after ...Nxe4, the grasshopper is reborn in g8, which would be the rebirth square of the BN in anti-circe.
Thanks to the greffier for the difference between "cuckoo" and "couscous" which I didn't know.
Problem 7: there is also a h#0.5, in other words an BK mat in one move.
Problem 16 : the "grasshopper-2" is in a8.
I can't see anything else.
Merry Christmas.
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