# december 10 2013

Click in the right part of the chessboard to move forward, left to move backward...

or directly on the move in the solution

## A word from Daniel

for this fairy session, it was Daniel who did it.

Growing men.

A piece cannot play a move shorter than the one it has played previously (i.e. the last time it played).

The following problems are originals of

**Paul Bissicks**and are only there as an initiation.

### 1 - #1 Growing men

**
Paul BISSICKS**

**#1**

Growing Men

Growing Men

} 1.Qd5*b7? {Which is a move of length 2.28 does not even check the Kh8 located at 1.4.} 1.Qd5-a5?! {A long shot of length 3 checks well against Ka8 ... who counteracts this one with

} Ka8-a7!! {shortening the distance and thus getting out of reach.

Henceù} 1.Qd5-a2# {because this move has a length of 4.24 and therefore makes it possible to reach squares at a distance of 5 or 6 on the next move..}

*for players*. I will therefore content myself with providing you with a harvest of problems... orthodox or heterodox, but affordable by the player

*lambda*.

**4**times. The great Vladimir's #4 is deceptive: apparently there are 2 or 3 ways of mate in 4. But no, that's not it at all! The #5 seemed difficult to me, but perhaps I had my head in the bag. For those who know the author for his batteries where the unmasking piece plays a 2nd move, that's not the idea at all.

**tuesday 7th january**. Good food, not only in diagrams and games, but also good company, even good meal.

### 2 - #2 Growing men

**
Paul BISSICKS**

**#2**

Growing Men

Growing Men

We understand more quickly now that} 1.Qe2-f3+ ? Kh1-h2 2.Qf3-g2 {does not even check and that} 1.Qe2-e4 + Kh1-h2 2.Qe4-h7+ {is not mate because of} 2...Kh2-h3! {

We also note that} 1.Qe2-h5+ Kh1-h2 {would be mate after Qh10 ... on a checkerboard (except that on a checkerboard, the h-column does not allow checkmate from the couloir).

So} 1.Qe2-e5 ! Kh1-h2 2.Qe5-h8 #

### 3 - s#4 Growing men

**
Paul BISSICKS**

**s#4**

Growing Men

Growing Men

We understand that we will have to guide the R to a checkmate in the couloir. The mode lends itself quite well to remote control.. } 1.Bd2-a5 + Ra1*a5 { Now all you have to do is remove the Q, but how. The idea that comes is} 2.Qb1-b5 Ra5-a1 + 3.Qb5-f1 Ra1-a8 4.Qf1-a1 Ra8*a1# { This is twice untrue: on the one hand} 4.Qf1-a1 {is illegal because it is "too short" and on the other hand the Ws would have} 5.Kh1-g1 ! 2.Qb1-a1 Ra5*e5 3.Qa1-a2! {and 2 possibilities : } 3...Re5-a5 4.Qa2-d5! Ra5-a1# {or} 3...Re5-e1 {no check} 4.Qa2-e2! Re1-a1#

### 4 - #4 Growing men

**
Paul BISSICKS**

**#4**

Growing Men

Growing Men

We can imagine that we are going to checkmate from the couloir on column a.} 1.Rd5-d2 {and} 1.Rd5-d3 {must therefore be considered, but after } 1.Rd5-d2? Bh8-b2! {The Ws don't have a really threatening move, } 2.Rd2-f2 {facing} Ka7-a8 3.Rf2*b2 Ka8-a7 {et} 4.Rb2-a2 {is illegal! Hence:

} 1.Rd5-d3 Bh8-c3 2.Rd3-d1! {threatening }threat: 3.Rd1-a1# {

} 2...Bc3-h8 {to control a1} 3.Rd1-d4!! {and }threat: 4.Rd4-a4 {is unstoppable and mate.}

### 5 - #2 Growing men with twin

**
Paul BISSICKS**

**#2 b) Rf3->h4.**

Growing Men

Growing Men

A simple problem that allows you to check that you have understood. We will check that there is no dual !

} a){

} 1.Kf3-e3 Kh2-g3 2.Qf1-f2#{

} b) wKf3-->h4{

} 1.Kh4-g5 Kh2-g3 2.Qf1-g1#

Now, after the initiation, we arrive at

**Turnbull**who gave back his honour to the first name.

. Luckily, in his great anticipation, the Master had chosen enlarging chess, an original but simple genre, so that the simplest works of RT remain accessible there. It was all the better as I was alone. I hope that the great Michel had only a simple impediment.

### 6 - #2 Growing men

**
Ronald TURNBULL**

**#2**

Growing Men

Growing Men

We immediately think of capturing in h5 (with what?) then pushing the K to mate with the R.

} 1.Rh6*h5? Qb5-e8! {(easy).

Donc } 1.Kh4*h5! {Blacks's have 3 variants for intercepting the h-column, resulting in 3 echo variants.

} 1...Qb5-e2+{

} 1...Qb5*e5+{

} 1...Qb5-e8+{

} {How could anyone not like this problem ?}

### 7 - #5 Growing men

**
Ronald TURNBULL**

**#5**

Growing Men

Growing Men

Obviously, we couldn't expect anything else from Turnbull: only one white piece, and it's the only one that has no interest in the chosen genre, all the Knight moves inevitably having the same length! Question : how to avoid mate in 3 by Nf6 or Ng7 ? Knowing that the answer } 1...h3-h2 {followed by } 2...h4-h3 {is not the right one. Genius to serve the imagination is beautiful. ! if Black plays }1...h3-h2{, is that it's a legal move. THEREFORE the h3-pawn has never made a step of more than 1 in length, THEREFORE it comes in direct line from h7 and THEREFORE the h4-pawn comes from another file, has already made a move of 1,414 and THEREFORE it cannot play } 2...h4-h3 { This removes one defence from the Black, but at the same time offers them a new one: lift the stalemate. After a move of Knight, the Black answers }1...g5-g4! {and then, it is the proof that Pg4 comes from g7, so that h6 comes from h7, so that Pg3, h3 and h4 have already played diagonal moves (holds) and are therefore forbidden to advance. But then, what to do? The answer already appears in the above: lift the pat, and since the Knight has no interest in this kind of move ....} 1.Se2-d4! g5-g4! 2.Sd4-f3!! g4*f3 {all the black P's are now static !

}3.Kf5-f6! Kh5-g4 {BK is now condemned to diagonal steps !

}4.Kf6-g6! h6-h5 5.Kg6-g5# !

### 8 - #2 Growing men

**
Ronald TURNBULL**

**#2**

Growing Men

Growing Men

Before going on to the explanations, let's clarify the idea: how do you #2? The only possible scheme is } 1.Kh4-h5# {with a WR controlling g7 and h7. But for the moment, this Kh5 move is not legal. For it to be, it would be necessary that the last Black move is 1...Kg7-h6.

And nothing allows to prove it because the position of the diagram can be obtained with for last move of the rook the move Rf4-f7. And in this hypothesis, the last White move can be g5-g6+ and the last Black move Kh7-h6, the Rf7 not checking Kh7.

If we have understood the above, the solution becomes simple :

} 1.Rf7*c7 { Here, one has no right to conclude on the stalemate, because nothing strictly prohibits the f3 move. So the B's have to play }f4-f3 {But then, the pawn comes directly from f7 and played f7-f6-f5-f4 and so the WR which was in f7 could come at best only from f5 (but not f4) and so it could not make a move longer than 2. But then, the last Black move, which is a move of K, is necessarily Kg7-h6, because in h7 the K would have been in double check. And so from now on, the BK is condemned to diagonal steps.

} 1.Rf7*c7 f4-f3 2.Kh4-h5# {And that's it. }

And for dessert, some positions :

Click in the right part of the chessboard to go forward, left to go backward ...

or directly on the solution move

### 9 - #3 with chinese pieces

**
Hans Peter REHM**

**#3(13+6)**

🨷f1: Nao

🨵e3, f3, 🨻g4: Pao

🨶f2, 🨼h7: Vao

🨓b7: Mao

🨴d7: Leo

🨷f1: Nao

🨵e3, f3, 🨻g4: Pao

🨶f2, 🨼h7: Vao

🨓b7: Mao

🨴d7: Leo

**: moves normally, but to capture, need a sautoir**

the path must be clear between the start square and the sautoir, as well as between the sautoir and the finish square.

le move on the Queen's lines, Pao on the Rook's lines and on Bishop's lines

Le is a special case, it is a Crawling Knight: 1 Rook step then 1 Bishop step.

The square of the rook step must be free. Le is a chinese Nightrider

{

} 1.Kg6-g5 ? threat: 2.Kg5*g4 threat: 3.Sh3-g5 #{

} 1...BPg4-g3 2.WPe3*g3 threat: 3.WPg3-g4 #{

} but 1...Re1-c1 !{

} 1.Kg6-h5 ? threat: 2.Kh5*g4 threat: 3.Sh3-g5 #{

} 1...Re1-d1 2.LEd7*d1 threat: 3.LEd1*g4 # 3.LEd1-e2 # 3.LEd1-e1 #{

} 2...BPg4-g3 3.LEd1-e2 # 3.LEd1-e1 #{

} 2...BPg4-g8 3.LEd1-e2 # 3.LEd1-e1 #{

} 2...BPg4-g7 3.LEd1-e2 # 3.LEd1-e1 #{

} 2...BPg4-g6 3.LEd1-e2 # 3.LEd1-e1 #{

} 2...BPg4-g5 3.LEd1-e2 # 3.LEd1-e1 #{

} 2...BPg4-h4 3.LEd1-e2 # 3.LEd1-e1 #{

} but 1...Re1-c1 !{

} 1.WPe3-e2 ! threat: 2.NAf1-c7 threat: 3.NAc7-a6 #{

} 1...PAg4-g5 2.WVf2-e3 + 2...Re1*e2 3.LEd7-g4 #{

} 1...MAb7*d6 2.NAf1-e3 + 2...Re1*e2 3.LEd7-b7 #{

} 1...BVh7-g8 2.WPf3-e3 + 2...Re1*e2 3.LEd7-h7 #

the path must be clear between the start square and the sautoir, as well as between the sautoir and the finish square.

le move on the Queen's lines, Pao on the Rook's lines and on Bishop's lines

Le is a special case, it is a Crawling Knight: 1 Rook step then 1 Bishop step.

The square of the rook step must be free. Le is a chinese Nightrider

} 1.Kg6-g5 ? threat: 2.Kg5*g4 threat: 3.Sh3-g5 #{

} 1...BPg4-g3 2.WPe3*g3 threat: 3.WPg3-g4 #{

} but 1...Re1-c1 !{

} 1.Kg6-h5 ? threat: 2.Kh5*g4 threat: 3.Sh3-g5 #{

} 1...Re1-d1 2.LEd7*d1 threat: 3.LEd1*g4 # 3.LEd1-e2 # 3.LEd1-e1 #{

} 2...BPg4-g3 3.LEd1-e2 # 3.LEd1-e1 #{

} 2...BPg4-g8 3.LEd1-e2 # 3.LEd1-e1 #{

} 2...BPg4-g7 3.LEd1-e2 # 3.LEd1-e1 #{

} 2...BPg4-g6 3.LEd1-e2 # 3.LEd1-e1 #{

} 2...BPg4-g5 3.LEd1-e2 # 3.LEd1-e1 #{

} 2...BPg4-h4 3.LEd1-e2 # 3.LEd1-e1 #{

} but 1...Re1-c1 !{

} 1.WPe3-e2 ! threat: 2.NAf1-c7 threat: 3.NAc7-a6 #{

} 1...PAg4-g5 2.WVf2-e3 + 2...Re1*e2 3.LEd7-g4 #{

} 1...MAb7*d6 2.NAf1-e3 + 2...Re1*e2 3.LEd7-b7 #{

} 1...BVh7-g8 2.WPf3-e3 + 2...Re1*e2 3.LEd7-h7 #

### 10 - s#10 Mars Circe

**
René J. MILLOUR**

**s#10 Mars Circe(13+5)**

**: the pieces normally move, but to capture, they virtually return to their original square.**

{

} 1.Sa6-c7 {The threats were Bxa6 and Qxb6+.

} 1...Qd1-d2 {became the only legal move preventing Qd1xKd3

} 2.Re2-f2+ {check by the e-pawn and possibly by the Bishop

} 2...Kd3-e3 3.Bb8-a7 {prevents Qxb8

} 3...Qd2-c1 4.Sc7-e8 Qc1-d2 5.Qb6-c7! {tempo !

} Qd2-c1 6.Qc7-d8 Qc1-d2 7.Rf2-e2+{

} Ke3-d3 8.Ba7-b8 Qd2-d1 9.Bc2-a4+ {close the box

} 9...Kd3-c2 10.Qd8-c7 Qd1*c7# {

Superb mechanics !}

} 1.Sa6-c7 {The threats were Bxa6 and Qxb6+.

} 1...Qd1-d2 {became the only legal move preventing Qd1xKd3

} 2.Re2-f2+ {check by the e-pawn and possibly by the Bishop

} 2...Kd3-e3 3.Bb8-a7 {prevents Qxb8

} 3...Qd2-c1 4.Sc7-e8 Qc1-d2 5.Qb6-c7! {tempo !

} Qd2-c1 6.Qc7-d8 Qc1-d2 7.Rf2-e2+{

} Ke3-d3 8.Ba7-b8 Qd2-d1 9.Bc2-a4+ {close the box

} 9...Kd3-c2 10.Qd8-c7 Qd1*c7# {

Superb mechanics !}

### 11 - h#4 Functionnary Chess with Grasshoppers and Dragon

**
Stephan DIETRICH**

**h#4 Functionnary Chess(4+3)**

b) turn 90° to the right

🨟c5, c4, 🨥g5: Grasshoppers

🨍d5: Dragon

b) turn 90° to the right

🨟c5, c4, 🨥g5: Grasshoppers

🨍d5: Dragon

**: so that a piece can move, and a fortiori capture, it must be "observed" by at least one opposing piece**

: piece moving like a Queen but needing a sautoir behind which it lands

the path must be clear between the starting square and the sautoir, and, behind the sautoir,

the square must be free or occupied by an opponent's piece

: a piece that moves like a knight as well as a pawn.

{

} a) {

} 1.Sf6-e4 DRd5-e3 + 2.Kd4-d5 WGc5-f2 3.Se4-d6 Kf5-f6 4.BGg5-c5 WGf2-d4 # {

mate by the Dragon which is "observed" by the Grasshopper c5, which cannot move, being attacked by nobody

. the King is "observed" by the Dragon and can thus capture d4, but in doing so, he puts himself in mutual "observation" by the pawn part of the Dragon

} b) rotate 270 {rotate 90° right} {

} 1.Sf3-d4 DRe5-c4 + 2.Kd5-e5 WGe6-b3 3.Sd4-f5 Ke3-f3 4.BGe2-e6 WGb3-d5 # {

Same kind of remark}

: piece moving like a Queen but needing a sautoir behind which it lands

the path must be clear between the starting square and the sautoir, and, behind the sautoir,

the square must be free or occupied by an opponent's piece

: a piece that moves like a knight as well as a pawn.

} a) {

} 1.Sf6-e4 DRd5-e3 + 2.Kd4-d5 WGc5-f2 3.Se4-d6 Kf5-f6 4.BGg5-c5 WGf2-d4 # {

mate by the Dragon which is "observed" by the Grasshopper c5, which cannot move, being attacked by nobody

. the King is "observed" by the Dragon and can thus capture d4, but in doing so, he puts himself in mutual "observation" by the pawn part of the Dragon

} b) rotate 270 {rotate 90° right} {

} 1.Sf3-d4 DRe5-c4 + 2.Kd5-e5 WGe6-b3 3.Sd4-f5 Ke3-f3 4.BGe2-e6 WGb3-d5 # {

Same kind of remark}

### 12 - serial s#37

**
Unto HEINONEN**

**ss#37(6+8)**

**: White plays n moves in a row to bring a position in which Black is forced to checkmate in one.**

{

} 1.b2-b4 2.b4-b5 3.b5-b6 4.b6-b7 5.b7-b8=B 6.Bb8-a7 7.Ba7*e3 8.Be3-g5 9.f2-f4 10.f4-f5 11.f5-f6 12.f6-f7 13.f7-f8=R 14.Rf8-f4 15.Ke4-f5 16.e2-e4 17.e4-e5 18.e5-e6 19.e6-e7 20.e7-e8=Q 21.Qe8*a4 22.Qa4-b3 23.a2-a4 24.a4-a5 25.a5-a6 26.a6-a7 27.a7-a8=B 28.Ba8-g2 29.Bg2*h3 30.Bh3-g4 31.h2-h4 32.h4-h5 33.h5-h6 34.h6-h7 35.h7-h8=S 36.Sh8-g6 37.Qb3-g3+ Sh1*g3# {

AUW plus supplement}

} 1.b2-b4 2.b4-b5 3.b5-b6 4.b6-b7 5.b7-b8=B 6.Bb8-a7 7.Ba7*e3 8.Be3-g5 9.f2-f4 10.f4-f5 11.f5-f6 12.f6-f7 13.f7-f8=R 14.Rf8-f4 15.Ke4-f5 16.e2-e4 17.e4-e5 18.e5-e6 19.e6-e7 20.e7-e8=Q 21.Qe8*a4 22.Qa4-b3 23.a2-a4 24.a4-a5 25.a5-a6 26.a6-a7 27.a7-a8=B 28.Ba8-g2 29.Bg2*h3 30.Bh3-g4 31.h2-h4 32.h4-h5 33.h5-h6 34.h6-h7 35.h7-h8=S 36.Sh8-g6 37.Qb3-g3+ Sh1*g3# {

AUW plus supplement}

### 13 - h#2 AntiCirce Isardam with Equihoppers

**
Manfred RITTIRSCHdédicate to F. PACHL for his 60 yearsDie Schalbe, 2011**

**h#2 AntiCirce Isardam(5+12)**

2 solutions

🩈h7, 🩉d1: Equihoppers

2 solutions

🩈h7, 🩉d1: Equihoppers

**: the capturing piece is reborn on its original square if it is free, otherwise the move is illegal.**

: it is illegal to put two opposing pieces of the same nature in mutual "observation".

: piece moving only with a sautoir which is the centre of symmetry between the start and target squares.

{

} 1.Rf8-b8 Kh3-g3 {Nh1xg3 is illegal, the renaissance square of the Knight (b8) being now occupied

. Note that Kg2 would give the escape square g6 to the Black King.

} 2.BEd1-d3 Se3-d5 # {

f5 is the centre of symmetry between the 2 Equihoppers, so Kf5 would put the 2 Equihoppers in mutual "observation".

} 1.Rf8-d8 Kh3-h2 {Qe2xh2 is illegal, as the Queen's rebirth square (d8) is now in use.

} 2.BEd1-b5 Sc7-d5 # {

e6 is the centre of symmetry between the 2 Equihoppers, so Ke6 would put the 2 Equihoppers in mutual "observation".}

: it is illegal to put two opposing pieces of the same nature in mutual "observation".

: piece moving only with a sautoir which is the centre of symmetry between the start and target squares.

} 1.Rf8-b8 Kh3-g3 {Nh1xg3 is illegal, the renaissance square of the Knight (b8) being now occupied

. Note that Kg2 would give the escape square g6 to the Black King.

} 2.BEd1-d3 Se3-d5 # {

f5 is the centre of symmetry between the 2 Equihoppers, so Kf5 would put the 2 Equihoppers in mutual "observation".

} 1.Rf8-d8 Kh3-h2 {Qe2xh2 is illegal, as the Queen's rebirth square (d8) is now in use.

} 2.BEd1-b5 Sc7-d5 # {

e6 is the centre of symmetry between the 2 Equihoppers, so Ke6 would put the 2 Equihoppers in mutual "observation".}

### 14 - #3

**
Sam LOYDAmerican Chess Magazine, 1898**

**#3(9+3)**

} 1.f7-f8=Q + ? but 1...Rd8*f8 !{

} 1.f7-f8=B + ? but 1...Rd8*f8 !{

} 1.c7*d8=S ? but 1...Bd7-c6 + !{

} 1.c7*d8=B ? but 1...Bd7-f5 + !{

} 1.Re5-e6 + ? but 1...Kd6*e6 !{

} 1.c7*d8 ! {threatens} 2.f7-f8=Q # {or} 2.f7-f8=B # {

} 1...Bd7-c6 + 2.b5*c6 {threatens} 3.Re5-e6 # {or} 3.b4-b5 # {

} 2...Kd6*c6 3.b4-b5 # {

} 1...Bd7-f5 + 2.Re5*f5 {threatens} 3.f7-f8=Q # {or} 3.f7-f8=B #{

} 2...Kd6-e7 3.f7-f8=Q #{

} 1...Bd7*c8 2.f7-f8=Q + 2...Kd6-d7 3.Qf8-e7 # {

Loyd had both talent and imagination !}

Thanks to Daniel for his pedagogical approach

next class on January 7th

Have a nice holiday

Yours faithfully

Le greffier virtuel

## Gallic hair

Qd5xb7: I would have said "length 2.8".

Nao : I don't really like the name "Mao of the night" because the Mao crawls, but not the Nao! The Mao b7 can capture the Pd6 but not the Pc5.

The Nao is to the Nightrider what the Leo is to the Queen, the Pao to the Rook and the Vao to the Bishop: he only needs the sautoir to capture.

Dietrich : clearer than this 270° without any precise meaning, to say that in the twin, the WK comes in **d6** and the BK in **e4**.

**2 solutions**.

Merry Christmas.

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