py_20120110

h#2 Anti-Circe

: capturing unit is moved on its original square if free
If not, capture is not legal

Pierre TRITTEN
The Problemist 2010

white Rg1 Kb8 Ba1 Sc1 black Qg8 Pa6b6a4 Ka5 Bd4e8 Sd2

h#2 AntiCirce(4+8)
3 solutions

{

} 1.Bd4*a1[bBa1->f8] Sc1-b3 2.Bf8-b4 Rg1-g5 #{

} 1.Bd4-b2 Rg1-g5 2.Bb2*c1[bBc1->f8] Ba1-c3 #{

} 1.Bd4*g1[bBg1->f8] Ba1-c3 2.Be8-b5 Sc1-b3 #

h#2 parrain Circé

: captured unit stay under capturing square and make equipollent move copying next move

Vito RALLO
The Problemist Supplement 2009

white Kc6 Bg4 Sg5 black Ke7 Re4 Sf7

h#2 Parrain Circe(3+3)
b) ♜e4-->e5

Solution

{

} a) {

} 1.Re4*g4 Sg5*f7[+wBf6] + 2.Ke7-e8[+bSf8] Sf7-d6 #{

} b) bRe4-->e5{Re4-->e5

} 1.Re5*g5 Kc6-c7[+wSg6] + 2.Ke7-e8 Bg4-d7 #

serial s=10

: White plays n moves in a row and only legal Black move is mate (or stalemate) in one

Bernd GRAEFRATH
The Problemist Supplement 2008

white Pc2d3g4 Kh5 black Pg7e7 Rg8h8 Bf8 Kh7 BGe6

ser-s#10(4+7)
🨥e6: Grasshopper

Solution

{

} 1.c2-c4 2.c4-c5 {

} 3.c5-c6 4.c6-c7 {

} 5.c7-c8=G 6.Gc8-f5 {

} 7.Gf5-c2 8.d3-d4 {

} 9.d4-d5 10.d5*e6 g7-g5 {stalemate !!
Of course,} 10...g7-g6 { would put his own King in check by the Grasshopper}

h==3 Madrasi

: two opposite units of same kind (except Kings) mutually in "observation" are paralyzed
h== : the two sides are stalemated with the last white move

Arpád MOLNAR
The Problemist 2008

white Ke6 Pe5f7 Ba8a7 Rb2f1 Sd7 black Bh1 Kd3 Qc1 Pf2g2 Sb8 Rh2c8

h==3 Madrasi(8+8)

Solution

{

} 1.g2-g1=B Rb2-a2 {

} 2.Qc1-a3 Rf1-c1 {

} 3.f2-f1=Q f7-f8=Q { double stalemate !!
Very good move saving with no extra condition}

Add a comment