py_20170307

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or directly on the move in the solution

1 - serial h#18 with Equihopper

H.HELLEDIE
1972

white Ke5 Rc2 Sg1f1 black Pe6 Kh1 EQh2
ser-h#18(4+3)
🩉h2: Equihopper
unit that moves using another unit as the centre of symmetry of its movement

Solution

 

2 - #2 Lortap

Y.CHEYLAN
2008

white Bg1f1 Ka6 Qa8 Pc6d4h2a4b3 Sg5a3 Rh3 black Pb6d7d6d5e2b4 Kc5 Bg2a1 Rh4g6
#2 Lortap(12+11)
(or anti-patrol): a piece can only capture if it is not observed by a piece of its side
. Pd4 does not check, but 1 Re3? would (parried by ...Bxd4!).

Solution

 

3 - h#2 Mars Anti Circe with Sparrow

R.KOHRING
2016

white Ke8 SWa7 black Pd2 Kd4 Sb1a5
h#2 Mars Anti Circe(2+4)
b) ♟d2-->e2
🨊a7: Sparrow
to make a move without a capture, a piece virtually passes through its original square
: Sparrow returns 45 degrees from the sautoir, i.e. the angle square of arrival of the Sparrow-jumper-case of arrival of the Grasshopper is 135 degrees. A Sparrow a1, with a sautoir d4, can go to d3 or c4.

Solution

 

 

4 - serial h#11 Mars Anti Circe

R.KOHRING
2016

white Pf6 Kh4 Bd4 black Pc3 Kc1 EAb4
ser-h#11 Mars Anti Circe(3+3)
🨺b4: Aigle (Eagle)
it's an in b4. The eagle makes a 90 degree angle with the sautoir. An eagle a1, with a sautoir d4, can go to c5 or e3.

Solution

 

5 - sérial reflex #18

E.BOURD
2016

white Pc7c6f5 Sa8h8 Kh5 black Ra4 Sf7 Ba6 Kc8 Pc4
ser-r#18(6+5)
when a mat is presented, we are obliged to execute it

Solution

 

 

6 - h=4 Mars Circe

V.CRISAN
1997

white Pa7b7c7d7f6c2b3 Ka5 black Bb8 Kh3 Qg8 Pf7h4 Sa1 Rd8
h=4 circé martien(8+7)
to capture, a unit first passes through its native square

Correction 20 ans après, en hommage à Alexandre Dumas !
Solution

 

 

7 - #2 Anti-Circe

R.TURNBULL
2000

white Ra1h8 Sc1g8 Bb3e8 Kf2 Pf6f7g6d3e3 black Kf8 Pa2 Bh1e1 Rd1g1 Sf1b1
#2 AntiCirce(12+8)
Solution

 

8 - h#3,5 mars Circe

D.INNOCENTI
2016

white Qa7 Pf5 Bf2 black Kc4
h#3,5 mars Circe(3+1)
Solution

 

9 - #2 with Roses

J.QUAH
2016

white ROf6h2 Pc4f2e4c2 Re8f4 Bb5h8 Kb1 black Qf3 Pc5g6h6g4 Sb7 Bg5e2 Kf7
#2(11+9)
󼎜f6, h2: Rose
: rounded Nightrider

Solution

 

10 - s#4 Maximum

B.LINDGREN
1970

white Bg4e1 Ke8 Qf1 Pd7f7h7h4g3b6d4 Sg5a6 Rf8f3 black Pg2 Kd6
s#4 Maximum(15+2)
: black is required to play the geometrically longest moves

Solution

 

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