WSC 2007 - 2nd day
Ch. Jones
2007
white Pe5 Ka8 Bg7 Rf5
black Bg8 Kd4 Qf1 Pc6e7c4 Se6f2 Rh6d3
h#3(4+10)
b)Cf2-->e4
The second
although original, seems to be authorized. It comes from one of the world's leading specialists.
V. Kopaiev & C. Markov
1994
white Pe2g4 Kd1 Bc8
black Be1 Kd5 Qe6 Pb2c3e7c7b7g6g5f2 Sd4e5
h#4(4+15)
3sol.
> #3 - 80mn
W. Jorgensen
1950
white Bh3g1 Kc5 Qd1 Pe6c4d4g4g3f2 Sb5e2 Rf8
black Ph2 Sg2 Bh1e1 Kf1
#4(13+5)
Charpentier :
Oh yes, they treated them. Really hard to digest, this AUW... The blockade from hell!
H. Boettger
1994
white Pb3d2g5 Kf7 Rd8 Sc4 Bf3
black Pd3b4b6b7 Kc5 Ba5a6 Rb5
#6(7+8)
Charpentier :
In fact, the #6 is a version (probably shortened for the championship) of a #8
(Be4 instead of f3). The authors are Horst Boettger and Uwe Auerswald.
Selfmates - 50mn
I. Mikan
1935
white Bc6a1 Ka5 Qd5 Pb7f3e3 Sb1e8 Rb8f2
black Pc7e4 Kb3 Ba6 Rc4
s#5(11+5)
This problem is listed in the FIDE album 14-44. It has been recognised by several participants.
Try to solve it in half an hour
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