py_20240305

{

} 1.e2-e1=BL f6*g7 2.BLe1*b4 g7*f8=WL 3.BLb4-c4 WLf8-b4 {pat

} 1.e2-e1=BP f6*g7 2.BPe1-e2 g7*f8=WP 3.BPe2-g2 WPf8-f2 {pat

} 1.e2-e1=BV f6*g7 2.BVe1*b4 g7*f8=WV 3.BVb4-a5 WVf8-b4 {pat

} 1.e2-e1=BM f6*g7 2.BMe1-f3 g7*f8=WM 3.BMf3-g5 WMf8-g6 {pat

Chinese Babson.
The author specifies that the Leo c1 could be replaced by a Vao, but the diagram would then show a promotion Vao..}

{

} 1.SWd6-d7 ! {The d6 Sparrow uses the e7 jump to get to d7.
(} 1...Kd5-c6 {forbidden by Sparrow d3 --} 1...Kd5-d4 {forbidden by Sparrow d3)
} 1...Kd5-e5 {The squares c4 & e4 are forbidden by the Sparrow d7.
} 2.Ke7-f7 Ke5-d5 {The f4 & e4 squares are controlled by the d7 Sparrow; the f5 square by the g4 Sparrow...
} 3.Kf7-g6 {(} 3...Kd5-e6 {forbidden by Sparrow d3)} 3...Kd5-e5 {
} 4.Kg6-g5 Ke5-d5 5.SWg4-e7 + {(d7 jump) is checked by the e4 jump
} 5...Kd5-e5 6.SWd7-d6 # {Nice comeback.
It's mate(not a model because e6 is controlled 2 times):
the King is attacked by the Sparrow d3 (jumping d6), d5 is controlled by the Sparrow e7, d4 as already said by the Sparrow d3, e4 by the Sparrow d6.}

{

tries :
} 1.WRg7-d4 + ? 1...Ra3-g3 ! {
} 1.WRg7-c3 + ? {(via e8-c7-b5)} 1...Qc4-g4 ! {
} 1.WRd6-f5 ? BRb7-f3 ! {because the g7-d4 path is interrupted

} 1.WRd6-c8 ! {(threatens} 2.WRc8-e7 # {(by double check, via d5-e3 or c6-b4-c2-e1)
} 1...Qc4-d5 {(does not counter the threat)} 2.WRc8-e7 # {because no unit can come on b4, c2 or e1,
et} 2...Qd5-c6 {frees up the d5-e3 passage; this says,} 2.WRc8-c2 # {also mate
Black will parry the threat by unmasking Ra7.
} 1...BRb7-f3 {(via a5-b3-d2)} 2.WRg7-d4 # {
} 1...BRb7-e4 {(via d6)} 2.WRg7-c3 # {
} 1...Qc4*e6 {or} 1...Qc4-c2 {or} 1...Qc4-b4 2.WRc8-c2 # {
} 1...Ra3-e3 2.WRc8*e3 # {

This problem is the author's favourite in the "roses" family..}

{

} 1...Bc8-a6 2.g3-g2 Ba6-f1 ! {
} 3.a7-a6 Bf1*a6 {(Bishop observed by bPg2.)
} 4.g5-g4 ! {(Tempo.)} Ba6-f1 {
} 5.g2*f1=B a5-a6 {
} 6.Bf1-g2 a6-a7 {
} 7.Bg2-h1 ! {(So that he can't leave the big diagonal.)} a7-a8=R # ! {
(} 7...a7-a8=Q + ? 8.Bh1*a8 ! {)

Note that } 4.f5-f4 ? {instead of 4.g4, would allow on the same line : } Ba6-f1 5.g2*f1=B a5-a6 6.Bf1-g2 a6-a7 7.Bg2-h1 ! a7-a8=R + 8.f4-f3 !

{

} 1.SWb1-c3 2.SWc3*d5 3.SWd5*b6 4.SWb6-b4[-b5] {
} 5.SWb4*a6 6.SWa6-a4[-a5] 7.SWa4*c5 8.SWc5-e4 {
} 9.SWe4*g5 10.SWg5-g7[-g6] 11.SWg7*h5 12.SWh5-h7[-h6] {
} 13.SWh7-f8 14.SWf8-c5[-d6] {pat.
Bf5 is "pinned".}

{

} 1...SWa1-b3 2.Ke6-e5 SWb3-g8[-f7] 3.Bb1-e4 SWg8*e7 {stalemate!

} 1...Ke3-f4 2.Bb1-a2 SWa1-a3[-a2] 3.Ke6-f6 SWa3-f8[-e7] {stalemate!

Front and rear pinning.}