py_20220621

1 - 2# circe

Macleod, N.
1978

white Pc7c5e3b2 Rc4g7 Bd7d2 Kd6 Sf4 Qa4 black Sa8b3 Kd1 Rg8 Bg1 Pb4

#2 Circé(11+6)

A captured piece is reborn on its native square if it is free

Solution

{

} 1...Kd1*d2[+wBc1] {is illegal.

Every promotion threatens Qxb3# : the pawn having disappeared can no longer be taken by Na8, resurrecting on c2
} 1.c7-c8=Q ? {(threatens} 2.Qa4*b3 # {)
} 1...Bg1*e3[+wPe2] 2.Rg7-g1 # {Rook could not be taken because of the rebirth on a1
} 1...Sb3*c5[+wPc2] 2.Qa4-a1 # {
but} 1...Rg8*c8 ! 2.Qa4*b3[+bSg8] Rc8*c5[+wPc2] ! {
} 1.c7-c8=B ? {(same threat)
} 1...Sb3*c5[+wPc2] 2.Qa4-a1 # {
} 1...Rg8*c8[+wBf1] 2.Bf1-e2 # {
but} 1...Bg1*e3[+wPe2] ! 2.Rg7-g1 + Rg8*c8[+wBf1] ! {
} 1.c7-c8=S ? {(same threat)
} 1...Bg1*e3[+wPe2] 2.Rg7-g1 # {
} 1...Rg8*c8[+wSb1] 2.Rc4-c1 # {
but} 1...Sb3*c5[+wPc2] ! 2.Qa4-a1 + Rg8*c8[+wSb1] ! {
other tries :
} 1.Qa4*b3 + ? Sa8*c7[+wPc2] ! 2.c2-c3 + b4*c3[+wPc2] {
} 1.Rg7*g1[+bBf8] {illegal because self-check
} 1.Bd7-g4 + Bg1*e3[+wPe2] {
} 1.Rc4-c1 + Kd1*d2 {no more rebirth

} 1.c7-c8=R ! {(the threat is the same)
} 1...Rg8*c8[+wRh1] 2.Bd7-g4 # {
} 1...Bg1*e3[+wPe2] 2.Rg7-g1 # {
} 1...Sb3*c5[+wPc2] 2.Qa4-a1 # {
3 different mat on Rxc8}

2 - h=5 circe madrasi

Bienabe, A.
2013

white Pa5d6f6 Ka1 black Pa6a7d7c2d2f2h2 Kb7

h=5 Circe madrasi(4+8)

2 opposing unitss of same kind that observe each other are paralysed

Solution

{

} 1.f2-f1=B f6-f7 2.h2-h1=Q f7-f8=Q {

} 3.Qh1-c6 Qf8*f1[+bBc8] 4.d2-d1=R + Qf1*d1[+bRa8] {

} 5.c2-c1=S Qd1*c1[+bSb8] { model stalemate.
note that } 3.c2-c1=S ? {is not good because } 3...Qf8*f1[+bBc8] { would paralyse the bQ)
AUW.}

3 - h#2,5 take & make

Bienabe, A.
2013

white Ba2 Kc8 Pe3 black Pb3 Kd5 Se5

h#2.5 Take&Make(3+3)
b) Ne5=B

After a capture, the capturing piece pays tribute to the captured piece by making a no-catch move with its march. If this move is impossible or illegal, then the prior prise is not possible

Solution

{

} a) {
} 1...Kc8-c7 2.Kd5-e4 Kc7-d6 3.Se5-f3 Ba2-b1 # {
Note that Kxe3 is illegal, the King must make a white pawn move, so go to e4
In pictures :} 4.Ke4*e3-e4 {

} b) +bBe5 {bBe5
} 1...Kc8-d7 2.Be5-f4 e3-e4 + 3.Kd5-e5 Ba2*b3-b2 # {

Chameleon echo.}

4 - h#2,5 with Set Play with neutral moa mao and locusts

Vysotska, J.
2012

neutral La6b1 MOd6 MAe4 white Pb2a5d4 Kb3 black Qe5 Pf7g4 Kg6 Bg5

h#2,5 (4+5+4)
a6, b1: neutral Locusts
d6: neutral Moa
e4: neutral Mao

normal paly with h#2.5 : W-B-W-B-W#. Set play : B-W-B-W#

Creeping Knight with first a Bishop step

Creepin Knight with first a Rook step

Kind of Grasshopper thatt swallow the sautoir

Solution

{

Set play :
} 1... ... 2.Qe5-f4 nMOd6*e4 + 3.Kg6-f5 nMOe4-g3 # {
the neutral Moa cannot go back to e4 and he pins the Black Queen

} 1...Kb3-a4 {(Immobilizing the neutral Locust a6)} 2.Qe5-e7 nMAe4*d6 + 3.Kg6-f6 nMAd6-e8 # {
The neutral Mao cannot go back to d6 and he pins the black Queen.

Mats are not given by double check, but neutral Locust cannot escape.}

5 - aidé 5# sentinels into opposing pawns white ultra maximum

Harris, P.
2012

white Pf7 Qg8 black Re8 Kh7

h#5(2+2)
sentinels into opposing pawns
White Ultra-Maximum
b) +pg7

each playing figure leaves a pawn of the opponent's colour on its starting square
(except 1st or 8th rank)
In Ultra Maximum, even the King's capture must be maximum.
Even in twin (b), ♚ is not in check because ♕xe8 is longer than ♕xh7

Solution

{

} a) {
} 1.Re8*g8 f7*g8=S 2.Kh7-g7[+wPh7] Sg8-f6 {
} 3.Kg7*f6[+wPg7] h7-h8=B 4.Kf6-f7[+wPf6] g7-g8=B + {
} 5.Kf7-f8[+wPf7] Bh8-g7 # {

} b) +bPg7 {+pg7
} 1.Re8-e1 Qg8-a8 2.Kh7-g6[+wPh7] Qa8-h1 {
} 3.Re1*h1 h7-h8=S + 4.Kg6-h6[+wPg6] f7-f8=S {
} 5.Rh1-h5 Sh8-f7 #

6 - 2# lortap

Gockel, H.
2017

white Pg5e5d4 Bh7 Rd7e8 Kf3 black Bh2 Rf4 Ph5f6d5 Sg7g6 Kf5

#2 Lortap(7+8)

you must not be supported by a unit of your side to capture or check.
Thus, ...Kxg5 is illegal and the white king is not in check

Solution

{

Essais :
} 1.Bh7*g6 + ? Kf5-e6 ! {because Re8 is now "supported" by a piece from its side
} 1.e5-e6 ? {(threatens} 2.Bh7*g6 # {because the supported bK cannot take e6 but does not threaten 2 Rxd5# because the Rook d7 is now supported)} 1...Sg7*e6 2.Rd7*d5 # {
but} 1...Sg7*e8 ! {
} 1.Kf3-g4 + ? Kf5-e4 ! {

} 1.Rd7*d5 ! {(threatens} 2.e5-e6 # {)
} 1...Sg7-e6 2.Bh7*g6 # {but not 2 exf6#? illegal.
Djurasevic theme: in the try, key A + threat B + variant C.
In the real play, key C + threat A + variant B.
Donc ABC-CAB.
} 1...Rf4-e4 2.Kf3-g4 # {(and not} 2.Kf3-f4 ? Bh2*f4 ! {)
} 1...Rf4-g4 2.Kf3-e4 # {(and not} 2.Kf3*g4 ? Kf5-e4 ! {)
} 1...Rf4-h4 2.Kf3-f4 # {
}

7 - h#2 2 solutions breton

Maeder, Th
2021

white Sa1 Pd2 Ke8 Rd7h3 Bc6 black Pe2d4 Rc4h1 Kd3 Sg3 Bf3

h#2 breton(6+7)
2 solutions

Breton When a piece is captured, a piece of the same kind from the capturing side must also disappear (if any).
The choice of the piece to be eliminated is made by the capturing side.
For example, 1...♚xd2 would be legal, provided Black chooses to remove the ♟e2.
Which will promote itself, so that the Black King will no longer be able to take ♙d2, as ♙d4 would have to be removed.

Solution

{

} 1.e2-e1=S Bc6-a4 2.Sg3-e2 Ba4-c2 # {
Taking the Bc2 would be a self-check, as the Bf3 would have to be removed

} 1.e2-e1=B Sa1-c2 2.Bf3-e2 Sc2-b4 # {
taking Nb4 would be a self-check, as Ng3 would have to be removed}

8 - h#2 breton adverse b) ♗a2

Maeder, Th
2021

white Ra2g3 Sb6 Bf2 Kf1 black Sa4 Ke4

h#2 Breton adverse(5+2)
b) ♗a2

breton adverse after each capture, a unit of the same nature must disappear (if possible) from the side that suffered the capture.
If there is more than one, the choice lies with the capturing side.

Solution

{

} a) {
} 1.Sa4-c5 Rg3-e3 + 2.Ke4-d4 Ra2-a4 # {3.Nxa4 ? impossible : this would be a self-check as the e3 Rook would disappear.
In pictures :} 3.Sc5*a4[-e3] {

} b) +wBa2 {wBa2
} 1.Sa4-c3 Bf2-e3 2.Ke4-d3 Ba2-b1 # {3.Nxb1 impossible : this would be a self-check as the e3 Bishop would disappear.
In pictures :} 3.Sc3*b1[-e3]

9 - h#3,5 2 solutions isardam transmuted Kings

Crisan, V & Huber E
2015

white Sg6 Ph7 Kh4 black Rg7d4 Sf5g2 Pf6a2f4g3 Be1h5 Ka1

h#2 isardam transmuted K.(3+11)
2 solutions

two opposing units of the same nature may not observe each other :
the White King is not in check, but the capture of Ng6 will check
each King acquires the march of the unit which checks him.

Solution

{

} 1...h7-h8=R 2.Bh5*g6 + Kh4*g2 3.Rd4-e4 Rh8-h1 {
} 4.Sf5-e3 + {(giving the White King the Knight's march again)
} Rh1*e1 # {(is defeated by the Isardam effect, the 2 Rooks cannot be in contact ;
and it is mate because the Black King has become a Rook and the Knight-King protects his Rook)

} 1...h7-h8=B 2.Rg7*g6 + Kh4*f5 3.Be1-f2 Bh8*f6 {
} 4.Sg2-e3 + {(giving the White King the Knight's march again)
} Bf6*d4 # {(The 2 Bishops cannot be in contact with each other, so the Isardam effect is used to prevent check. ;
and it's mate because the Black King has become a Bishop and the Knight-King protects his Bishop).}

Add a comment

Name

E-mail

Website

Anti-spam