py_20220426

1 - h#2,5 3 solutions mars circe

Innocenti, D.
2005

white Rc2 Sf2 black Kd2

h#2.5 mars Circe(2+1)
3 solutions

the movements are normal, but for the capture, it is necessary to virtually pass by its original square

Solution

{

} 1...Sf2-d1 + {(check from b1)} 2.Kd2-e2 Rc2-d2 3.Ke2-e1 Sd1-f2 # {("discovery" by Rd2 via a1! and ...Ke2 is impossible because of the Nf2 via g1)

} 1...Sf2-h3 + 2.Kd2-e2 Sh3-g1 + {(Well, it looks like an almost normal problem)} 3.Ke2-d1 Sg1-e2 # {
(echo-chameleon, d2 is controlled by the Knight via b1 and the 1st row by the Rook via h1)

} 1...Sf2-h1 + 2.Kd2-e1 Rc2-g2 3.Ke1-f1 Sh1-f2 # {Battery mate, e2 is controlled by the Knight and the 1st row by the Rook (via h1) unmasked.

Two Knight returns to f2.}

2 - 2# amu

Lytton, C.
2018

white Kb7 Ba6b4 Pc7e3c2 Re8a4 Sd7f5 Qg4 black Pa7 Kd5 Sg1 Rh1

#2 AMU(11+4)

a move can only checkmate if the checkmating unit was initially observed by one and only one enemy unit.

Solution

{

} 1.Ra4-a1 ! {
} 1...Sg1-e2 {(or elsewhere, h3 or f3)} 2.Ra1-a5 # {
} 1...Rh1-h2 2.c2-c4 # {
} 1...Rh1-h3 2.e3-e4 # {
} 1...Rh1-h4 2.Qg4-g8 # {
} 1...Rh1-h5 2.Sf5-e7 # {
} 1...Rh1-h6 2.Ba6-c4 # {
} 1...Rh1-h7 2.Sd7-f6 # {
} 1...Rh1-h8 2.Re8-e5 #

3 - h#2 5 solutions super-circe with Lion and neutral Empress and Camel

Soulivy, K.
2018

neutral CAe3 EMe1 white LIg3 black Kd3

h#2(1+1+2)
🩃e3: neutral Camel
🨗e1: neutral Empress
🨴g3: Lion

Knight + Rook.
bouncer (1,3). remind : Knight is a bouncer (1,2)
move on the Queen's lines with help of a sautoir and lands on any square after the sautoir
as long as the route is clear.

On the diagram, black King is in double check (🨗e1 & 🨴g3), last move was 🨗f3-e1+.
Solution

{

} 1.Kd3*e3[+nCAe2] nEMe1*e2[+nCAf3] + 2.nEMe2*g3[+wLIa3] nEMg3*f3[+nCAb3] # {
Mate is not model, the square d3 being (like e3) controlled by both the Lion a3 and the neutral Empress f3.
Neutral Camel cannot run away, because the check is double, given by both the Lion and the neutral Empress. And the King cannot capture the said Empress, as she would have to be posed so that she intercepts the Lion, but she would still give check, as a Rook.
} 1.Kd3-c4 nEMe1*e3[+nCAc3] + 2.nEMe3*g3[+wLIc8] nEMg3*c3[+nCAc7] # {
} 1.nEMe1-f3 {(humorous return, as the last move before the diagram was EMnf3-e1+)} LIg3*e3[+nCAh3] 2.nEMf3*h3[+nCAg3] LIe3*h3[+nEMc3] # {
} 1.Kd3-e4 LIg3-d3 2.nEMe1*d3[+wLIe8] nEMd3*e3[+nCAe7] # {
} 1.Kd3-d4 nEMe1*e3[+nCAd3] 2.nEMe3*g3[+wLId8] nEMg3*d3[+nCAd7] # {

Quintuple echo}

4 - 2# checkless chess

Gockel, H.
2017

white Be8e5 Sa6f2 Ra5 Qf3 Ph2d5 Kg1 black Rd8a2 Qb7 Pc5b3b2h3g5 Kc4 Sa4 Bb1

#2 (9+11)

Only valuable checks are checkmates

Solution

{

Essai :
} 1.Kg1-f1 ? {(threatens } 2.Qf3-d3 # {)
} 1...Ra2-a1 2.Qf3-e4 # {(because 2...Bxe4+ is illegal)
} 1...Qb7*a6 2.Qf3*b3 # {(because 2...Kxb3+ is illegal)
But} 1...Rd8*d5 ! {

} 1.Kg1-h1 ! {(threatens } 2.Qf3-e4 # {)
} 1...Ra2-a1 2.Qf3-d3 # {
} 1...Sa4-c3 2.Ra5*c5 # {
} 1...Qb7*d5 2.Be8-b5 # {
} 1...Rd8*d5 2.Qf3-g4 # {

AB-BA exchange between threat and main mate.}

5 - h#2 anti-circé symétrique

Tritten, P.
2016

white Sa3g7 Bd2 Rc6 Kg8 Ph5 black Pd4g6 Sf8 Kh6 Bg5h3

h#2 symetrical anti-circe(6+6)
b) -Nf8

the capturing piece is reborn on the square symmetrical to the centre of the board

Solution

{

} a) {
} 1.Kh6*h5[bKh5->a4] Bd2*g5[wBg5->b4] 2.Ka4*a3[bKa3->h6] Bb4*f8[wBf8->c1] # {
bK cannot capture g7 as it would be reborn on b2.

} b) -bSf8 {-Nf8
} 1.Kh6*g7[bKg7->b2] Rc6*g6[wRg6->b3] + 2.Kb2*a3[bKa3->h6] Rb3*h3[wRh3->a6] # {
bK cannot capture g7 as it would be reborn on a4.

Return home of Black King}

6 - h#2 2 solutions patrol with neutral pieces

Onkoud, A.
2018

neutral Rb2 Bd1 white Kc1 Pg2f3 Sd5e5 black Pf4f5d6c6c5d4 Ke6

h#2 Patrol(5+7+2)
2 solutions
🨂b2: neutral Rook
🨃d1: neutral Bishop

you can only capture and check if you are supported by a unit of your side.
Can be played by either side

Solution

{

} 1.nBd1-b3 Se5-d7 2.Ke6-e5 Sd5-b6 # {display-departure-rank} {
The neutral Bishop, supported by the neutral Rook, controls the e6-square. And not} 2...Sd5-f6 + ? {display-departure-rank} 3.Ke5*f6 ! {: lack of support.
Without the g2-pawn, black king could go to e4.

} 1.nRb2-e2 Sd5-b6 2.Ke6-d5 Se5-d7 # {display-departure-rank} {
the neutral Rook, supported by the neutral Bishop, controls the e6 square; not} 2...Se5-c4 + ? {display-departure-rank} 3.Kd5*c4 ! {: lack of support

The same two white moves are played, but inverted, in both solutions.}

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