py_20220208

1 - aidé 2# 2 solutions provocation chess

Prentos, K.
2008

white Qa4 Pb3 Sc5 Kh4 black Pd5f5c3d3 Ke5 Rf3 Bc1

h#2 infra-fonctionnary(4+7)
2 solutions

you can only capture if you are observed by an enemy unit.

Solution

{

} 1.Rf3-e3 Qa4-f4 + 2.Ke5-d4 Sc5-e6 # {
It's really checkmate because} 3.Re3*e6 ? {or} 3.Re3-f3 ? {would activate Qf4.

} 1.Bc1-e3 Sc5*d3 2.Ke5-f4 Qa4-d4 # {
Here too it is really checkmate because} 3.Be3*d4 ? {or} 3.Be3-d2 ? {would activate Nd3}

2 - aidé 2# 2 solutions provocation chess

Kirchner, I.
2008

white Kb7 Pc7 black Ka5 Sa4 Pe2

h#2 infra-fonctionnary(2+3)
2 solutions

Solution

{

} 1.e2-e1=S c7-c8=Q 2.Se1-d3 Qc8-c5 # {

} 1.e2-e1=B c7-c8=R 2.Be1-b4 Rc8-c5 # {

AUW.}

3 - h#2 2 solutions isardam

Rittirsch, M.
1999

white Pc7e7c2 Kd8 Rf8 Sf1c6 Ba5 black Rb8b1 Qh6 Sg4d1 Pg5h4e2g2b5 Bb2h1 Ke3

h#2 Isardam(8+13)
2 solutions

two opposing units of the same nature may not observe each other.

Solution

{

} 1.Sd1-f2 {display-departure-file} c7*b8=B {(so Bb2 cannot cover on e5)
} 2.e2*f1=R {(so Nf2 cannot cover on e4)} e7-e8=Q # {
(but not} 2...e7-e8=R + ? 3.Rb1-e1 ! {or} 3.Qh6-e6 ! {

} 1.Sd1-c3 {(interception of Bb2)} c7-c8=Q {(so Qh6 cannot cover on e6)
} 2.e2-e1=B {(so Nc3 cannot cover on e4)} e7-e8=R # {
(but not} 2...e7-e8=Q + ? 3.g2-g1=Q ! {).

Promotion cycle BRQ-QBR.}

4 - serial h#6 2 solutions avec Moose

Feather, Ch
2008

neutral NMe5 white Kf2 black Mf4h4 Kh1 Ph2

ser-h#6(1+4+1)
🨫e5: neutral moose
🨥f4, h4: Moose
2 solutions

Moose The moose, playing as a grasshopper along the path of a queen, makes an angle of 45 degrees from the sautoir, in relation to the arrival square of a Grasshopper.
For example 🨥h4h4 can go to f1 or e2 via the f2 sautoir (e1-f2-f1 = e1-f2-e2 = 45 degrees).
🨫e5 can move on f3 or g4 via sautoir f4 (these last moves as a knight, but it would go to g2 or h3 if the f4-square was on g3).
Note that 🨥f4 is pinned by 🨫e5 (sautoir h2) ;
besides, without it, Black would be checkmated because 🨫e5 would have no possible escape.

Solution

{

} 1.nMe5-f3 {(neutral Moose plays black move.)} 2.Mh4-e3 {(sautoir f4 ;
could not have been played on the 1st move as the wR was checked by the nM e5)} 3.Me3-f5 4.Mf4-g2 5.nMf3-g1 6.nMg1-h3 + nMh3-e5 # {

} 1.nMe5-g4 2.Mf4-g1 {(sautoir f2)} 3.Mg1-f5 {(sautoir g4)} 4.nMg4-f6 5.nMf6-h3 6.Mh4-g2 + nMh3-e5 # {

Same checkmate in the 2 solutions, but with a reversal of the two black Mooses.
Neutral Moose e5, playing as black, can go to g4 or g6 (sautoir f5),
but the black king remains in check (sautoir g2). but Black's King remains in check (jump g2).}

5 - 3# mars circe

Geister, A & Papack D
2021

white Ke4 Pg5g7d3 Rg3 Qg2 Bg1e6 Sa5 black Kf3 Pg4h3 Bh2d1 Sh1f2 Qb3

#3 circé martien(9+8)

the piece that wants to capture is first transferred to the square it occupied at the beginning of the game
( according to the rules of normal Circe), which must imperatively be free.

Solution

{

Essai :
} 1.Qg2-f1 + ? {(checked by P g5 et g7)} 1...Kf3-g2 ! {

} 1.Be6-c4 ! {(threatens } 2.Qg2-f1 + Kf3-g2 3.Qf1-e2 # {checkmate by Bc4
But not} 3.Qf1-e1 + ? Kg2-f1 ! {)
} 1...Bh2*g7 {(via f8)} 2.Qg2-h2 + Qb3*g5 {(via d8)} 3.Bg1*g5 # {("discovering" Na5)
(and not} 2.Bg1-h2 + ? {check by Ca5 because } Qb3*a5 ! {(via d8))
} 1...Qb3*g5 2.Bg1*g5 + Bh2-g1 3.Qg2-h2 # {(Bg1, "pinned" by Na5, cannot capture g7)
But not} 3.Qg2-f1+ ? Kf3-g2 ! {

Exchanged lines AB-BA.
Bishop coming on c4 to not be captured : on e6 (f5), there is ...Bd1-c8xe6 (f5), on d5 (g8) ...Qb3-d8xd5 (g8), on f7 ...Ke8xf7.
The mate-threat being carried out by a "g" pawn, the thematic variants consist in taking one of these pawns (g7 or g5),
to take the other one at the 2nd move.}

6 - 2# boléro

Gockel, H.
2021

white Ke8 Rf8d4 Bg8h6 Sh4c1 Pe3e6 black Bh8 Ph7h5d5d6 Se4 Ke5 Rc5

#2 boléro(9+8)

capturing moves are played normaly.
A non-capturing figure adopts the march of the one initially on the same file. It plays like a ♖ if it is on the "a" or "h" file, like a ♘ if it is on "b" or "g", etc.
For example, the ♖f8 cannot go to f6, but neither can ♚e5 because said rook would "normally" take it.
Similarly (after 1.♙e7!) ♗g8 cannot go to e6 (♗h6 could!), but neither can ♚e5.

Solution

{

Essai :
} 1.Sc1-a3 ? {(move like a Bishop and threatens} 2.Sa3-d3 # {as a Rook)} 1...Se4-d3 ! {
} 1.Sh4-h3 ? {(move like a Rook and threatens} 2.Sh3-f3 # {as a Rook)} 1...Se4-f3 ! {
} 1.Bh6-g6 ? {(move like a Rook and threatens} 2.Bg6-f4 # {as a Knight)} 1...Se4-f4 ! {
} 1.Rf8-g7 ? {(move like a Bishop and threatens} 2.Rg7-f5 # {as a Knight)} 1...Se4-f5! {
} 1.Sc1-b2 ? {(move like a Bishop and threatens} 2.Sb2-d3 # {as a Knight)} 1...Rc5-a3 ! {

} 1.e6-e7 ! {(pawns, which are not figures, play normally)
} 1...Se4-d3 ! 2.Sc1*d3 # {
} 1...Se4-f3 ! 2.Sh4*f3 # {
} 1...Se4-f4 ! 2.Bh6*f4 # {
} 1...Se4-f5 ! 2.Rf8*f5 # {
1...R plays } 1...Rc5-a3 {,} 1...Rc5-b4 {,} 1...Rc5-b6 {or} 1...Rc5-a7 {)} 2.Rd4*d5 # {
Bh8, playing as a Rook if it can't capture, has no move.

Dombrovskis theme: the threats of the tries come true in the real game.}

7 - aidé 2# 3 solutions anti-circe

Heinonen, U.
2017

white Se6 Bf4c4 Kd1 black Qe8 Bf8a2 Pe7g6g4e3d3b7 Re5 Kf5 Sg5

h#2 anti-circé(4+12)
3 solutions

the capturing piece returns to its original square if it is free, otherwise the capture is illegal

Solution

{

} 1.Sg5-e4 Bf4-g5 2.Ba2*c4[bBc4->c8] {(you must avoid the parade ...Bb1)} Se6-d4 # {
no occupation of b1 possible

} 1.Re5*e6[bRe6->a8] Bc4-e6 + 2.Kf5-f6 Bf4-e5 # {
no occupation of c1 possible

} 1.Qe8-a8 {(you must avoid the parade 2.Rxb5(Ra8))} Se6-d8 2.Kf5*f4[bKf4->e8] Bc4-b5 # {
3.Kxd8 impossible because of a rebirth on e8

cyclic Zilahi :
we take the white square Bishop, Knight checkmate,
we take the Knight, the Bishop of black squares checkmate,
we take black square Bishop, white square Bishop checkmate.

Checkmate on 3 different squares.}

8 - serial helpmate 10# with moas

Foster, G.
2018

white Kf3 Pd3 black MOa5b5c7f7f5h5g3d1b3b4 Kd5

ser-h#10(2+11)
🨽a5, b5, c7, f7, f5, h5, g3, d1, b3, b4: Moa

black plays n moves in a row after which white checkmates in 1 move
Creeping knight who first makes a bishop step and then a rook step

Solution

{

} 1.MOd1-e3 2.MOf5-d4 {(would have checked on the first move)
} 3.MOg3-e4 {(played earlier, would have barraged the Mof5)} 4.MOh5-f4 {(played earlier, would have barraged the Mog3)
} 5.MOf7-e5 {(don't check thanks to Mof4)} 6.MOc7-e6 {(played earlier, would have barraged the Mof7)
} 7.MOb5-d6 {(played earlier, would have barraged the Moc7)} 8.MOb4-c6 {(played earlier, would have barraged the Mob5)
} 9.MOb3-c5 {(played earlier, would have barraged the Mob4)} 10.MOa5-c4 {(played earlier, would have barraged the Mob3)
} 10...d3*e4 # ! {

The 8 squares adjacent to the black king have been occupied, following a strict move order.}

9 - aidé 3# madrasi b) ♚e8-->e6

Shankar Ram, N.
2002

white Bh2h7 Rg4 Kc1 black Ba7e4 Ke8 Qd7 Rg8

h#3 madrasi(4+5)
b) ♚e8-->e6

two opposing pieces of the same kind that observe each other are paralysed.
By default Kings are not concerned

Solution

{

} a) {
} 1.Qd7-f5 Bh7-g6 + 2.Qf5-d7 Bh2-c7 3.Rg8-f8 Rg4*e4 # {

} b) bKe8-->e6 {Re8-->e6} 1.Qd7-g7 Rg4-g6 + 2.Qg7-d7 Bh2-d6 3.Be4-f5 Bh7*g8 # {

Double aller-retour.}

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