py_20210119

Click in the right part of the chessboard to move forward, left to move backward...
or directly on the move in the solution

1 - 3# circe

Delbarre, JC.
1984

white Ph3e4d7 Bg7 Rh1 Kh7 black Ph2d2f3f4h4h5d4 Kg5 Bg1 Sa2b7
#3 Circé(6+11)
A captured piece reborn on its original square if it is free, otherwise it disappears.

Solution

 

2 - S#19 Circe with Rook-locustes

Smits, G.
2015

white Pa3 Ka6 Bf1 WRd6g8 black Kc7 BRc5
s#19 Circé(5+2)
🨋d6, g8, 🨑c5: Rook-Locuste
plays on the lines of the Rook by eating the hurdle.
Black is currently pat, the ...Kxd6 being impossible, the RL being reborn in d8.
Solution

 

3 - h#3 face-to-face b) back-to-back

Frankiss, Ch
2020

white Kc8 Bf5 black Pb7c4b3 Kd5
h#3 face-à-face(2+4)
b) dos-à-dos
face-to-face if two pieces of opposite colour are "face to face",
for example a white in e4 and a black in e5, they exchange their moving way.
back-to-back if two pieces of opposite colour are "back-to-back",
for example a white in e5 and a black in e4, they exchange their moving way.

Solution

 

 

4 - s#2 Fuddled Men PRA

Turnbull, R & Bissicks P
2014

white Qa2 Pf2f7 Ke3 black Pf3e4f6c6 Kc1 Sh4
s#2 ivrognes rap(4+6)
created by John Beasley, a unit has to rest after every move,
time to digest his alcohol a little.
In "partial retro-analysis" (PRA) we consider all the "components" (said Luigi Ceriani) of a multiple position.
and as a result, there may be several WITHOUT DUAL solutions, depending on the history of the position.

Solution

 

5 - h#2 5 solutions super-circe with leo and locuste

Soulivy, K.
2013

neutral LEa8 Lh7 black Kc4 white Sf5
h#2 5sol. super-circe(1+1+2)
🩀a8: neutral Leo
🨖h7: neutral Locuste
The Leo is a Chinese Queen (which requires a hurdle to capture)
The Locust plays like a Grasshopper but ingests the hurdle, necessarily of opposite colour.
the capturing side places the captured unit wherever it wishes within the limits of legality.

Solution

 

6 - #3 with Equistopper

Rehm, HP & Widlert K
2013

white Bc7 Kh1 Ph3h5g5 Sf5g7 Rd8 QFf2 black Pf3c6b5c4 Ke4 Rh6a5 Sb3 Ba3
#3 (9+9)
🩈f2: Equistopper
It controls the middle of any segment of which it is one end and the other is occupied by any unit.

Solution

 

7 - h#2 anti-circe b) antipode anti-circe c) mars anti-circé d) column anti-circé

Tritten, P.
2016

white Pb7 Kd4 black Be4 Kf4 Qf8 Pc3e2f3g3h5h6f7e7 Sg8d7 Rg4e3
h#2(2+15)
a) anti-circe
b) antipode anti-circe
c) maes anti-circe
d) column anti-circe
the capturing piece reborn on its original square if it is free, otherwise the capture is illegal.
the taking unit reborn on the square located at 4 diagonal steps, i.e. at the distance 4 x root of 2
(if the capture takes place in a2, it is reborn in e6).
it is when the unit does not capture that it is first reborn before playing, the capture being orthodox.
For example, the b7-pawn can play in b3 or b4, but not take in c3.
the capturing unit reborn on the column where it is located, e.g. Kxc3 is reborn in c1.

Solution

 

8 - s#37 zigzag chess

Mueller, F & Geissler N
2011

white Kh8 black Pa7f6 Kf7
s#37 zigzag(1+3)
zigzag In Zigzag Chess, Black only plays when he can give check.

Solution

 

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