py_20200526

1 - hs#3 3 solutions francfort Chess

Smotrov, S.
2019

white Qd8 Pg2 Kb6 black Pf7 Sc5 Ke5

hs#3 3sol.(3+3)
Francfort chess

a capturing unit adopts the moving way of the captured unit

Solution

{

} 1.g2-g4 Sc5-a6 2.Kb6*a6=rS Ke5-e6 3.Qd8-d6 + Ke6*d6=rQ # {

} 1.g2-g3 Sc5-b7 2.Kb6*b7=rS f7-f6 3.Qd8-d5 + Ke5*d5=rQ # {

} 1.Kb6*c5=rS f7-f5 2.rSc5-a4 Ke5-e4 3.Qd8-d4 + Ke4*d4=rQ # {

Triple echo of manoeuvres. Horizontal-diagonal echo.}

2 - 2# circe

Petkov, P & Gandev K
1976

white Qe7 Re3e5 Bf4e8 Sd2d6 Kd8 black Pe4g6e6b7c5c3 Sf6 Bh4 Kd4 Rb5

#2 Circe(8+10)

a captured piece is reborn on its original square if it is free

Solution

{

} 1.Qe7-d7 ! {(threatening} 2.Sd6-f5 # {but not Nxb5 illegal because bR is reborn in a8. In visual form :} 2.Sd6*b5[+bRa8] {)
Creates a white battery, but also a black battery.
} 1...Sf6*d7[+wQd1] + 2.Sd2*e4[+bPe7] # {display-departure-rank} {
} 1...Sf6*e8[+wBf1] + 2.Re3*e4[+bPe7] # {display-departure-rank} {
} 1...Sf6-g4 + {(or g8, h7, h5)} 2.Sd6*e4[+bPe7] # {display-departure-rank} {
} 1...Sf6-d5 + 2.Re5*e4[+bPe7] # {display-departure-rank} {
} 1...c3*d2[+wSg1] 2.Sg1-e2 # {

Quadruple capture on the same square.}

3 - serial h#3 10 solutions with Grasshopper

Gandev, K.
1978

white Be1c8 Ga4 Kh7 Qa6 Pd4g5c7b6d2c2 Se3f7 Re2 black Pf2 Kc6

ser-h#3 10sol.(!)(14+2)
🨟a4: Grasshopper

Black plays n series moves after which he is checkmated in 1 move
. piece moving on the Queen's lines with the help of a sautoir
. the square just behind the sautoir must be free or occupied by an opponent's unit

Solution

{

} 1.f2*e1=Q 2.Qe1*d2 3.Qd2*c2 + Re2*c2 # {
} 1.f2*e1=R 2.Re1-b1 3.Rb1*b6 Qa6-c4 # {
} 1.f2*e1=B 2.Be1-g3 3.Bg3-d6 Sf7-d8 # {
} 1.f2*e1=S 2.Se1-d3 3.Sd3-c5 d4-d5 # {
} 1.f2*e1=BG 2.Ge1-c3 3.Gc3*c7 b6-b7 # {

} 1.f2-f1=Q 2.Qf1-f6 3.Qf6-d8 c7*d8=S # {
} 1.f2-f1=R 2.Rf1-f6 3.Rf6-d6 Sf7-e5 # {
} 1.f2-f1=B 2.Bf1-h3 3.Bh3-d7 Bc8-b7 # {
} 1.f2-f1=S 2.Sf1*e3 3.Se3-d5 Re2-e6 # {
} 1.f2-f1=BG 2.Gf1-f8 3.Gf8-b8 c7*b8=S # {

Task of the 10 promotions.}

4 - h#9 3 solutions köko, maximum Whites

Kotesovec, V.
2008

white Ke1 Rd2 black Sf4 Kg7

h#9 3sol.(2+2)
Köko, maximum White

at the arrival of a move, it is necessary to be in contact with another piece
. whites are required to play the geometrically longest moves

Solution

{

} 1.Sf4-d3 + Ke1-e2 2.Sd3-f2 Ke2-f3 3.Sf2-e4 Rd2-d5 4.Se4-d6 Rd5-e5 5.Sd6-f7 Re5-e2 {(6.Re8? legal, but White chooses the other one)} 6.Kg7-g6 Re2-e8 7.Sf7-g5 Kf3-g4 8.Sg5-f7 Re8-e6 + 9.Kg6-h5 Re6-h6 # {

} 1.Sf4-e2 Ke1-f2 2.Se2-c3 Rd2-d4 3.Sc3-d5 Rd4-e4 {(Ke3 is longer but illegal, even in köko !)} 4.Sd5-f6 Re4-e7 + 5.Kg7-g6 Re7-e1 6.Kg6-g5 Re1-e7 7.Sf6-g4 {(no check)} Kf2-g3 8.Sg4-f6 Re7-e5 + 9.Kg5-h4 Re5-h5 # {

} 1.Sf4-g6 Rd2-f2 2.Kg7-h6 Rf2-f7 3.Kh6-h5 Rf7-f1 4.Sg6-h4 Ke1-f2 {(no longer köko move)} 5.Kh5-g4 Kf2-g1 {(idem)} 6.Kg4-g3 Rf1-f4 7.Kg3-h2 Kg1-h1 {(the same length as Rg4, knowing that Rf1 is illegal)} 8.Sh4-f5 Kh1-g2 9.Kh2-h3 Rf4-h4 # { Mate by double check.

Triple echo stepped.}

5 - 4# with roses

Loustau, JM.
2015

white Bh5b8 Kh1 Pc7 Sc4c6 Rd3 WRh7 black Be1 Kc8 Qf2a2 Pd6b7b6g3 Sh2g1 Rg4 BRb1g2

#4(8+13)
󼎜h7, 󼎝b1, g2: Roses

Extended knight in a rounded manner

Solution

{

Tries :
} 1.Sc4*b6 + ? Qf2*b6 {
} 1.Sc4*d6 + ? BRb1*d6 ! {(via d2-e4 or a3-b5)
} 1.Sc6-a7 + ? Qa2*a7 ! {
} 1.Sc6-e7 + ? BRg2*e7 ! {(via h4-g6 or e3-d5)
} 1.Bh5*g4 + ? Sh2*g4 ! {

} 1.Bh5-f7 ! {(threatening} 2.Bf7-e6 # {)

} 1...Rg4-e4 {(interrupts one of the routes of the Rose b1 to d6)
} 2.Rd3-a3 {(interrupts his 2nd itinerary and therefore threatens} 3.Sc4*d6 # {, outre} 3.Sc6-a7 # {.)} 2...BRb1*a3 3.Sc6-a7 + 3...BRa3*a7 4.Sc4*d6 # {
} 2...Qa2*a3 3.Sc4*d6 + 3...Qa3*d6 4.Sc6-a7 # {

} 1...Rg4-g6 {(interrupts one of the routes of the Rose g2 to e7)} 2.Rd3-e3 {(interrupts his 2nd itinerary and therefore threatens} 3.Sc6-e7 # {, in addition to } 3.Sc4*b6 # {)} 2...Qf2*e3 3.Sc6-e7 + 3...Qe3*e7 4.Sc4*b6 # {
} 2...BRg2*e3 3.Sc4*b6 + 3...BRe3*b6 4.Sc6-e7 # {

Two kinds of "Novotny" or "Plachutta" Queen-Rose.
Experts call this the Brunner-Novotny.}

6 - h#2 2 solutions lortap locusts

Pachl, F & Müller D
2019

white Se7 Ph2a2 Kf3 Le2f4 black Pc6c5c3c2e3f5h4h3 Be8 Rb8 Kc4

h#2 2sol.(9+6)
lortap
🨊e2, f4: Locusts

one must not be supported by a unit of one's own side to capture or check.

Solution

{

} 1.Be8-d7 {"patrolling" the Pf5, which prevents it from giving check in g4.
} Kf3-g4 + {unpatrolling Locust e2, so that it gives check.
} 2.Rb8-b5 Kg4-h5 # {The Locuste f4 is unpatrolled. But the King could not capture h3 nor h4, being supported by the Locust e2
. (which could "capture" in g4 a black unit).

} 1.c2-c1=B {("patrolling" the Pe3, which prevents it from giving check in f2)
} Kf3-f2 + {(unpatrolling Locust f4, so that it gives check)
} 2.Rb8-b4 Kf2-g1 # {: Locuste e2 is unpatrolled}

7 - s#6 royal dynasty

Marlo, T.
2018

white Qc1 Pf5 Kg2h2 Rd8h1 Ba5 black Pe6 Ke2

s#6(7+2)
royal dynasty

a side can possess multiple "Kings", who do not have royal prerogatives,
can be left in check and captured, unless... there is only one of them left !

Solution

{

} 1.Ba5-c7 ! {

} 1...e6-e5 2.Kh2-g1 zugzwang. 2...e5-e4 3.Bc7-h2 zugzwang. 3...e4-e3 4.Qc1-c2 + 4...Ke2-e1 5.Rd8-e8 zugzwang. 5...e3-e2 6.Kg2-f1 + 6...e2*f1=K # {

} 1...e6*f5 2.Rh1-f1 zugzwang. 2...f5-f4 3.Kg2-h1 zugzwang. 3...f4-f3 4.Qc1-d2 + 4...Ke2*f1 5.Rd8-f8 zugzwang. 5...f3-f2 6.Kh2-g1 6...f2*g1=K # {

Chameleon Echo.}

8 - 1# mars circe

Caillaud, M.
1985

white Pb7 Ke8 black Pb2 Ke1 Ba8

#1(2+3)
mars circe

the pieces move normally but capture from their original square

Solution

{

} 1...b2-b1=Q # ! {
The White King was able to reach e8, following a sequence like ...Ne8-f6+ (at the "discovery" by the bK via e8) Kd8-e8 but this was much earlier, otherwise there would be a Knight on the chessboard.
. Or ...Be8-c6 + Kd8-e8 but ...Bc6-a8 is prevented by Pb7. Black to move, the last
move was b6-b7, following ...Ba8. There was previously axb3 or cxb3.

} 1...b7-b8=Q # ? {illegal, as it is Black to move :
because if it was White's, the last black move could only have been ...b3-b2, following b6-b7 ;
. but this position is illegal, the white b6 pawn cannot have a black b3 pawn in the back,
. as one of the captures ...axb6, ...cxb6, axb3 & cxb3 was necessary}

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