py_20191126

1 - hs#4 2 solutions Chinese pieces

Predrag, N.
2013

white WVh1e5 LEg1 WNf4 Kc8 Pg4c7 WPe1 black BVe8f6d8 Kh2 BPb8h8 BNg8 Pg3e7g7b3

hs#4 2sol.(8+11)
🨵e1, 🨻h8, b8: Paos
🨴g1: Leos
🨶e5, h1, 🨼d8, f6, e8: Vaos
🨢f4, 🨨g8: Naos

move normally, but capture with a sautoir
. A particular case is the Nao which is a Chinese Nightrider represented below by Knights with the head down
. The Nightrider is an extended Knight, that is to say that he can make several successive jumps
Solution

{

} 1.WVh1-a8 BVe8-a4 2.WPe1-e4 {(controling g2 & h1)} BPb8-b5 {(VAa4/Pab5 anti-battery control d7)} 3.WNf4-b6 + Kh2-h3 {
} 4.WVa8-d5 + {(NAb6/VAd5 anti-battery)} BVd8*b6 # {(by discovery of the Pao h8)

} 1.LEg1-d4 BPb8-b4 2.WPe1-e3 {(controling f2 & g1)} BVe8-b5 {(PAb4/VAb5 anti-battery control b7 & b8)} 3.WVh1-c6 Kh2-g2 {
} 4.WNf4-d5 + {(anti-battery VAc6/NAd5)} BNg8*c6 # {

"Anti-Grimshaw" black in b5 and white in d5.

It is curious that this problem was awarded first prize even though the judges were very critical :
. passive VAf6 in a solution, imperfect correspondence between the 4th white moves (the Vao playing twice and the Leo once), etc.
. But the following problems also had their share, without achieving the same effects that make it a "task".}

2 - h#3 with locustes and rose

Mlynka, K.
2015

white Kf5 ROa3 WLg3 black Pf2 Kh5 LBd4 BLg7

h#3(3+4)
󼎜a3: Rose
🨊g3, 🨐g7: Locusts
🨒d4: Bishop-Locust
b) 󼎜a3-->a5
c) 󼎜a3-->a7

moves on the Queen's lines with the help of a sautoir which she swallows and which must therefore be an opposing unit
. Same thing but on the lines of Bishop
Extended knight in curved shape

Solution

{

} a) {
} 1.f2-f1=RO + ROa3-e3 2.ROf1-d6 + BLg3*d6-c7 3.LBd4*e3-f2 {(Tempo.)} BLc7*g7-h7 # {

} b) wROa3-->a5 {Rose a3-->a5
} 1.f2-f1=WL + ROa5-f3 2.WLf1*f3-f4 + BLg3*f4-e5 3.Kh5-h6 BLe5*g7-h8 # {

} c) wROa3-->a7 {Rose a3 -->a7
} 1.f2-f1=S ROa7*d4 2.WLg7*d4-c3 BLg3*c3-b3 3.Sf1-g3 + BLb3*g3-h3 # {

How can this kindly work be placed in front of Vaclav's masterpiece? See course of 14 November 2017.}

3 - 2# marine pieces

Boyer, JP.
1978

white Bh4 Kf6 WTa4 Pd2f2h3e6 Se7f3 Re3 black NDc4c6 Kf4 Ba2 BTd1g6 SIg2

#2 marine piece(10+7)

move normally, but capture like locusts

Solution

{

} 1.Sf3-d4 ! {(threatening} 2.Sd4-e2 # {. example } 1...Ba2-b3 2.Sd4-e2 # {)
The Nereid c4 can be unpinned by playing on e4, but also on g4.
} 1...SIg2-e4 2.Se7-d5 # {
} 1...NDc6-e4 2.Re3-f3 # {
} 1...SIg2-g4 2.Bh4-g5 # {
} 1...BTg6-g4 2.Bh4-g3 # {
} 1...NDc4*e6-f7 + {(check by Triton g6)} 2.Sd4-e6 # {
} 1...SIg2-f1 2.Se7*g6 # {

It can be noted that the best way to neutralize two marine pieces is to slip between them !}

4 - 2# annan

Gockel, H.
2010

white Bd7f7 Kb4 Qg4 Pc3d3c6 Sb5g5 Rf5d8 black Ba7f8 Kd6 Qh8 Pa3c4e5h4 Sb6b3 Ra1

#2 annan(11+11)

a unit acquires the moving way of the friendly unit located "under" it (to the south).
For example Nb5, marching momentarily like a King, does not check the black King d6.
And Ng5-e4 is illegal, this one moving like a Queen.
Let us add that squares c7 and e7 are unavailable to the Black King, Td8 having the march of a Bishop.

Solution

{

Essai :
} 1.Qg4*c4 ? {(threatening} 2.Sg5-e4 # {)} 1...Ra1-e1 ! 2.Kb4*a3 Kd6-c5 ! {
} 1...Sb3-c5 2.Kb4-a5 # {(the Knight b5 becomes himself again and the square c5 is blocked) and not } 2.Sb5*c5 + ? {(catch the Qc4 moving way)} Sb6*c4 ! {
} 1...Sb3-d2 2.Qc4-c5 # {(} 2.Kb4-a5 + ? {doesn't fit because the wQ moves like a pawn and therefore } Kd6-c5 ! {parry the check)
} 1...Sb6-d5 2.Qc4*d5 # {(no} 2.Sg5-e4 + ? {does not succeed because the Nd5 moves like a King and therefore } Sd5*e4 ! {parry the threat)
} 1...Qh8-h5 2.Rf5-f6 # {(...Kd5 does not work, Qc4 being a pawn).

} 1.Qg4-d4 ! {(threatening} 2.Sg5-e4 # {)
} 1...Sb3-c5 2.Qd4*c5 # {(} 2.Kb4-a5? {does not work because the c4 pawn, now Knight, controls this square).
} 1...Sb3-d2 2.Kb4-a5 # { : The Queen walks like a pawn, but that's enough.
} 1...Sb6-d5 2.Kb4-a4 # {(of course 2 Qxd5 no longer works).
} 1...Qh8-h5 2.Qd4*e5 # {(no} 2.Rf5-f6 + ? Kd6-d5 ! {because the Bf7 has become a Rook and the Queen d4 a pawn).
} 1...Ra1-e1 2.Kb4*a3 # {(because c5 is checked)
} 1...Sb6*d7 2.Rd8*d7 # {and Kxc6 impossible, Nb5 moving as a King
(no} 2.Sg5-e4 + ? { because } Kd6*f5 {: the bK has become Knight).

. Four changed mats, two of which were exchanged.}

5 - h#2 6 solutions(!) Grasshoppers giraffe

Gandev, K. & Rehm HP.
1991

white Pe7 Sc6 Kf8 black Ba3 Gh8d3c3 Ke6 Pd7c7 Sb5e4 Rd5g4 GIf6

h#2 6sol.(3+12)
🨓f6: Giraffe
🨥h8, d3, c3: Grasshoppers

bondisseur (1,4)

Solution

{

} 1.Gd3-d6 + e7-e8=B 2.Rd5-f5 Be8-f7 # {
} 1.Se4-d6 {display-departure-file} e7-e8=S 2.Rg4-d4 {display-departure-file} Se8-g7 # {
} 1.Sb5-d6 {display-departure-file} e7-e8=WI 2.Gd3-f5 WIe8-a7 # {
} 1.Rd5-d6 e7-e8=WG 2.Gh8-e5 Sc6-e7 # {
} 1.Ke6-d6 e7-e8=Q 2.d7*c6 Qe8-e7 # {
} 1.d7-d6 e7-e8=R + 2.Ke6-d7 Sc6-b8 # {

Sextuple promotion and use of square d6.}

6 - 2# exclusive chess

Trommler, S.
2013

white Kd4 Ph4e2d2c4g3 Rg5 Ba1d5 Sc8 black Pg4d6g6g7 Kf6 Bh3h6

#2 exclusive chess(10+6)

No dual in the checkmate is allowed.

Solution

{

Essais :
} 1.e2-e4 ? zugzwang. 1...Bh3-f1 2.Kd4-e3 # 1...Bh6*g5 ? 2.Kd4-d3 # but 1...Bh3-g2 ! {
} 1.d2-d3 ? zugzwang. 1...Bh3-g2 2.Kd4-e3 # 1...Bh6*g5 ? 2.Kd4-e4 # but 1...Bh3-f1 ! {

} 1.e2-e3 ! {(blocus)} 1...Bh3-f1 2.Kd4-e4 # 1...Bh6*g5 2.Kd4-e4 # 1...Bh3-g2 2.Kd4-d3 #

7 - h#2 lortap with locustes

Petkov, P.
2019

white Kf3 Rh4e8 WLa1h2c8 Bc3 black Pe3d3f7 Kh8 BLf8

h#2 lortap(2+3)
b) 🨐f8-->d4
c) 🨐f8-->h6

In Lortap (Anti-patrol), a unit can only capture if it is NOT observed by her own's side unit.
The Black King is thus not in check, the Bc3 being observed by the Loc c8 (if it was Black, Loc c8XBc3-c2 would be possible) and the Rh4 by the Loc h2.

Solution

{

} a) 1.BLf8*e8-d8 Bc3-f6 2.BLd8*f6-g5 Rh4-h7 # {
Square g8 is forbidden by Loc c8, g7 by Loc a1. And the R in h7 is no more observed by the Loc h2 since h8 is occupied.

} b) bLf8-->d4 1.BLd4*c3-b2 Rh4-b4 2.BLb2*b4-b5 Re8-g8 # {

} c) bLf8-->h6 1.BLh6*h4-h3 Re8-e6 2.BLh3*e6-d7 Bc3-g7 #

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