py_20190528
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1 - hs#3 breton anti-andernach with rose
Petkov, P.2018
white Pd6b6b5f5g6 Sd7 Rb4 Ke7 Bc2
black Qg8 Pa7b7a5d5e5f3f2 Ka8 ROe8h4
hs#3 breton(9+11)anti-Andernache8, h4: Roseb) ♙d6 --> a6
{}
a) {}
1.Bc2-a4[+bBa4] f2-f1=R[+wRf1] 2.Rf1-e1[+bRe1] {(unpins Rb4 on the line h4-g2-e1-c2-b4-c6-e7)} a7*b6[-a5] 3.Rb4*a4 + ROe8*a4[-e1] #
{(via f6-e4-c3) unmasks battery.}
b) wPd6-->a6 {d6 --> a6}
1.Rb4-e4[+bRe4] f2-f1=B[+wBf1] 2.Bf1-g2[+bBg2] {(unpins Bc2 on the line h4-g2-e1-c2-b4-c6-e7)}
b7*a6[-d5] 3.Bc2*e4 + ROe8*e4[-g2] # {(Unmasks the battery) Specific Breton batteries.}
2 - h#2 3 sol take & make, zebu, night zebra
Barth, M & Pachl F2014
neutral CHh6 ZEh3 Se2 Rb4 ZRd5
black Qh5 Pa7a5 Ka6
white Ke6
h#2 3sol(1+4+5)
🨙h3: neutral Zebu🨂b4: neutral Rook🨄e2: neutral Knight
🩃h6: neutral Leaper 2,4🨮d5: neutral Zebrarider
{}
1.Qh5*h3-g7 + {the Queen who captured a Zebu made a Zebu (in this case Giraffe) move}
ZRd5*g7-g2 + {(makes a Queen's move)} 2.CHh6-d4 Se2*d4-b8 # {by double check.}
1.Qh5*h6-f2 {(the Queen who captured a 2-4 Leaper has made a 2-4 Leaper move)}
ZRd5*f2-g2 + 2.Se2-d4 + ZEh3*d4-b3 # {: the Zebu has played like a Giraffe, captured a Knight of which he has taken a step, made
finally check since it is a Camel!!!; checkmate also by double check}
1.Qh5*e2-g3 {(the Queen who captured a knight has made a knight move)}
ZRd5*g3-g2 + 2.ZEh3-d4 CHh6*d4-e8 # {(a Giraffe step); mate also by double check).
Cyclic captures of 3 neutral pieces in d4. Zilahi also cyclic. The "Noctamzebra" comes to checkmate on g2 in all three solutions, accompanied
three solutions, accompanied successively by a nNb8, a nZub3 & a nBone8.}
3 - 2# avec locustes et rose-locuste
Cheylan, Y.2015
white Bf1 Kf6 Lc1e8g8h8 Pg4 Se6 LSh1
black Ph5d4b3 Kd3 Bd1e2
#2(9+6)🨊c1, e8, g8, h8: Locusth1: Rose Locust
{Tries :}
1.Se6-c5 + ? Kd3-c4 ! {}
1.Se6-f4 + ? Kd3-e3 ! {}
1.Kf6-f7 ? b3-b2 ! 2.Se6-c5 + Kd3-c4 ! { the g8 locust was intercepted on the diagonal}
1.Kf6-e7 ? {(and there, the defence} 1...Bd1-c2 {doesn't work because of} 2.Lh8*d4-c3 #
{car} Kd3-e4 {is impossible because of} 3.LSh1*e4-f6 {through f2, as well as} 2...Kd3*c3 {because of} 3.LSh1*c3-b1
{passing by g3 and e4.) but } 1...Be2*f1 ! 2.Se6-f4 + Kd3-e3 ! {Locust e8 is intercepted on the column e ;}
1.Kf6-g5 ? {ou} 1.Kf6-g6 ? h5*g4 ! {as the Locust g8 is intercepted on the g-file, we do not have checkmate by } 2.Lg8*g4-g3 {}
1.Kf6-f5 ! {}
1...Bd1-c2 2.Lh8*d4-c3 # {(car} Kd3*c3 {est impossible à cause de} 3.LSh1*c3-b1 {passing through g3 and e4 as already seen.
Note that this was not a threat because of 2...Kc2! slipping between the two Locusts.) }
1...b3-b2 2.Se6-c5 # {}
1...Be2*f1 2.Se6-f4 # {}
1...h5*g4 2.Lg8*g4-g3 # {}
1...h5-h4 2.Lh8*h4-h3 # {
Three test rebuttals become three variants. The judges (Dupin & Kerhuel) point out that a Nereid (Sea Bishop)
could have been placed in d1 instead of a second Bishop of white squares. "A matter of taste", they say.
We obviously prefer the author's choice.
This problem is also the 5th of a competition in which... the first four seemed undrinkable to us.
It is therefore the best that our modest constitution can offer.}
4 - h#3 2 solutions back-to-back with Nightrider Mao
Foster, G.2018
white NAh1 Ke3
black Pb3 Kg4
h#3 back-to-back(2+2)🨷h1: Nightrider Mao
{ }
1.Kg4-h3 NAh1-b4 {making the modest b3 pawn a formidable Nightrider Mao... which remains a pawn all the same, able to promote itself !}
2.b3-f1=R ! NAb4-d5+ 3.Kh3-h2 NAd5-h3 # ! {NM, having acquired the King's moving way, attacks the bK which, having become a NM,
cannot go anywhere: to f1, f3 and even less to g4 as h3 is occupied.}
1.Kg4-g5 NAh1-e7 {(g4 square being freed)} 2.b3-b2 NAe7-g6 + {(NM having the moving way of a King, checks)}
3.Kg5-a2 {(bK having the march of a NM)} NAg6-a3 # ! {
the bK is attacked by the NM who has become King; he himself, now NM, is completely immobilized because his rook steps are forbidden}
5 - h#4 circe with neutral pawns b) ♚a8
Feather, Ch2005
neutral Pg4f3
black Ka1
white Kd3
h#4 Circe(1+1+2)🨅g4, f3: neutral Pawnsb) ♚a1-->a8
{
} a) {} 1.nPf3-f2 Kd3-c2 2.nPf2-f1=nB nBf1-h3 3.nPg4*h3[+nBf1] nBf1*h3[+nPh7] 4.nBh3-e6 nPh7-h8=nB # {} b) bKa1-->a8 {Ra1-->a8} 1.nPg4*f3[+nPf2] Kd3-e4 2.nPf2-f1=nR nRf1*f3[+nPf7] 3.Ka8-a7 nPf7-f8=nR 4.nRf8-b8 Ke4*f3[+nRa8] # { Quite convincing orthogonal-diagonal echo !}
} a) {} 1.nPf3-f2 Kd3-c2 2.nPf2-f1=nB nBf1-h3 3.nPg4*h3[+nBf1] nBf1*h3[+nPh7] 4.nBh3-e6 nPh7-h8=nB # {} b) bKa1-->a8 {Ra1-->a8} 1.nPg4*f3[+nPf2] Kd3-e4 2.nPf2-f1=nR nRf1*f3[+nPf7] 3.Ka8-a7 nPf7-f8=nR 4.nRf8-b8 Ke4*f3[+nRa8] # { Quite convincing orthogonal-diagonal echo !}
6 - h#2 isardam with first a) vao then b) pao
Loerinc, J.2005
white WVe3
black BVg3 Kc7 PAc1
h#2 Isardam(1+3)🨻c1: Pao🨶e3, 🨼g3: Vaob) 🨵e3
{}
a) {}
1.Kc7-d6 WVe3-a7 2.PAc1-c7 WVa7-b8 #
{Pao and bK moves (other than ...Ke5, remaining under the attack of the Vao) are prohibited according to the Isardam effect.}
b) -wVAe3 +wPAe3 {Pao e3}
1.Kc7-c6 PAe3-e8 2.BVg3-c7 PAe8-c8 #
{Vao and bK moves (other than ...Kc5, remaining under the attack of the Pao) are prohibited according to the Isardam effect}
7 - serial h#17 2 sol with nightrider-hopper and Grasshopper
Novomesky, D.2009
white Pc6 Kb6
black NHb2 Kb1 Gh1
ser-h#17 2sol.(2+3)🨥h1: Grasshopper🨽b2: Nightrider hopper
{}
1.Kb1-c2 2.Kc2-d3 3.Kd3-e4 4.Gh1-d5 5.Ke4-f4 6.NHb2-h5 {}
7.Kf4-e5 8.Ke5-d6 9.Gd5-d7 10.Kd6-e7 11.Ke7-d8 12.Kd8-c8 {}
13.Kc8-b8 14.Kb8-a8 15.NHh5-b8 16.Gd7-b5 17.Gb5-b7 c6*b7 # {}
1.Gh1-a1 2.Kb1-a2 3.Ga1-a3 4.Ka2-b3 5.Kb3-c4 6.Kc4-d5 {}
7.Kd5-d6 8.NHb2-e8 9.NHe8-c4 10.Kd6-e7 11.Ga3-f8 12.Ke7-d8 {}
13.Kd8-c8 14.Kc8-b8 15.Gf8-a8 16.Ga8-c8 17.NHc4-a8 c6-c7 #
8 - h#3 3 solutions with Paos & Vao
Wong, P.2000
white VAd5 Ke6 PAb1h6
black Bc6 Kh1 Qh8 Pg7b6b5 Sa3 Ra1
h#3 3sol.(4+8)🨵b1, h6: Paos🨶d5: Vao
{}
1.Qh8-f8 VAd5-b3 2.Bc6-g2 VAb3-d1 + 3.Qf8-f1 VAd1-h5 # {by double check, and not} 3...VAd1-f3+ {which also double check, but}
4.Kh1-h2 ! {saves itself honourably}
1.Bc6-e8 PAb1-b3 2.Ra1-g1 PAb3-h3 + 3.Be8-h5 PAh3-f3 # {still double check}
1.Ra1-a2 PAh6-f6 2.Qh8-h2 PAf6-f3 + 3.Ra2-g2 PAf3-f1 # {by double check too, and not}
3...PAf3-h3 {because of } 4.Kh1-g1 {Anti-battery cycle.}
9 - serial h#3 4 solutions anti-circe
Millour, RJ.2005
white Bg8 Kh5 Qf8 Pe7f7 Sd7d4 Re3
black Pc3b2 Kc4 Re8 Bb4
ser-h#3 Anti-circe(8+5)4 solutions
{}
1.b2-b1=Q 2.Qb1-e4 3.Qe4*e7[bQe7->d8] f7*e8=Q[wQe8->d1] # {(it is indeed checkmate, because} 4.Kc4*d4-e8 {is prevented by the e3 Rook,
the capture by Qf8 being illegal)
Rook promotion (} 3...f7*e8=R[wRe8->h1] {) would have allowed} 4.Kc4-d3 ! {,
Bishop promotion (} 3...f7*e8=B[wBe8->f1] {)} 4.Kc4-d5 ! {,
Knight promotion (} 3...f7*e8=S[wSe8->b1] {)} 4.Kc4-b5! {. }
1.b2-b1=R 2.Rb1-d1 3.Rd1-d3 f7*e8=R[wRe8->h1] # {}
1.b2-b1=B 2.Bb1-e4 3.Be4-d5 f7*e8=B[wBe8->f1] # {}
1.b2-b1=S 2.Sb1-a3 3.Sa3-b5 f7*e8=S[wSe8->b1] # {Babson Theme}
10 - h#2 2 solutions take & make
Tritten, P.2010
white Sd7 Rc8 Bb8 Ke8
black Be5d3 Kd5 Qh4 Pb6a6d4 Sb7g6 Rc5f1
h#2 Take&Make(4+11)2 solutions
{}
1.Rc5-c7 Sd7*e5-f4 + 2.Kd5-d6 Rc8*c7-c8 # {}
1.Be5-c7 Sd7*c5-c3 + 2.Kd5-c6 Bb8*c7-b8 # {
Another placement of the Bishop or Rook on the last move would allow a black capture immediately replacing a unit on c7.
Reciprocal batteries and returns.}}
11 - s#2 Fuddled Men
Bissicks, P.2013
white Kf3 Ra1
black Pg6 Kh1 Bf1
s#2 Fuddled Men(2+3)
{Tries :}
1.Ra1-a4 ? Bf1-c4 ! 2.Kf3-e2 g6-g5 + 3.Ra4*c4 {}
1.Ra1-a7 ? Bf1-a6 ! 2.Kf3-e2 g6-g5 + 3.Ra7*a6 {}
1.Ra1-a6 ! {}
1...g6-g5 2.Kf3-f4 Kh1-h2 # {(or K elsewhere, or B plays)}
1...Bf1-e2 + 2.Kf3-g4 g6-g5 # {or Kh1 plays}
1...Bf1-g2 + 2.Kf3-e4 g6-g5 # {or Kh1 plays}
1...Bf1-h3 2.Kf3-g4 g6-g5 # {or Kh1 plays}
1...Bf1*a6 {(or on b5, c4)} 2.Kf3-e2 g6-g5 # {or Kh1 plays}
1...Kh1-g1 2.Kf3-f2 g6-g5 # {or Bf1 plays}
1...Kh1-h2 2.Kf3-g3 g6-g5 # {or Bf1 plays.
The white King moves to 6 separate squares (of the 8 available).}
12 - #2 sat
Gockel, H.2008
white Bb8 Ka8 Qb4 Pa7g4 Sg3g7 Ra4
black Qg2 Pg6h6g5h3 Kh4 Bh1 Sf2
#2 sat(8+8)
{}
1.Sg3-e4 ? {is illegal}
1.Sg7-e6 ! {threatening} 2.Se6-f4 # {giving 2 free squares for bK}
1...Qg2*g3 {(to parry} 2.Se6-f4 + ? {by} Sf2*g4 ! {)} 2.Se6-d4 # {because after} 2...Sf2*g4 {, the black King would have the square h5.}
1...Sf2*g4 {(to parry} 2.Se6-f4 + ? {by} Qg2*g3 ! {)} 2.Se6-c7 # {because after} 2...Qg2*g3 {, the black King would have the square h5.}
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