py_20180109

1 - 2# with rose-lion

Quah, J & Hurme H
2016

white WBa3 Ka1 Pg5f6 Sg7 Rc8 RLc2h2 WRc6 black BBb1 Kf7 Pa2h5 Sh8 RLa5 BRg1

#2(9+7)
🨶a3, 🨼b1: Bishop-Lion
󼎜c6, 󼎝g1: Rose-Lion
🨵c2, h2, 🨻a5: Rook-Lion (TL)

: moves with help of a sautoir
. the squares between the start square and the sautoir must be free, as well as between the sautoir and the landing square
. The Lion Rose c6 controls g6 & e7 with the sautoir c2 (c6-b4-c2-e1-g2-h4-g6-e7)

Solution

{

} 1.WRc6-e7? {via c2 as already mentioned, threats} 2.Rc8-f8# {having provided a sautoir to BLa3
} 1...BRg1-c5? {sautoir g5} 2.WTc2-c7# {this time, ...Kg6 is prevented by the Lion-Rose e7, with the bK itself as a sautoir,
the Lion-Rose making a full round clockwise, or two rounds the other way !
} 1...Sh8-g6? 2.WTh2-h7# {Bishop-Lion b1 interception
} 1...h5-h4! {g6 is no longer controled

} 1.WTc2-c7! {menace} 2.WTh2-h7# {that the Bishop-Lion b1 no longer controls
} 1...BRg1-c5 {controls h7, via e4, sautoir g5} 2.Rc8-f8# {defended by Bishop-Lion a3
} 1...Sh8-g6 2.WRc6-e7# {sautoir g6.

Cycle (key + threat + mats) ABCD-CDBA.}

2 - h#3 with gnu & lion

Rallo, V.
2013

white GNb5 Kc5 black Ke8 LIh2

h#3(2+2)
b) 🨍b5-->e2
🨺h2: Lion (LI)
🨍b5: Gnu (GN)

= Camel (1,3) + Knight (1,2)

Solution

{

} {

} a) {
} 1.Ke8-d8 Kc5-d6 2.LIh2-b8 GNb5-e4 3.LIb8-e8 GNe4-f7 # {controlling both d8 & c8.
To be noted : } 2...Kd6-c6 3.Kd8-c8? GNb5-a7# {but bK put himself in check by playing Kc8 !

} b) wGNb5-->e2 {b5-->e2
} 1.LIh2-c2 GNe2-f4 2.LIc2-c8 Kc5-d6 3.Ke8-d8 GNf4-g7 # {controlling both d8 & e8

Echo, but not really echo-chameleon, as only the Gnu is chameleon !}

3 - h#2 3 sol with dabbabas

Gurov, V & Evseev
2008

white Kf1 Rg3c7 Bh8 DAc4d4d3 black Pf2b5 Bh1 Rb6f8 Kc3

h#3 3sol.(7+6)
🨋c4, d4, d3: Dabbaba (DA)

: bouncers 0-2

Solution

{

} 1.Bh1-f3 Bh8-f6 2.Kc3*d3 Rg3*f3 # {Dc4 controls e4 & c2, Dd4 controls d2.

} 1.Rb6-c6 Rg3-f3 2.Kc3*c4 Rc7*c6 # {Dd3 controls d5 & b3, Dd4 controls b4.

} 1.Rf8-f6 Rc7-c6 2.Kc3*d4 Bh8*f6 # {Dc4 controls e4, Dd3 controls d5.

Cycle AB-BC-CA
greffier's note : with the Dabbaba, we rather expected an AB-BD-DA cycle !}

4 - h#2 2 sol super-circe

Rice, J.
2017

white Kf1 Bc2 black Pd3e5f4 Ke4 Re2

h#2 super-circe 2sol.(2+5)

: the rebirth of a captured piece is left to the discretion of the taker
. if a pawn is replaced on a promotion rank, the nature of the promotion is also left to the discretion of the taker
. Of course, and in all the cases, the position after rebirth of the piece must be legal

Solution

{

} 1.Ke4-f3 Bc2*d3[+bPe3] 2.e5-e4 Bd3*e2[+bRg3] # {

} 1.d3*c2[+wBb1] Kf1*e2[+bRd5] 2.c2*b1=B[+wBa2] Ba2*b1[+bBd4] # {

Six rebirths out of eight movements}

5 - 2# anti-circe

Gockel, H.
2007

white Bc4d2 Kc3 Qb7 Ph2 Sh5b3 Rg3f6 black Pf2g4h6h7e5b6 Sf1 Rd5 Ke4

#2 Anti-Circe(9+9)

: the captured piece is reborn on its native square if it is free, otherwise the move is illegal

Solution

{

It should be noted that if the capture on a rebirth square was allowed, one could play :
} 1.Bc4*f1[+wBf1] ! {and the only legal move would be } 1...b6-b5 {which would be followed by} 2.Sb3-c5 # {
It should also be noted that the "corporal" opposition to the Black King comes up against a capture by the latter and rebirth in e8
Example : } 1.Rg3-e3 + ? {and here, not} 1...Sf1*e3[bSe3->b8] 2.Sh5-g3 # {but rather} 1...Ke4*e3[bKe3->e8] ! {
} 1.Qb7-c6 ? {or} 1.Rf6-f8 ? {both come up against} 1...Sf1-e3 ! {

} 1.Bd2-c1 ? {blocus
} 1...Sf1*h2[bSh2->b8] 2.Sb3-d2 # {
} 1...Sf1*g3[bSg3->b8] 2.Sh5-g3 # {
} 1...Sf1-e3 2.Sb3-d2 # {
} 1...Sf1-d2 2.Bc4*d5[wBd5->f1] # {
} 1...b6-b5 2.Sb3-c5 # {
mais} 1...Rd5-d1 ! {

} 1.h2-h3 ? {blocus
} 1...Sf1-h2 2.Bc4*d5[wBd5->f1] # {
} 1...Sf1*g3[bSg3->b8] 2.Sh5-g3 # {
} 1...Sf1*d2[bSd2->b8] 2.Sb3-d2 # {
} 1...b6-b5 2.Sb3-c5 # {
mais} 1...Sf1-e3 ! {

} 1.Rg3-h3 ! {blocus
} 1...Sf1*h2[bSh2->b8] 2.Sh5-g3 # {
} 1...Sf1-g3 2.Bc4*d5[wBd5->f1] # {
} 1...Sf1-e3 2.Sh5-g3 # {
} 1...Sf1*d2[bSd2->b8] 2.Sb3-d2 # {
} 1...g4-g3 2.Rh3-h4 # {
} 1...b6-b5 2.Sb3-c5 # {

Lacny Theme : ABC-BCA.}

6 - h#2 8 sol with zebras and grasshoppers

Heinonen, U.
2003

white Kd3 Bf6 Ze5 Gg7 black Be3b3 Gh2 Kh8 Pe6h4f2e2c6 Sa4 Zh1h6

h#2 8sol.(4+12)
🨟g7, 🨥h2: Grasshoppers
🨷e5, 🨽h1, h6: Zebras (Z)

: moves along the Queen's lines using a sautoir behind which it lands
. : leaper (2,3)

Solution

{

} 1.BZh1-f4 Kd3*e3 2.BZf4-d7 WGg7-c7 # {
} 1.f2-f1=BG + Kd3*e2 2.BGf1-f7 WGg7-e7 # {
} 1.Bb3-c2 + Kd3-c4 2.Bc2-g6 WGg7-g5 # {
} 1.Bb3-d5 Kd3-c2 2.Bd5-g2 WGg7-g1 # {
} 1.Be3-f4 Kd3-d4 2.Bf4-g3 WGg7-g2 # {
} 1.Be3-b6 Kd3-d2 2.Bb6-c7 WGg7-b7 # {
} 1.Sa4-c5 + Kd3-c3 2.Sc5-b7 WGg7-a7 # {
} 1.BZh6-e8 Kd3-e4 2.BZe8-g5 WGg7-g4 # {

Complete White King Rosace.}

7 - hs#4,5 Anti-Circe

Harris, P.
2008

white Kf4 black Ka7 Re1d1

hs#4,5 Anti-Circe(1+3)

Solution

{

} 1...Ka7-a8 {(preventing the Rooks rebirth, which can no longer capture on white squares)} 2.Kf4-e4 Rd1-d6 3.Ke4-d5 Re1-e8 4.Kd5-c6 Ka8-b8 + {(now, selfmate 1#)} 5.Kc6-b7 + Re8-e1 #

8 - serial h#5 disparate

Thoma, A.
2017

white Qc3 Kh1 black Pd2e2 Kd6

ser-h#5 disparate(2+3)

if one side plays a piece, the opposite side cannot play a piece of the same nature in reply

Solution

{

} 1.e2-e1=S 2.d2-d1=Q 3.Qd1-d4 4.Kd6-e5 5.Qd4-g1+ {White is no longer allowed to play the Queen
} 6.Kh1*g1# {Black is no longer allowed to play the king.}

Add a comment

Name

E-mail

Website

Anti-spam