py_20170627

1 - s#9 AntiCirce

Millour, RJ.
2013

white Bh3a5 Ka6 Qe7 Pg6h4d5 Sh2c4 Ra2a7 black Pg7c5d6 Sd1 Bh8 Ke1 Rb4

s#9 AntiCircé(11+7)

: the capturing piece is reborn on its original square if it is free,
otherwise the capture is illegal. The captured piece disappears

Solution

{tries :
} 1.Qe7-e3 ? Sd1*e3[bSe3->b8] + 2.Ka6-b6 {because bR cannot be reborn in h8.
} 1.Ra2-f2 ? Ke1*f2[bKf2->e8] {because wQ cannot be reborn on d1.

} 1.Bh3-g4! Sd1-e3 2.Ra2-f2 Se3-d1 3.Rf2-f8 ! {3.h5 ? Kxf2 (Ke8) because once again 4 Qxe8 (Qd1) is impossible
} 3... Sd1-e3 4.h4-h5 ! {4.Rxh8 ? (Ra1)+ Kf2} Se3-d1 5.Qe7-h4 ! {Not check, but only leaves } 5...Sd1-f2 {
} 6.Rf8*h8[wRh8->a1]+ Sf2-d1 7.Ra1-a2 {return
} 7... Sd1-f2 8.Qh4-g3! {8 Qe7+? Ne4!} Sf2-d1 {and, now that the Bh8 is gone :} 9.Qg3-e3 Sd1*e3[bSe3->b8]# {

"High precision mechanics" (M. Kerhuel).}

2 - h#4,5 AntiCirce

Sobrecases, G.
2010

white Kg3 Bd1 Sb1 black Pe6g5g4f3e3d3c2b2 Kc4 Re2 Sh2

h#4,5 AntiCirce(3+11)

Solution

{

Apparent Play
} 1... ... 2.c2-c1=B Bd1-a4 3.Re2-d2 Ba4-e8 {or} 3... Ba4-d7 {or} 3... Ba4-c6 {or} 3... Ba4-b5 + 4.Kc4-b3 Kg3*h2[wKh2->e1] {tempo} 5.Kb3-c2 Bb5-a4 # {

Try :
} 1...Sb1-c3 ? 2.c2-c1=B Bd1-a4 3.Re2-d2 Ba4-b5 + 4.Kc4-b3 Kg3*h2[wKh2->e1] 5.Kb3-c2 Bb5-a4 {and} 6.Kc2-b1 { would demolish in AntiCirce Calvet, but by default, we are in Cheylan type where captures on rebirth square are illegal.} Sc3*b1 {is therefore impossible

Real play
} 1...Sb1-d2 + 2.Kc4-c3 Sd2-f1 3.c2-c1=B Bd1-a4 4.Kc3-c2 Sf1-d2 + 5.Sh2-f1 + Sd2*f1[wSf1->b1] # {
Double round trip}

3 - h=2,5 Duplex Masand

Stun, J.
2016

white Ke5 Sh1 black Kc3 Ra2

h=2,5 duplex masand(2+2)
b) Ch1-->e1

: the statement is valid for both sides

. : a unit that checks causes the units it observes to change colour, Kings excepted

Solution

{

} a) {
} 1... Sh1-f2 2.Ra2-b2 Sf2-d1[b2=w] + 3.Kc3-d3 Ke5-d5 {pat
} 1...Ra2-a1 2.Ke5-f4 Ra1-f1[h1=b] + 3.Kf4-e3 Sh1-g3 {pat

} b) wSh1-->e1{Nh1-->e1
} 1...Se1-d3 2.Kc3-c2 Sd3-b4[a2=w] + 3.Kc2-d1 Sb4-d3 {pat
} 1...Kc3-b4 2.Se1-g2 Ra2-e2[g2=b] + 3.Ke5-d4 Sg2-f4 {pat}

4 - h#2,5 Phantom Chess swapping Kings

Foster, G.
2016

neutral Pe7a7 black Ke5 white Kd8

h#2.5 fantômes Rois permutant(1+1+2)
2 sol.

a unit can move from his square or native square

. put in check, Kings swap places

Solution

{

} 1... nPe7-e8=nB 2.Ke5-d4 nPa7-a8=nQ[wKd8->d4][+bKd8] + 3.nQa8-a3 Kd4-c4[bKd8->c4][+wKd8] #{
Even if bB plays h3, it will will continue to give check from f1.

} 1... nPa7-a8=nB 2.Ke5-d6 nPe7-e8=nQ[bKd6->d8][+wKd6] + 3.nQe8-b5 Kd6-c6[bKd8->c6][+wKd8] # {
b5 & d6 are covered by the B and Q respectively

Reciprocal promotions.}

5 - serial #5 Köko

Glass, G.
1999

white Pg7 Ke5 Bf8 black Ka8

ser-#5 Köko(3+1)
b) ♖f8

: at the end of a move, the unit that has played must be in contact with another piece

Solution

{

} a){
} 1.g7-g8=Q 2.Bf8-d6 {(no check !)} 3.Bd6-b8 4.Qg8-c8 5.Bb8-a7 #{

} b) +wRf8 {Rf8
} 1.Rf8-h8 {(critical move)} 2.g7-g8=Q 3.Qg8-b8 4.Rh8-c8 5.Qb8-a7 #

6 - serial s#7 Circe

Laborczi, Z.
2004

white Pb7h7e5 Ke3 black Qb8 Pg4 Ke1

ser-s#7 Circe (4+3)
2 sol.

captured unit is reborn on its native square

Solution

{

} 1.h7-h8=Q 2.Qh8*b8[+bQd8] 3.Qb8-a8 {(pawn e5 prevents 3.Qh2)} 4.b7-b8=S {
} 5.Sb8-c6 6.Sc6-d4 7.Qa8-h1 + Qd8*d4[+wSg1] #{

} 1.h7-h8=R 2.Rh8*b8[+bQd8] 3.Rb8-a8 4.b7-b8=B {
} 5.Bb8-a7 {(le pion e5 empêche 5.Fe5)} 6.Ba7-d4 7.Ra8-a1 + Qd8*d4[+wBc1] # {
AUW}

7 - h#5 with Double Grasshopper

Kotesovec, V.
2015

white DGf5h3a3c1 black Ke6

h=5(4+1)
4 sol.
🨊f5, h3, a3, c1: Double Sauterelle

: moves on the Queen's lines with the help of a sautoir behind which it lands.
. It is necessary that the arrival square is free or occupied by an opposing piece
. : makes 2 grasshopper steps in a row.

Solution

{

} 1.Ke6-f6 DGh3-g6 {(via e6)} 2.Kf6-e7 DGa3-f4 {(via f8)} 3.Ke7-f6 DGc1-e7 {(via g5)} 4.Kf6-g7 DGf5-f7 {(via h7)} 5.Kg7-h8 DGf4-f6 {(via f8)stalemate

} 1.Ke6-e5 DGh3-e4 2.Ke5-f4 DGc1-e5 3.Kf4-g3 DGa3-e6 4.Kg3-g2 DGe4-f3 + 5.Kg2-h1 DGe6-g2 {stalemate

} 1.Ke6-d7 DGf5-e6 2.Kd7-d6 DGa3-e5 3.Kd6-c7 DGc1-c6 4.Kc7-b8 DGh3-f5 5.Kb8-a8 DGf5-b7 {stalemate

} 1.Ke6-d5 DGh3-g4 2.Kd5-c4 DGg4-b3 3.Kc4-c3 DGc1-c2 4.Kc3-b2 DGa3-c3 5.Kb2-a1 DGf5-b4 {stalemate

the four corners.}

8 - #2 Annan

Gockel, H.
2015

white Be2a2 Kh6 Qd3 Pc4b2 Sf4a3 Re6 black Bc1 Kc5 Qb6 Pf5c2b7d4 Sh4f1 Rb4

#2 Annan(9+10)

A unit acquires the march of the friendly unit below it. For example the Na3,
because of Ba2, is momentarily a bishop that nails Rb4. But the Bc1, now a pawn (because of c2)
does not nail Nf4, any more than bQ pinss wR.

Solution

{

essais
} 1.Qd3-f3 ? {threatens} 2.Qf3-d5 # 1...Sh4*f3 2.Sf4-d3 # but 1...Sf1-e3 !{Please note that } 2.Sf4-d3 {is not possible since the Knight now has the Queen's march !
} 1.Qd3-d2 ? {threatens} 2.Qd2*b4 # 1...Sf1*d2 2.Sf4-d3 # 1...d4-d3 2.Qd2-c3 # but 1...Qb6-b5 ! {and there} 2.Sf4-d3 {does not even check since the Knight now has the Queen's march !
} 1.Qd3-h3 ? {menace} 2.Sf4-d3 # but 1...d4-d3 !{
} 1.Qd3-b3 ? {threatens} 2.Sf4-d3 # but 1...d4-d3 !{one might think that} 2.Qb3-c3 {checkmates by taking the Queen's moving way on pc4, but this move is impossible, since on b3, the Q has the march of a pawn !
} 1.Qd3-c3 + ? but 1...d4*c3 !{
} 1.Qd3-g3 ? {threatens} 2.Sf4-d3 # but 1...d4-d3 !{

} 1.Qd3*c2 ! {threatens} 2.Qc2-a4 # {Queen moves as Na3
} 1...Bc1*b2 2.Sf4-d3 #{
} 1...d4-d3 2.Qc2-c3 # {pc4 moves as Qc3
} 1...Qb6-b5 2.c4*b5 #

9 - #2 vertical cylinder with Nightriders

Chicco, A.
1940

white Qd7 Ph5h4g4c5 Kh8 WNg1d8 black Bg6 Kh6 BNc1d1e1 Pg5b7b6a5b4 Sb1 Rf7b3

#2 vertical cylindric (8+13)
🨢g1, d8, c1, d1, e1: Nightriders

the chessboard is a cylinder whose columns a and h are the contact lines
: extended Knight

Solution

{

} 1.Qd7*b7 ? BNd1-f5! {pinning wQ

} 1.Qd7-d6 ! {Pinning Pb6.
} 1... Sb1-d2 {or} 1... Sb1-h2 {or Rb3-b3 -sic- (threat variation)} 2.h4*a5# {
Seven interceptions of the Nightriders by the bR, leading to 7 separate mats.
} 1... Rb3-a3 {(interception of NIe1 via g2 !) or } 1... Ne1*g4 {abandonment of guard)} 2.Qd6*g6# {
} 1... Rb3-c3 {(interception of NId1)} 2.Qd6-b8 # {
} 1... Rb3-d3 {(interception of NIc1)} 2.WNd8*f7# {
} 1... Rb3-e3 {(interception of NId1)} 2.Qd6-f8# {
} 1... Rb3-f3 {(interception of NIe1)} 2.h4*g5# {(supported by NIg1 via a4 or a2)
} 1... Rb3-g3 {(interception of NIc1)} 2.WNg1-a4# {
} 1... Rb3-h3 {ou} 1... Rb3-b2 {(interception of NId1 via b2 !)} 2.Qd6*b6# {
} 1... g5*h4 {(ouverture de ligne)} 2.Ng1-a8# !! {via a4-g5 : seven steps of Knight! and not} 2.Qd6-f4 + ? Ne1-g5 {
} 1... a5-a4 {or} 1... a5*h4 2.Ng1*b7# {via h3-a5
} 1... BNd1-e3 2.Qd6*b6# {or} 2.Qd6-b8# {
} 1... BNd1-f2 2.Qd6-f8# {or} 2.Qd6-b8 #

10 - h#4 Functionnaries

Dietrich, St
2010

white Kc3 Bd4 Sc2 black Sc4d2 Kc1

h#4 Functionnaries(3+3)
b) Kings moved one square right

: a unit can only move, and "a fortiori" capture, if it is threatened (observed) by an opposing unit

Solution

{

} a) {

} 1.Sd2-b1 {no check} Kc3-b3 2.Sc4-d2 {display-departure-file} {no check} Kb3-a2 3.Sb1-a3 Sc2-e3 4.Sa3-c2 {oberve Ne3} Bd4-b2 #{

} b) wKc3-->d3 bKc1-->d1 {the 2 Kings moved one square right}{

} 1.Sd2-f3 Bd4-e5 {tempo} 2.Sc4-e3 Be5-f6 3.Se3-d5 Sc2-e3 + {checks as observed by Nd5 which also observes Bg5} 4.Kd1-e1 Bf6-h4 #

11 - #2 Isardam

Caillaud, M.
1997

white Kg1 Pd3g7h7 Rc2 Ba4 Sb1a1 black Pd2c5 Kc3 Rc4 Se4 Ba2

#2 Isardam(8+6)

: Il est illégal que 2 pièces adverses de même nature s'observent

Solution

{

} 1.h7-h8=B ! {threatens} 2.g7-g8=Q # 2.g7-g8=S # 2.g7-g8=R # 2.g7-g8=B #{

} 1...Ba2*b1 {or} 1...d2-d1=S {these 2 moves free the Ne4 to intercept the check with Nf6, but it remains} 2.g7-g8=S #{

} 1...d2-d1=Q + 2.g7-g8=Q #{

} 1...d2-d1=R + 2.g7-g8=R #{

} 1...d2-d1=B {paralyses Rc2 and thus releases Rc4 making Rc4-d4 possible, but there is } 2.g7-g8=B # {

Babson task.}

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