py_20160517

hs#3 Isardam Super-Circé with Roses and Nightriders

Eric HUBER &
Vlaicu CRISAN
2015

white Kf4 rof3 wng5 black Pf2 Kd3 bng3

hs#3 Isardam Super-Circe(3+3)
2 solutions
󼎜f3: Rose
🨢g5, 🨨g3: Nightriders

: Knight extended by successive leaps in the same direction.
For example, NIg5 can go to e4, c3, a2
. : Like the Nightrider, but rounded.
. For example, the ROf3 can make the path d4-c6-d8

Solution

1.ROf3-e1 + f2*e1=BR[+wROe2] 2.Ng5*e1[+bBRa6] + {
does not check wK thanks to the the Rose e2, due to the isardam
}Kd3-e4 + {
similarly, wK does not check bK because the Rose e2 paralyses it with isardam : e2-f4-e6-c7-a6
} 3.WNe1-c5 !! {
pinning the bK; the Rose a6 must continue to "pin" the wK, but c7 and e6 are unavailable, so Black has only one move : } BNg3*e2[+wROf8] #{
NIc5 is pinned because of the isardam f8-e6-c5-a6, so it does not check the bK; and wK cannot play because of the isardam f8-g6-f4-d3-b4-a6, which is why it was the White Rose on f8, intersection of the two paths of the a6 Rose two paths of the a6 Rose, via c5 and via f4; the double threat ...Kxf4 & ... NIxf4 is unstoppable

} 1.ROf3-g1 + f2*g1=BR[+wROe4] 2.Kf4*g3[+bBNa2] + Kd3*e4 [+wROc6] {
bK is not checked by the NIg5 thanks to the isardam effect of NIa2; it is also pinned
} 3.Kg3-f3 + !! {
wK does not check, as the g1 Rose cannot come to f3 to f3 because of the Rose c6
} BNa2*c6[+wROb3] # {
NIg5 does not check bK because the Rose g1 paralyses it with the isardam (h3-g5-e6-c5-b3). Neither does the RB (g1-f3-d4-b3). It was therefore imperative to revive the White Rose in b3, intersection of the two paths of the g1-Rose, via g5 and via f3. The threat ...Kxf3 is unstoppable. Surprising problem: even if we limit ourselves to the final 1# reverse (in each solution), it is already remarkable. The very last move is indeed the only legal one, as the Rose cannot be placed elsewhere. And it's mate to the White King.}

h#15 Functionaries chess

Stephen EMMERSON
2015

white Pf2b2 Ka1 black Sg3 Kd8
h#15 Functionnaries(3+2)
: a piece can only play, and a fotiori capture, if it is "observed" by at least one opponent piece

Solution

{

} 1.Sg3-e4 f2-f3 2.Se4-g5 f3-f4 {
} 3.Sg5-e6 f4-f5 4.Se6-g7 f5-f6 {
} 5.Sg7-e8 f6-f7 6.Se8-d6 f7-f8=Q {
} 7.Sd6-c4 b2-b3 8.Sc4-a5 b3-b4 {
} 9.Sa5-c6 b4-b5 10.Sc6-a7 b5-b6 {
} 11.Sa7-c8 b6-b7 12.Kd8-c7 b7-b8=R {
} 13.Sc8-e7 Rb8-b6 14.Se7-g6 Qf8-e7 + {
} 15.Kc7-b8 Qe7-b7 # {
Double Excelsior !}

h#2,5 Sentinels Einstein

Vito RALLO
2015

white Ke4 Se5 black Pd7 Ke6
h#2,5 Sentinels Einstein(2+2)
2 solutions
: when a piece (not a pawn) plays, it defecates a pawn on the square where the move started
. : if a piece captures, it moves up a step in the hierarchy, and if it does not capture, it moves down.
with capture : p->N->B->R->Q
. without capture : Q->R->B->N->p

Solution

{

} 1...Ke4-e3[+wPe4] 2.Ke6-d6[+bPe6] Se5-c6=P[+wPe5] + 3.Kd6*e5[+bPd6] c6*d7=S # {
The model mat is in a solution
} 1...Se5*d7=B[+wPe5] + 2.Ke6-e7[+bPe6] Bd7*e6=R[+wPd7] + 3.Ke7-d8[+bPe7] Re6-b6=B[+wPe6] # {
... and also in the other}

serial #29 Relegation Chess

Z.OLIVA
1994

white Ba3 black Ph7 Sg6 Kh8
ser-#29 Relégation(1+3)

In , any figure arriving on the 2nd row becomes a pawn. Do not confuse with the "reversible promotion" rule where this degradation is limited to the promoted pieces (see Bell & MC 2011

Solution

{

} 1.Ba3-b2=P {
Bishop becomes a pawn, and so doesn't Check.
} 2.b2-b4 3.b4-b5 4.b5-b6 5.b6-b7 {
} 6.b7-b8=S 7.Sb8-c6 8.Sc6-d4 9.Sd4-e2=P {
} 10.e2-e4 11.e4-e5 12.e5-e6 13.e6-e7 {
} 14.e7-e8=B 15.Be8*g6 16.Bg6-c2=P 17.c2-c4 {
} 18.c4-c5 19.c5-c6 20.c6-c7 21.c7-c8=S {
} 22.Sc8-d6 23.Sd6-e4 24.Se4-f2=P 25.f2-f4 {
} 26.f4-f5 27.f5-f6 28.f6-f7 29.f7-f8=Q #

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