py_20151103

hs#4 Circe with Locust

Unto HEINONEN
2014

white Pb4 Sa5a3 Ka8 Lb1 black Pc5d4c2e2f4f6 Kd5 Ba6

>hs#4 Circe(5+8)
2 solutions
🨊b1: Locust

: a captured piece is reborn on its native square if it is free, otherwise it disappears
special case of fairy pieces which are, a priori, promotion pieces and are therefore reborn
on the promotion square which is by convention on the capture column
. : piece moving on the Queen's lines but with the necessity to have a sautoir.
The Locust lands just behind the sautoir and the latter disappears (or is reborn according to Circe's modalities as here)

Solution

{

} 1.Sa3-c4 {display-departure-rank} c2-c1=B 2.Lb1*c1-d1[+bBf8] e2-e1=R 3.Ld1*e1-f1[+bRh8] c5*b4[+wPb2] 4.Lf1*f4-f5[+bPf7] + Bf8-c5 # {

} 1.Sa3-b5 e2-e1=S 2.Lb1*e1-f1[+bSb8] c2-c1=Q 3.Lf1*c1-b1[+bQd8] d4-d3 4.Lb1*d3-e4[+bPd7] + Sb8-c6 # {
AUW. No 4...KxLocus e4 as it would rebirth in e8, hence Ld3(xe4)}

h#2 Take&Make with Nightriders, Equistoppers and Vaos

Klaus WENDA
2014

white Kb4 QFb8c8 Na5h5 black VAg4h2 Kc7 Be3f1

h#2 Take&Make(5+5)
2 solutions
🨢a5; h5: Nightriders
🩈b8, c8: Equistoppers
🨼g4, h2: Vaos

: after a capture (Take) the capturing piece must make a move (Make) without a take with the characteristics of the captured piece
. : A knight capable of making several successive jumps in the same direction
. : piece moving thanks to a sautoir and which lands on the square, if it exists, which is in the middle of the path to the sautoir. Example: EQb8-e5 is a possible move thanks to the Vao h2
. : piece moving like a bishop but needing a sautoir to capture the piece located one or more squares behind
. the squares between the start and the sautoir must be free, as well as between the sautoir and the finish square

Solution

{

} 1.VAh2-e5 Na5*e3-f2 2.Kc7*b8-d5 Nh5*f1-e2 # {

} 1.VAg4-e6 Nh5*f1-e2 2.Kc7*c8-d5 Na5*e3-f2 # {

d5, middle of the segment b8-f2 3 NIxf1-e2#! (Kb4, Ec8, NIe2 & f2 / Kd5,Ve5, Vg4). The mate boards differ in the role played by the residual stopper (not to be confused with the hopper). The non-blocking Vao activates Equistopper: e5 is the middle of the segment b8-h2, as e6 is the middle of the segment c8-g4.}

serial h#7 SuperPin with Equihopper

N.GUTTMAN
2013

white Ka6 Ba4 EQe2h2 black Qe7 Pc3 Ka2 Rf8

ser-h#7 SuperPin(10+16)
🩈e2, h2: Equihopper

: pinning takes precedence over checkmate
. : a piece that needs a sautoir to move
. The sautoir is the centre of symmetry for the movement example : EQh2-b2 is possible thanks to the sautoir e2

Solution

{

} 1.Qe7-f7 {Qf6 would check
} 2.Qf7-f1 {super-pin of EQe2
} 3.c3-c2 {made possible by the previous move
} 4.c2-c1[+bBc1] {
} 5.Bc1-a3 {
} 6.Qf1-a1 {
} 7.Rf8-f1 {
} Ba4-c2# {
Equihopper is "superpinned" after 2.Qf1 and therefore does not checkmate on c3-c2 7.Rf1 is to avoid that the bQ comes back to f1 "superpinning" the e2 Equihopper which would prevent mate}

#2 Circe

Stephen Slumstrump NIELSEN
2014

white Bd2d3 Kb6 Qh4 Pc7e4f3e2c2b2b5 Sf7g5 Rf6a3 black Ph2g3e5d4a2a4 Kd1

#2 Circe(15+7)
2 solutions

: a captured piece is reborn on its native square if it is free, otherwise it disappears
. particular case of fairy pieces which are, a priori, promotion pieces and are therefore reborn on the promotion square which is by convention on the capture column

Solution

{

Essais :
} 1.Sg5-h7 ? but 1...a2-a1=R ! {
} 1.Sf7-d8 ? but 1...h2-h1=R ! {
} 1.Sf7-d6 ? but 1...h2-h1=Q ! {
} 1.Sf7-h6 ? but 1...h2-h1=S ! {
} 1.Kb6-c6 ? but 1...a2-a1=S ! {
} 1.Kb6-b7 ? but 1...h2-h1=B ! {
} 1.Kb6-c5 ? but 1...a2-a1=B ! {
} 1.Kb6-a5 ? {ou} 1.Kb6-a7 ? but 1...h2-h1=R ! {
} 1.c7-c8=Q ? but 1...h2-h1=Q ! {or} 1...a2-a1=Q ! {
} 1.Sf7*e5[+bPe7] ? but 1...e7-e6 ! {
} 1.Bd2-a5 ? but 1...Kd1-c1 ! {

La clé :
} 1.Sg5-e6 ! {
} 1...a2-a1=Q 2.Ra3*a1[+bQd8] # {
} 1...a2-a1=S 2.Ra3*a1[+bSb8] # {
} 1...a2-a1=R 2.Ra3*a1[+bRh8] # {
} 1...a2-a1=B 2.Ra3*a1[+bBf8] # {
} 1...h2-h1=Q 2.Qh4*h1[+bQd8] # {
} 1...h2-h1=S 2.Qh4*h1[+bSg8] # {
} 1...h2-h1=R 2.Qh4*h1[+bRa8] # {
} 1...h2-h1=B 2.Qh4*h1[+bBc8] # {
} 1...g3-g2 2.Qh4-e1 #{

10 tries, 7 of which were refuted by a different promotion}

h#2 Growing Men

Ronald TURNBULL
2014

white Pg7 Kb8 black Kf6

h#2 Growing Men(2+1)
3 solutions

Growing Men : a piece must necessarily play a move geometrically greater than or equal in length to its previous move.
This requires a bit of retro-analysis !

Solution

{

} 1.Kf6-f7 Kb8-c8 2.Kf7-e8 g7-g8[+wQg8]# {After f7-e8, bK is "enlarged" and cannot escape

} 1.Kf6-e7 g7-g8[+wSg8]+ 2.Ke7-d8 Kb8-c8# {bK having played e7-d8, he is thus "enlarged" and cannot escape the assiduities of the wK

} 1.Kf6-g6 g7-g8[+wRg8]+ 2.Kg6-h7 Rg8-g7#{The bK having played ...Kg6-h7 can no longer go to g7, nor to h6, nor to h8.}

#2 Growing Men

Ronald TURNBULL
2012

white Qd6 Pa4c2f2f3g3h2 Sh4 Kg1 black Ke2

#2 Growing Men(9+1)

Solution

{

If bK still has an orthogonal march, he must have arrived via a4-a3-a2. After the key :
} 1.a4-a5 ! {
it appears that the pawn did not change its column (axb3xa4) and would therefore have hindered the passage of the bK, which is therefore "enlarged". But then he had to pass by h3-g2-f1. In order for the wK to let him pass, the latter must be enlarged too. But Pf2 & h2 forbid him diagonal steps. He must therefore have castled. He is thus totally immobilized. Note that 2.Qd3+ does not check
} Ke2-f1 2.Qd6-a6#

h=4 Growing Men

Ronald TURNBULL
2013

white Kf1 black Rh7 Ba3 Kb8

h=4 Growing Men(1+3)
2 solutions

Solution

{

} 1.Kb8-b7 Kf1-e1 2.Kb7-a8 Ke1-d2 3.Rh7-b7 Kd2-c3 4.Ba3-e7 Kc3-b4 {

} 1.Kb8-c7 Kf1-f2 2.Kc7-d8 Kf2-e3 3.Rh7-c7 Ke3-d4 4.Ba3-e7 Kd4-c5 {

Very nice! The 2 stalemates are in echo}

serial h=9 Growing Men

Ronald TURNBULL
2013

white Ka7 black Pg2 Kh1

ser-h=9 Growing men(1+2)

Solution

{

} 1.Kh1-g1 2. Kg1-f1 3.Kf1-f2 4.g2-g1[+bQg1] 5.Qg1-g2 6.Qg2-a8 7.Kf2-g2 8.Kg2-h1 9.Qa8-g2 Ka7-b7 {
After 2.Kf2, bK could not access g2.
. On 5.Qh1, the bQ will not be able to return to g2. After 8.Kh1, bK is now "enlarged"}

h#4 Köko

Vito RALLO
2013

white Kc4 Bb5 black Sd4 Be4 Kg4

h#4 Köko(2+3)
b) Kc4-->c3

: when the move ends, a unit must be in contact with another one

Solution

{

} a) {
} 1.Sd4-f5 Kc4-d5 2.Be4-f3 Kd5-e6 3.Sf5-e7 Bb5-d7 4.Kg4-f5 + Ke6-e5 # {

} b) wKc4-->c3 {
} 1.Sd4-c2 Kc3-d2 2.Be4-f5 Bb5-e2 + 3.Kg4-f3 Be2-d1 4.Sc2-e1 Kd2-e3 # {

Symmetrical echo.}

h#3 AntiKöko

Vito RALLO
2013

white Sa4 Bf2 Kd4 black Kf6 Bd7

h#3 AntiKöko(3+2)
2 solutions

: à l'arrivée d'un coup, il est illégal de se mettre au contact d'une autre pièce

Solution

{

} 1.Kf6-f5 Kd4-d3 2.Kf5-e5 Bf2-g3 + 3.Ke5-d5 Sa4-b6 # {

} 1.Bd7-e8 Kd4-c3 2.Kf6-e5 Sa4-c5 3.Be8-g6 Bf2-g3 #

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