py_20151013

1 - #2 Mars Circe

U.AVNER & M.CAILLAUD
2001

white Bb1a1 Kb6 Qb2 Pa7a2h3 Se2c1 Rd8b4 black Qa6 Pb7b5e4e3 Ka3 Ra5

#2 Mars Circe(11+7)

: the pieces move normally, but to capture, they virtually pass through their original square

. small review of the position :
. - the Bb1 obstructs the square of Ne2 - the Nc1 obstructs the square of the Ba1
. - the Qb2 controls d1-a4
. - Rd8 is pinned by Qa6
. - Black has very few moves:
Ra5xh3, Ra5xd8 and Ra4

Solution

{

} 1.a7-a8=Q ? {or} 1.a7-a8=S ? {ou} 1.a7-a8=R ? {or} 1.a7-a8=B ? zugzwang. but 1...Qa6-a7 ! {
} 1.h3-h4 ? zugzwang. but 1...Ra5*h4 ! {
} 1.Qb2-h8 ? {or} 1.Qb2-g7 ? {or} 1.Qb2-e5 ? {or} 1.Qb2-d4 ? {or} 1.Qb2-d2 ? {or} 1.Qb2-c2 ? zugzwang. but 1...Ka3-b2 ! {
} 1.Bb1-d3 + ? but 1...Ka3*d8 ! {
} 1.Bb1-c2 + ? but 1...Ka3-a4 ! {

} 1.Qb2-c3 ! zugzwang. 1...Ka3-b2 2.Sc1-b3 # {
} 1...Ra5*h3 2.Sc1*h3 # {
} 1...Ra5*d8 2.Sc1-d3 # {
} 1...Ra5-a4 2.Sc1-b3 #{

Mutate. Battery change.}

2 - #2 Isardam

Ronald TURNBULL
1997

white Bh8 Ka8 Qg4 Pc4 Sb5e8 Rd8 black Qb1 Pc6f3d3 Ke5 Ba1d1 Ra2
#2 Isardam(7+8)
: it is illegal to put in mutual "observation" 2 opposite pieces of the same nature

Solution

{

} 1.Se8-f6 ! threat: 2.Sf6-d7 # {
} 1...Qb1-b2 2.Rd8-e8 # {
} 1...Ra2-b2 2.Qg4-e4 # {
} 1...Ke5*f6 2.Qg4-g5 #

3 - reflex check 2 moves Calvet AntiCirce

Ladislav PACKA
& Juraj LÖRINC
2014

white Qb7 Ph4f3f5e5d6d7 Kh6 Sb6 black Pa2g2g3f4d4 Kh3
r+2 Calvet AntiCirce(9+6)
: when 1 of the two sides presents a check possibility to the other, the latter is obliged to play it
. : the capturing piece is reborn on its native square if it is free, otherwise the move is illegal
. In Calvet AntiCircé, the capture on the rebirth square is allowed

Solution

{

} 1.Qb7-e4 ?{threatens} 2.Qe4-b1 2...a2*b1=S[bSb1->g8] + {
} 1...a2-a1=Q 2.Qe4*f4[wQf4->d1] 2...Qa1-c1 + {
} 1...a2-a1=S 2.Qe4-c2 2...Sa1*c2[bSc2->g8] + {
} 1...a2-a1=R 2.Qe4-e1 2...Ra1*e1[bRe1->h8] + {
} 1...a2-a1=B 2.Qe4*d4[wQd4->d1] 2...Ba1*e5[bBe5->f8] + {
} {but} 1...d4-d3 ! {prevents the threat

} 1.Sb6-a4 ? {menace} 2.Qb7-b1 2...a2*b1=S[bSb1->g8] + {
} 1...a2-a1=Q 2.Kh6-g5 2...Qa1*a4[bQa4->d8] + {
} 1...a2-a1=S 2.Qb7-b3 2...Sa1*b3[bSb3->g8] + {
} 1...a2-a1=B 2.Qb7-b2 {or} 2.Sa4-b2 {or} 2.Sa4-c3 2...Ba1*c3[bBc3->f8] + {
} {but} 1...a2-a1=R ! {prevents the threat

} 1.Sb6-c8 ? {threatens} 2.Qb7-b1 2...a2*b1=S[bSb1->g8] + {
} 1...a2-a1=S 2.Qb7-b3 2...Sa1*b3[bSb3->g8] + {
} 1...a2-a1=R 2.Sc8-a7 {ou} 2.Qb7-a7 2...Ra1*a7[bRa7->h8] + {
} 1...a2-a1=B 2.Qb7-b2 2...Ba1*b2[bBb2->f8] + {
} {mais} 1...a2-a1=Q ! {prevents the threat

} 1.Sb6-a8 ! {threatens} 2.Qb7-b1 2...a2*b1=S[bSb1->g8] + {
} 1...a2-a1=Q 2.Kh6-g5 2...Qa1*a8[bQa8->d8] + {
} 1...a2-a1=S 2.Qb7-b3 2...Sa1*b3[bSb3->g8] + {
} 1...a2-a1=R 2.Qb7-a7 2...Ra1*a7[bRa7->h8] + {
} 1...a2-a1=B 2.Qb7-b2 2...Ba1*b2[bBb2->f8] +

4 - h#2 with Princess and Empress

Ladislav PACKA
& Juraj LÖRINC
2014

white Pa7 Kd4 Bh6 black BEa5 Pd2f2g2e4e6a6 Kh4 BPh7
h#2(3+9)
3 solutions
🨓a5 : Empress
🨽h7 : Princess
The Queen is a piece that combines the march of the Bishop and the Rook
. : piece which cumulates the march of the Knight and the Bishop
. : piece which cumulates the march of the Knight and the Rook

Solution

{

} 1...a7-a8=Q 2.g2-g1=R Qa8-b8 3.Rg1-g4 Qb8-h2 #{

} 1...a7-a8=WE 2.f2-f1=S WEa8-f8 3.Sf1-g3 WEf8-f4 #{

} 1...a7-a8=WP 2.d2-d1=B WPa8*e4 3.Bd1-h5 WPe4*f2 #

5 - h#2 Couscous AntiCirce Cheylan

Chris FEATHER
2015

white Qd5 Pf7 Kb8 black Pd6e5 Ra1 Bf3d4 Ke7
h#2 Couscous AntiCirce(3+6)
4 solutions
: the capturing piece is reborn on the native square of the captured piece if it is free otherwise the move is illegal
Cheylan : une prise sur la case de renaissance est interdite

Solution

{

} 1.Bf3*d5[bBd5->d1] f7-f8=Q+ 2.Ke7-e6 Qf8-f7 # {
Square d1 is inaccessible to the bK, bB being there already.
} 1.Ra1-d1 f7-f8=R 2.Ke7*f8[bKf8->a1] Qd5-a2 # {
Square d1 is inaccessible to the bK, bR being there already.
} 1.Bd4-b2 f7-f8=B+ 2.Ke7*f8[bKf8->c1] Qd5-d1 # {
Square d1 is inaccessible neither the bK, nor the bB, because of Cheylan type
} 1.Bf3-d1 f7-f8=S 2.Ke7*f8[bKf8->g1] Qd5-g2 #{
Square d1 is inaccessible to the bK, as the bB is already there.
AUW}

6 - hs#3 Symmetry AntiCirce

Mario PARRINELLO
2015

white Pe4d5 Sb3h5 Re8 Ke7 black Qg1 Ph7g6c6b6a7g2f3 Ke5 Rd2
hs#3 Symmetry AntiCirce(6+10)
2 solutions
: the capturing piece is reborn on the square symmetrical to the central point of the board (in the middle of d5-e5-e4-d4) if the square is free, otherwise the move is illegal

Solution

{

} 1.Re8-a8 Rd2-d3 2.Ra8*a7[wRa7->h2] Qg1*h2[bQh2->a7] + 3.Ke7-e6 + Rd3-d4 # {

} 1.Re8-h8 Qg1-e3 2.Rh8*h7[wRh7->a2] Rd2*a2[bRa2->h7] + 3.Ke7-d6 + Qe3-d4 #

7 - h#6 with Contra-Grasshopper

Klaus WENDA
2015

white Pd2 Ka1 cgc5e8 black Ph7 Ka8
h#6(4+2)
🨊c5,e8 :Contra-Grasshopper
: Unlike the Grasshopper, which are at any distance from the sautoir and land just behind it, the Contra-Grasshopper must be right next to the sautoir and can land at any distance
. the path must be clear between the sautoir and the finishing square, which may be empty or occupied by an opponent's piece

Solution

{

} 1.h7-h5 d2-d4 {
} 2.h5-h4 CGc5-g1 {
} 3.h4-h3 d4-d5 {
} 4.h3-h2 d5-d6 {
} 5.h2-h1=S d6-d7 {
} 6.Sh1-f2 d7-d8=S # {
CGg1 controls a7.}

8 - #3 Shrinking Men

Paul BISSICKS
2015

white Kb4 Re2f1 black Qg7 Pb2 Ka2
#3 Shrinking Men(3+3)
b) ♛g7->h8 #4
Shrinking Men : a playing piece is required to make a move with a length less than or equal to the move it made previously
. This sometimes involves a bit of retro-analysis:
In each twin, Re2 is at 4 orthogonal steps (h1-h8-a8-a2-e2), and so Pb2 is pinned and Rf1 at 5 (a1-f1).

Solution

{

} a){ bQ is 4 orthogonal steps at best: via d1-d6-g3.
} 1.Rf1-c1 Qg7-g3 2.Re2*b2+ Ka2*b2 3.Kb4-a3# {

} b) bQg7-->h8 {bQg7-->h8 #4 bQ is 5 orthogonal steps at best: via d1-d7-h3.
} 1.Rf1-c1 ? Qh8-e5 ! 2.Re2*b2+ Qe5*b2 + ! {bQ is paradoxically better in h8, having a strong move of length 4.2
} 1.Re2*b2+ Ka2*b2 2.Kb4-c3+ Kb2-a2 3.Rf1-a1+ Ka2*a1 4.Kc3-b2#

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