py_20110125

h#4 Köko Sentinels with Locust

: arrival square of a move must be contiguous of a unit
: a move (except pawn move) let a pawn on the departure square
: Grasshopper capturing the hurdle and landing just behind
Hurdle must be an opponent's unit and arrival square must be free

white Le4 black Kc6

h#4 Köko Sentinels(1+1)
b) 🨊e4-->d5
c) 🨊e4-->c4
🨊e4 : Locust

Solution

{

} a) {

} 1.Kc6-b6[+bPc6] Le4*c6-b7[+wPe4] 2.Kb6-a6[+bPb6] Lb7*b6-b5[+wPb7] {
} 3.Ka6-a7[+bPa6] b7-b8=Q + 4.a6-a5 Qb8-b7 #{

} b) wLe4-->d5{

} 1.Kc6-c7[+bPc6] Ld5*c6-b7[+wPd5] 2.Kc7*b7[+bPc7] d5-d6 {
} 3.Kb7-a7[+bPb7] d6-d7 4.Ka7-a8[+bPa7] d7-d8=R #{

} c) wLe4-->c4{

} 1.Kc6-d6[+bPc6] Lc4*c6-c7[+wPc4] 2.Kd6-e7[+bPd6] c4-c5 {
} 3.Ke7-e8[+bPe7] Lc7*e7-f7[+wPc7] 4.Ke8-d8 c7-c8=L #

h#3,5 Circe Köko with Equihopper

: a captured unit is reborn on its original square if free
: unit moving symmetrically with respect to another unit which is used as the symmetry point

white Pb5f7 Ka1 WEc4 black Pb3b2c2 Ke8

h#3,5 Circe Köko(4+4)
🩈c4: Equihopper

Solution

{

} 1...f7-f8=B 2.b2-b1=BE Ka1-b2 {
} 3.c2-c1=Q + Kb2*c1[+bQd8] 4.BEb1-d7 Bf8-d6 #{

} 1...f7-f8=WE 2.b2-b1=R Ka1*b1[+bRa8] {
} 3.0-0-0 Kb1*c2[+bPc7] 4.c7-c5 b5*c6 ep.[+bPc7] #

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