py_20221101

1 - h#2 duplex circe

Duplex the statement works regardless of who starts.
In other words: B-W-B-W# or W-B-W-B#
Circe a captured piece is reborn on its original square if it is free, otherwise it disappears.

Grevlund, P.
1973

white Pd7f7h5 Kf6 black Ke1 Pe2g2

h#2 duplex Circe(4+3)

Solution

{

} 1.g2-g1=B d7-d8=R 2.Bg1-f2 Rd8-d1 # {

} 1.d7-d8=S g2-g1=Q 2.Sd8-e6 Qg1-g5 # {

AUW.

Note that} 1.Kf6-g6[-h5] g2-g1=Q + 2.Kg6-h5 Qg1-g5 # {would demolish without Ph5}

2 - PJ 5 symetrical point

symetrical point two units placed symmetrically in relation to the centre of the board (the common point of squares d4, e4, e5 & d5)
exchange their way of moving.

Solution

3 - s#30 Mars Circe

Mars Circe To perform a capture a piece virtually passes through its original square

Smits, G.
2012

white Pb4b6a2f4g2 Ra8 Se4 Kg3 black Rb5 Kh1

s#30 Mars Circe(8+2)

Solution

{

Black's King is stalemated, because ...Kg1 or ...Kh2 would be a self-check by Ra8.
} 1.Se4-c5 Rb5-a5 2.Ra8-a7 + {(via a1)} Kh1-h2 3.Ra7-a6 + {(via h1)} Kh2-h1 {
} 4.a2-a4 ! Ra5-b5 5.Ra6-a8 {(5. Kf3 ? Rxa6!)} Rb5-a5 6.Ra8-a7 + {(as on 2nd move, but with Pa2 on a4)} Kh1-h2 {
} 7.Ra7-a6 + Kh2-h1 8.Kg3-f3 ! Ra5-b5 9.Ra6-a8 {(9. Ke4 ? Rxa6!)} Rb5-a5 {
} 10.Ra8-a7 + Kh1-h2 11.Ra7-a6 + Kh2-h1 12.Kf3-e4 ! Ra5-b5 {
} 13.Ra6-a8 Rb5-a5 14.Ra8-a7 + Kh1-h2 15.Ra7-a6 + Kh2-h1 {(15... Kg3 ? : The square is controlled by Pf4)
} 16.Ke4-d5 ! Ra5-b5 17.Ra6-a8 Rb5-a5 18.Ra8-a7 + Kh1-h2 {
} 19.Ra7-a6 + Kh2-h1 20.Kd5-c6 ! Ra5-b5 21.Ra6-a8 Rb5-a5 {
} 22.Ra8-a7 + Kh1-h2 23.Kc6-b7 {!!} Ra5-a6 {(23... Rb5 idem)} 24.Ra7-a8 + Kh2-h1 {
} 25.Kb7-a7 ! Ra6-a5 26.Ra8-h8 + {(via a1)} Kh1-h2 27.b4-b5 Ra5-a6 + {(via a8)
} 28.Rh8-a8 + {(counter-check via h1)} Kh2-h1 29.Sc5-b7 Ra6-a5 30.Ka7-a6 Ra5*a8 # ! {

Already presented, but without explanation beyond the 4th move, on 26 November 2013.}

4 - 2# equihoppers

equihopper Equihopper plays symmetrically with respect to any unit, provided he does not leave the board. Thus, the Royal equihopper can go to e5 and could go to a5 if this square was not controlled by the a7 equihopper.

Lytton, C.
1969

white EQa7 Kc3 Pc7e6 Qc8 black EQd7 Pa3a6c6h2g4g6 Sa8 black Royal EQa1

#2(5+9)
a7, d7: equihopperss
a1: Royal equihopper

Solution

{

} 1.Qc8-h8 ! {blocus
} 1...h2-h1=Q {(or other promotion)} 2.Qh8*h1 # {
} 1...g4-g3 2.Kc3-d2 # {g3 is blocked for Eqr a1
} 1...g6-g5 2.Kc3-d3 # {g5 is blocked
} 1...a3-a2 2.Kc3-b2 # {
} 1...c6-c5 2.Kc3-c2 # {as e3 is controlled ( } 2.Kc3-b3 ? {self-check)
} 1...a6-a5 2.EQa7-e5 # {
} 1...Sa8-b6 2.Kc3-b3 # {as c5 is controlled
} 1...Sa8*c7 {(or} 1...EQd7-b7 {)} 2.Kc3-b4 # {
} 1...EQd7-b5 {(or}} 1...EQd7-f5 {)} 2.Kc3-c4 # {
Here we see the only weakness of the problem :
it is an unnatural (so-called "English") Eq on a7, intercepted on the lines of a Queen ;
after} 1...EQd7-b5 {(or} 1...EQd7-f5 {), and only in this case, Eqa7 controls e7 and thus forbids Eqr a1 to go there, hence} 2.Kc3-c4 # {

Note : the author was called "Sells" when this issue appeared, he later chose the name "Lytton".}

5 - pat aidé 9= sentinels minimum double

Sentinels each move deflates a pawn on the starting square except for the 1st and 8th rows

minimum double the move played must be the shorter of the piece playing
Traditionally, only Black is involved, but in minimum double, both sides are involved

Cefle, K.
2022

white Pa3c5e3 Ke1 black Pa4a5e4h6 Kc6

h=9 Sentinels(4+5)
minimum double

Solution

{

} 1.Kc6-c7[+bPc6] Ke1-f1 2.Kc7-c8[+bPc7] Kf1-g1 3.Kc8-d8 Kg1-h1 {
} 4.Kd8-e8 Kh1-h2 5.Ke8-f8 Kh2-h3[+wPh2] 6.Kf8-g8 Kh3-h4[+wPh3] {
} 7.Kg8-g7 {!!} Kh4-h5[+wPh4] 8.Kg7-g8[+bPg7] Kh5-g6[+wPh5] 9.Kg8-h8 Kg6-f7[+wPg6] {stalemate ;
Pg7 allows this move.
Another white route would have given rise to inappropriate sentinels, prohibiting the emergence of the sentinel g6}

6 - inv 7# masand

masand when a piece checks, all the units it "observes" change colour (except for Kings)

Bryukhanov, I.
2022

white Bb6a4 Pc5 Sc4d3 Kc1 black Ka1

s#7 masand(6+1)

Solution

{

} 1.c5-c6 Ka1-a2 2.Sd3-b4[c6=b] + Ka2-a1 3.Ba4-d1 c6-c5 {

} 4.Sb4-c2 + Ka1-a2 5.Sc4-d2 c5-c4 6.Bb6-f2 c4-c3 7.Bf2-e1 c3*d2[e1=b] # !

7 - 2# eiffel chess

eiffel chess the units are paralysed according to the P-N-B-R-Q-P cycle.
Thus, the b2-pawn does not check the white king

Gockel, H.
2017

white Kc1 Qd4 Be1c4 Pa2 Ra8 black Pb2d3d7 Rb4a4 Ka3 Ba6 Qf8

#2 eiffel chess(6+8)

Solution

{

Try :
} 1.Qd4*b2 ? {(threatens} 2.Bc4-b3 # {)
} 1...Ba6*c4 2.Be1*b4 # {
} 1...d3-d2 ! {

} 1.Bc4-b3 ! {
(menace} 2.Be1*b4 # {Ra4 being paralysed by Bb3 and bQ by Ra8, but not} 2.Qd4*b4 ? {ni} 2.Qd4*b2 ? {illégaux)
} 1...Ba6-c4 {(parries the threat as wQ no longer controls b4, but deparalyzes it)} 2.Qd4*b2 # {
But not} 2.Ra8*a4 + ? Bc4-b5 ! {or} 2...Bc4*b3 ! {

Djurasevic theme. ABC-BCA.

other variation} 1...Ba6-c8 2.Ra8*a4 # {: justification of Pd7}

8 - 2# breton

breton after each capture, a unit of the same nature must disappear (if possible) from the capturing side.
If there is more than one, the choice lies with the capturing side.

Loustau, JM.
2021

white Ba2c3 Rc4e6g5f3 Pc6d6f6e3 Kf7 Sd2h5 Qh1 black Sb3 Rf4f2 Kd5 Pe7f5e5e4 Bf8

#2 breton(14+9)

Solution

{

} 1.Bc3-b4 ! {(menace} 2.Rc4-c5 # {)
} 1...e7*d6[-e5] 2.Sh5*f4[-g5] # {(no Pe5)
} 1...e7*d6[-f5] 2.Sh5*f4[-e6] # {(} 2...e5*f4[-b3] {is not possible)
} 1...e7*d6[-d6] 2.Sh5*f4[-c4] # {(} 2...e5*f4[-b3] {is not possible)
} 1...e7*d6[-e4] 2.Sh5*f4[-f3] # {(} 2...e5*f4[-b3] {is not possible)
In each variation, capture of Nf4 is not allowed :
Either Pe5 has disappeared, or it is pinned, or Ba2 is awake, or Qh1 !

The position is illegal (3 black captures for 2 missing units).
The author has corrected this, but at the cost of another promoted unit.
The judge prefers this version, where "the promotion pieces are all thematic"..}

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