py_20221004

1 - h#2 5 sol anti-circé with lions

Anti-Circe The capturing piece is reborn on its original square if it is free.
If the resurrection square is occupied, the capture is illegal.
Lion piece moving on the Queen's lines with the help of a saltire.
The squares between the Lion and the saltire and between saltire and the arrival square must be free

Caillaud, M.
2022

white LIb8 Kc7 Sf6h4 Pg7d5 black LIf5 Re5h2 Pg6f3 Kg3 Qf1 Bg1

h#2 Anti-Circé 5sol.(6+8)
b8, f5: Lions

Solution

{

} 1.Rh2-f2 g7-g8=R 2.Re5-e8 Rg8*e8[wRe8->h1] # {
} 1.LIf5-f2 g7-g8=LI + 2.Re5-g5 LIg8-b3 # {
} 1.Bg1-f2 g7-g8=S 2.Re5-e7 + Sg8*e7[wSe7->g1] # {
} 1.Qf1-f2 g7-g8=B 2.Re5-e6 Bg8*e6[wBe6->f1] # {
} 1.f3-f2 g7-g8=Q 2.Re5*d5[bRd5->a8] Qg8-b3 # {

Super AUW.
In each solution, the occupation of the g8-square unpins Re5 as it makes the move Lib8xg3(Lig8) illegal ;
and the essential control of the h3 square is ensured each time.
In the solutions 1...f2 & 1...Lif2, mate occurs by double check.

G. Foster points out that Rh2 could not be replaced by a Nh1,
as after} 1.Rh2-f2=S g7-g8=R 2.Re5-e8 Rg8*e8[wRe8->h1] + { there would be the parade} 3.Sf2*h1[bSh1->g8] {preventing Lixg3 because rebirth on g8 is impossible.}

2 - h=8 circé maléfique

Mirror Circe a captured piece is reborn on the opponent's original square

Bakcsi, G.
2012

white Kh5 Rb7 Bd5 black Ka8 Pa3b2c3d2e3f2g3h2

h=8 Mirror Circe(3+9)

Solution

{

} 1.a3-a2 Bd5*a2 {(No rebirth, a2 being busy.
} 2.b2-b1=S Ba2*b1 {No rebirth, b1 being busy.
} 3.c3-c2 Bb1*c2 {
} 4.d2-d1=Q + Bc2*d1 {No rebirth, d1 being busy.
} 5.e3-e2 Bd1*e2 {
} 6.f2-f1=B Be2*f1 {No rebirth, f1 being busy.
} 7.g3-g2 Bf1*g2 8.h2-h1=R + Bg2*h1 {Stalemate. No rebirth, h1 being busy.

AUW.
The easiest fairy problem in history ?}

3 - 2# strictly growing chess b) Bf8 --> h6 c) Bf8 --> d7

strictly growing chess a piece must make a move of strictly greater length than its previous move
If no move of greater length is possible, then the piece is immobilised

wK has played f1-g2 and is therefore immobile.
bK has played e8-f7 and is therefore immobile.
wQ has played at best d1-e2-e4 and is therefore condemned to play for its next move at least 2 diagonal steps.
In (a) bB is free, in (b) it should make at least 3 diagonal steps, in (c) at least 2 diagonal steps.

Bissicks, P. & Emmerson St.
2018

white Qe4 Kg2 black Bf8 Kf7

#2 strictement agrandissants(2+2)
b) Ff8-->h6
c) Ff8-->d7

Solution

{

} a) {
} 1.Qe4-a8 ? Bf8-a3 ! {(prevents Qa2#)
} 1.Qe4-b7 ? {(doesn't check)} Bf8-b4! {(prevents Qb3#)
} 1.Qe4-c2 ! {
} 1...Bf8-d6 2.Qc2-f2 # {(it is well mate as} Bd6-f4 {is illegal)
} 1...Bf8-e7 2.Qc2-f2 # {(} Be7-f6 {illegal)
} 1...Bf8-c5 2.Qc2-f2 # {(} Bc5*f2 {illegal.)

} b) bBf8-->h6 {Bf8-->h6
} 1.Qe4-c2 ? Bh6-d2 ! {
} 1.Qe4-e7 + ? Bh6-e3 ! {
} 1.Qe4-a8 ! Bh6-e3 2.Qa8-a2 # {(6 is greater than 5,6)

} c) bBf8-->d7 {Bf8-->d7
} 1.Qe4-c2 ? Bd7-f5 ! {or} 1.Qe4-a8 ? Bd7-a4 ! {
} 1.Qe4-e7 ! {1...B move} 2.Qe7-a7 # { : Bishop cannot return on d7}

4 - h#2 4 sol anti-circe

Heinonen, U.
2018

white Pb4d2f4e6b7 Ka1 Rc7e8 black Qa4 Pb5a5a3e2d6d4 Sb1f1 Bc8 Kd5 Rh8

h#2 Anti-Circé 4sol.(8+12)

Solution

{

} 1.Sb1*d2[bSd2->b8] b7*c8=S[wSc8->b1] 2.e2-e1=S {(The pawn must vacate e2 square otherwise Ke5! becomes possible)} Sb1-c3 # {
Note that on } 2.e2-e1=R Sb1-c3 + {only check because of} 3.Re1-b1 ! {

} 1.Sf1*d2[bSd2->b8] b7*c8=B[wBc8->f1] 2.e2-e1=B Bf1-g2 # {

} 1.e2-e1=Q b7*c8=Q[wQc8->d1] 2.Qe1*e6[bQe6->d8] Qd1-b3 # {(and not} 2...Qd1-f3 + ? 3.Qa4-d1 ! {)
A noter que} 2.Qe1*d2[bQd2->d8] ? {would leave e4 square for the King

} 1.e2-e1=R b7*c8=R[wRc8->h1] 2.Re1*e6[bRe6->a8] Rh1-h5 # {

Babson task slightly shifted.}

5 - 2# köko

Köko the arrival square of a move must always be adjacent to an occupied square

Balasubramanian, SK & Seetharaman K
2021

white Bf2 Kg4 Qd1 black Pf3c4e5e6 Ke4 Ba8 Sh4

#2 Köko(3+7)

Solution

{

} 1.Bf2-a7 ? {
} 1...Sh4-f5 2.Kg4*f3 # {
} 1...Ba8-d5 2.Qd1-e2 # {
} 1...Sh4-g2 2.Qd1*f3 # {
but} 1...Ba8-b7 ! {
} 1.Bf2-c5 ? Ba8-c6 ! {
} 1.Qd1-f1 ? {no more Qxf3

} 1.Qd1-b3 ! {
} 1...Sh4-f5 {ou} 1...Sh4-g2 2.Qb3*f3 # {
} 1...Ba8-d5 2.Qb3-e3 # {
} 1...Ke4-d5 2.Qb3-d3 # {
} 1...c4-c3 2.Qb3-c4 # {
Note that} 1...Ba8-b7 {or} 1...Ba8-c6 {are illegal}

6 - 2# rose royale sauterelle royale et lions

Rose Rounded extended Knight
Grasshopper moves along the Queen's lines with the help of a saltire behind which she lands
It is necessary that the arrival square is free or occupied by an opponent piece
Royal piece Piece with its "normal" walking but with prerogatives of King

Smulders, K.
1974

white Royal ROb8 black Royal Gd2 black LIa3h1 Se1 Pd7d6

#2(1+6)
b8: Royal Rose
d2: Royal Grasshopper
a3, h1: Lions

Solution

{

} 1.rROb8-h8 ! {with 3 threats} 2.rROh8-h2 # {,} 2.rROh8-d8 # {and} 2.rROh8-f7 # {
} 1...Se1-f3 2.rROh8*f3 # {(and not} 2.rROh8-f7 + ? LIh1-b7 ! {)
} 1...Se1-c2 2.rROh8-h2 # {
} 1...Se1-d3 2.rROh8-d8 # {
} 1...Se1-g2 2.rROh8-f7 # {
} 1...d6-d5 {with a dual} 2.rROh8-h2 # 2.rROh8-f7 #

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