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1 - hs=6 3 solutions with sparrow and moose
Kotesovec, V.2019
white Kd4 SWe3
black Kf4 Me2e8
hs=6 3sol.(2+3)🨢e3: Sparrow🨺e2, e8: Moose
kind of Grasshopper which instead of arriving just after the sautoir, lands coming back 45° backwards
Kind of Grasshopper also but with an angle of 45° on the front of the sautoir
His movement over a short distance is that of a Knight: the White King is in check by the moose e2.
white Royal Kc8
black Royal Ke3
white Rc4 Bf5
black Bh3h6 Qf1 Pa5g7 Sd5 Ra3c1
h#2 symmetry point(3+9)2 solutions
symmetry pointtwo units placed symmetrically with respect to the centre of the chessboard.
(the common point of squares d4, e4, e5 & d5) exchange their moving way.
Thus, the wRc4 moves like a Bishop, the wBf5 like a Rook.
{}
1.Ra3-d6=K[+wBc4][+wRf5][+brRe3] {(Rook moves like Bh6)} rKc8-f8=rR {(the King moves like the Qf1 and now like the Rc1)}
2.rRe3-e6=rK[+bRd6] {(the King moves like Rd6; he is not in check in e6 for the
reason already reported)} Bc4-e2=R[+wBf5] # ! {(the Rook has moved like Bf5). both
white figures have recovered their moving way to administer a double chess.
The White King, moving like Rc1, controls the "f" column.}
1.Bh6-d6[+wBc4][+wRf5][+brBe3]
{(Bishop moves like Ra3)} rKc8-a6=rB {(the King moves like the Qf1 and now like the Bh3)} 2.rBe3-c5=rK {(the
King moves like Bd6; he is not in check in c5 for the reason already
reported)} Rf5-f2=B[+wRc4] # ! {(the Bishop has moved like the Rc4). The squares b5 & c4 are
controlled by the White King, who walks like the Bh3. Specific batteries
Rook-Bishop & Bishop-Rook. We could present the problem in twins, with
only the a5-pawn, then only the g7-pawn.}
3 - h#2,5 with AP reverse Boléro Kings Included
Petkov, P.2020
white Royal Kd1 Ra7
black Royal Pd6d3 Ke8 Bc3e4
h#2,5 reverse Boléro KI(2+5)apparent play
moves making a capture are played normally.
A non-capturing figure adopts the march of the one originally on the same column.
It therefore plays like a Rook if it is on the "a" column or the "h" column,.
like a Knight if it is on "b" or "g", etc...
In Reverse Bolero, this applies to moves making a capture,.
the moves that do not capture are normal.
Of course, in "Kings included", the Kings also adopt this way of doing things.
{Apparent play}
1.rBe4-h1=rR + {(checks since playing like a Rook for the captures)} rKd1*h1=rR
{(playing as a Queen)} 2.rBc3-h8=rR + rRh1*h8 # !
{real play} 1.rRa7-h7 !
{(1 Rg7? does not work, not only because the Black King could run away at the end on the 7th rank,
the Rook having, to capture, the Knight's march, but above all because this move is a check !)}
1...rBc3-a1=rR + {(checks, the Bishop playing like a Rook for the captures)}
2.rKd1*a1=rR {(moving like a Queen)} rBe4-a8=rR + 3. rRa1*a8 # !
{"Probably the first problem where the White King and the Black Bishops visit the 4 corners",
says the author.}
4 - h#2 2 solutions with hedgehogs
Joudon, L.1988
white Kh1 EHd1a2
black Pe7e5 Ke6 Bc5 Sd5
h#2 2sol.(3+5)🨊d1, a2: Hedgehog
The Hedgehog walks like a Queen,
but must start from or reach a strip.
Without, however, being allowed to travel from one strip to another !
{}
1.BHh7*e4 WHb5-a4 {(to control c2)} 2.BHc8-f5 {display-departure-file} {(intercepting the EHh3,
other moves checking the White King)} WHd4*d8 #
{}
1.BHd8*d4 WHb5-a5 {(to control d2)} 2.BHh3-d7 {display-departure-file} {(intercepting the EHc8)} WHe4*h7 #
{Reciprocal captures and interceptions.}
6 - h#2# 2 solutions anti-circe
Loerinc, J. & Dragoun M2010
white Pe7g6g5 Se1 Bd6h7 Kb2 Rg1f7
black Be3 Kf4 Qa7 Pf2e2g7g4b4 Sh2e5 Re8f6
h#2 Anti-circe 2sol.(9+12)
the capturing piece is reborn on its original square if this one is free, .
otherwise, the move is illegal
Kxg5 is never possible as the e8 square is occupied.
{}
1.Rg8-g5 f7-f8=R + 2.Kf5-g6 Rf8-g8 # {threat Rxg6 (Rh1). Black may not play a piece in h1,
and on ...Kg7 Rxg7 (Ra1). The other king moves are forbidden by the condition isardam.
Note (see comment below) that without ph5, Rh5 would be a defence.}
1.Be7-h4 f7-f8=B 2.Kf5-g5 Bf8-e7 # {(threat Bxg5 (Bc1) and Black cannot occupy c1)}
1.Qd3-a6 + f7*g8=Q[wQg8->d1] {(prevents check because ...Qxa2 (Qd8) is not possible)} 2.Qa6-g6 Qd1-d3 #
{threat Qxf5(Qd1), not 3 Qc2+? Qd6! and rebirth in d1 is forbidden ;
now 3...Qd6 is impossible 3/4 of AUW.}
8 - 2# relegation chess
Paavilainen, J.2017
white Bg7h1 Kb5 Qe1 Pe6d2 Sa4d4 Re4
black Pb6e7f4e2b2a2 Sf6 Bb1c1 Kd3 Ra1
{Try :}
1.Sb2-c4 + ? 1...Sa4-b2 ! {}
1.Bh5-f7 ! {(threatening} 2.Kd5-c6 # {, and not} 2.Kd5-d4 + Kb3-b4 ! {)
A comical element of the position is that the Qd1 is nailed by the Qc2 !!
any movement of Qd1 authorises the capture of the King by Qc2.
And of course the Bishop, since f7 as well as since h5, is forbidden ...Kxc2-e8..
The thematic defences free c7, allowing on Kc6 the renaissance ...dxc6-c7.}
1...Bc7-b8
2.Kd5-c5 # {}
1...Bc7*d6[bBd6->f8]
2.Kd5-d6 # {}
1...Bc7*b6[bBb6->f8]
2.Kd5-d4 # {}
1...Bc7-d8
2.Kd5*e5[wKe5->e1] # {}
1...Qd1*c2[bQc2->d8]
2.e7*d8=Q[wQd8->d1] # {}
1...Sb1-d2
2.Sb2*d1[wSd1->b1] # {(} 2.Kd5-c6 ? Sd2-f1 ! {}
1...Sa4-c5
2.Sb2-a4 # {
Greek Cross of the White King and Cross of Saint Andrew of the Black Bishop.}
Comments
1
Capron
On Tuesday, september 29, 2020
Problème 7, aidé 2# 3 solutions. Nous nous sommes demandés pourquoi le Ph5 puisque dans les 3 tableaux le RN ne pouvait partir de la ligne par laquelle il était échec.
La réponse est que dans la première solution (promotion en T) la position finale ne ferait pas mat ! (même type de défense que celle indiquée dans la variante avec promotion D)
2
Capron
On Tuesday, september 29, 2020
Au sujet du hérisson.
Il est dit : "Le Hérisson ("edgehog") marche comme une Dame, mais doit impérativement partir d'une bande ou y parvenir. Sans toutefois être autorisé à se rendre d'une bande à une autre !" ce à quoi il faudrait ajouter "ou rester sur la même"
Pour info, sur le hérisson, voici ce qu'en dit echekk :
Le Hérisson ou Edgehog est une Dame à champ d’action restreint. Parmi les coups de Dame ordinaire jouables depuis la case qu’il occupe, le Hérisson ne peut jouer que ceux dont la case de départ est sur la périphérie et la case d’arrivée au centre, ou l’inverse.
Qu'on pourrait dire aussi : Chaque pas de hérisson doit quitter ou rejoindre une case du bord mais pas les deux à la fois.
Comments
1 Capron On Tuesday, september 29, 2020
La réponse est que dans la première solution (promotion en T) la position finale ne ferait pas mat ! (même type de défense que celle indiquée dans la variante avec promotion D)
2 Capron On Tuesday, september 29, 2020
Il est dit : "Le Hérisson ("edgehog") marche comme une Dame, mais doit impérativement partir d'une bande ou y parvenir. Sans toutefois être autorisé à se rendre d'une bande à une autre !" ce à quoi il faudrait ajouter "ou rester sur la même"
Pour info, sur le hérisson, voici ce qu'en dit echekk :
Le Hérisson ou Edgehog est une Dame à champ d’action restreint. Parmi les coups de Dame ordinaire jouables depuis la case qu’il occupe, le Hérisson ne peut jouer que ceux dont la case de départ est sur la périphérie et la case d’arrivée au centre, ou l’inverse.
Qu'on pourrait dire aussi : Chaque pas de hérisson doit quitter ou rejoindre une case du bord mais pas les deux à la fois.