py_20200128

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1 - 2# Anda

Anda(invented by the author of this problem), any unit (except King) performing a direct check immediately becomes neutral. If it is already neutral, it becomes white or black, depending on which side plays it.

Petkov, P.
2019

white Pc4g3 Sa3c2 Be1g6 Kb6 Rf5 black Pe2g4 Kd3 Re4

#2 Anda(8+4)

Solution

{

Try :
} 1.Kb6-c5 ? Re4-e6 ! {

} 1.Kb6-c6 ! {
} 1...Re4-e6=n + 2.nRe6-e3=w # {
} 1...Re4*c4=n + 2.nRc4-d4=w # {
} 1...Re4-d4 2.Rf5-d5 # {: the Bishop does not become neutral because his check is indirect
} 1...Re4-e3 2.Rf5-f3 # {
} 1...Re4-f4 2.Rf5*f4 # {
} 1...Re4-e8 2.Rf5-e5 # {
(} 2.Rf5-d5=n + ? nRd5-f5=b ! {
} 2.Rf5-f3=n + nRf3-f5=b {)
} 1...Re4-e5 2.Rf5*e5 #

2 - hs#4,5 reverse anda

reverse anda any unit making a move that is not a direct check becomes immediately neutral.
If it is already neutral, it becomes white or black, depending on which side plays it.

Petkov, P.
2019

neutral Pb6 black Pd2g2 Kh1 white Pb7 Kc8

hs#4.5 reverse Anda(2+1+3)

Solution

{

} 1...Kh1-h2 2.Kc8-b8 d2-d1=nR { : the Rook does not give check and therefore becomes neutral.
} 3.Kb8-a8 nRd1-g1=b {Becomes a Black Rook.} 4.b7-b8=Q + {Remains a White Queen because of check.} 4...Kh2-h1 5.b6-b7=w {Become a white pawn.} Rg1-a1 # {Other Rook moves are illegal, because the Rook that has become neutral would check the Black King. (and there} 6.Qb8-a7=n {? is illegal because becoming a neutral Queen.

Please note that on } 4.b7-b8=R ? Kh2-h1 5.b6-b7=w {is prevented by } Kh1-h2 !

3 - 2# bicolores

bicolores In Bicolore, the Kings are so sensitive that they cannot tolerate being " checked " by the units of their own side.

Schiegl, H.
1970

white Qc5 Kg6 black Pb3b2f4 Ra4 Ba6 Kb1

#2 bicolores(2+6)

Solution

{

Tries :
} 1.Kg6-f6 ? {(threatening} 2.Qc5-c2 # {)} 1...Ra4-c4 2.Qc5-g1 # {but} 1...Ba6-c4 ! {(} 2.Qc5-f5 + {is illegal)
} 1.Kg6-g7 ? {(threatening} 2.Qc5-c2 # {)} 1...Ba6-c4 2.Qc5-f5 # {but} 1...Ra4-c4 ! {(} 2.Qc5-g1 + {is illegal}
} 1.Qc5-c2 + ? {illegal} 1.Qc5-c3 ? {(threatening} 2.Qc3-e1 # {)} {but} 1...Ba6-e2 ! 1.Qc5-f2 ? {(threatening} 2.Qf2-e1 # {)} {but} 1...Ba6-e2 ! 1.Qc5-c1+ ? b2*c1=B ! {or} 1...b2*c1=S ! {

} 1.Kg6-h6 ! {(threatening} 2.Qc5-c2 # {)
} 1...f4-f3 2.Qc5-c2 # {(as well } 2...Kb1*c2 {than} 2...b3*c2 {and} 2...Kb1-a2 {are illegal)
} 1...Ba6-c4 2.Qc5-f5 # {
} 1...Ra4-c4 2.Qc5-g1 #

4 - h#3 2 solutions madrasi

madrasi 2 opposing pieces of same nature that mutualy observe are paralysed.

Shankar Ram, N.
2000

white Ph2g2e2 Rc4 Bd6 Kh3 black Bc8f8 Kf4 Qd5 Ph4h5g5 Sf5e3 Rc1a3

h#3 madrasi(6+11)
2 solutions

Solution

{

} 1.Qd5-e4 g2-g3 2.Se3-c2 Rc4*c8 3.Sf5-e3 {display-departure-file} Rc8*f8 # {

} 1.Qd5-e5 g2-g4 2.Sf5-e7 Bd6*a3 3.Se3-f5 {display-departure-rank} Ba3*c1 #

5 - h#2 2 solutions kobul Kings

kobul Kings when a unit is captured, the King of the camp of the said unit acquires his march.
He becomes a normal King again if you take a pawn.

Bushan, Ph
2019

white Rh6 Kd4 Bg4 black Pa5g5 Kb8 Bc4 Re3

h#2 2sol. kobul(3+5)

Solution

{

} 1.Re3-e6 Kd4*c4[b8=rB] 2.rBb8-e5 Rh6*e6[e5=rR] # {

} 1.Bc4-e6 Kd4*e3[b8=rR] 2.rRb8-g8 Bg4*e6[g8=rB] #

6 - h=2 2 solutions with locusts and roses

locuste Grasshopper that eats its hurdle (which is necessarily an opponent's piece)
rose Extended and rounded knight e.g. ROf8 can go to d7, c5, d3, f2, h3, h7, g6, f4, d3, b4, a6, b8

Smits, G.
2015

white Ka7 ROf8 Lh1 black Qe1 Kd2 ROd1 Lf5

h=2 2sol.(3+4)

Solution

{

} 1.ROd1-e3 ROf8-a6 2.Qe1-d1 Lh1*d1-c1 {=

} 1.Kd2-c2 ROf8-h3 2.Qe1-c3 Lh1*d1-c1 {=

It should be noted that apparently there are other solutions such as :} 1.ROd1-c3 ROf8-b4 2.Qe1-f1 Lh1*f1-e1 {but it's not pat ...
because of the "null" move 3.ROc3-c3 via b5, c7, e8, g7, h5, g3 and e2 !!}

7 - #4 single combat & circé

single combat a unit that has just played continues, until it is impossible.
circe a captured piece reborn on its original square if it is free, otherwise it disappears.

Rittirsch, M.
1990

white Pd7e6g4a2b3b4b5c4 Sg5a3 Bf7g3 Kh2 Rf3 black Pb7c7e7g7g6 Kh8 Bd8

#4 single combat circe(14+7)

Solution

{

} 1.b5-b6 ! {

} 1...c7*b6[+wPb2] {(pb2 being blocked, an other unit can play.)} 2.Bf7*g6 2...b6-b5 3.Bg6-b1 zugzwang. 3...b5*c4[+wPc2] 4.Rf3-f8 # {(Bb1 being blocked, an other unit can play.)

} 1...c7-c5 2.Rf3-f1 zugzwang. 2...c5*b4[+wPb2] 3.Rf1-h1 zugzwang. 3...b4*a3[+wSg1] 4.Kh2-g2 # {(Rh1 being blocked, an other unit can play)

} 1...c7-c6 2.Bg3-e5 zugzwang. 2...c6-c5 3.Be5-a1 zugzwang. 3...c5*b4[+wPb2] 4.Rf3-h3 # { (Ba1 being blocked, an other unit can play)}

8 - h#4 2 solutions leffie

leffieLeffie is to the Eiffel what the Isardam is to the Madrasi: it is illegal to put oneself in a situation of Eiffel paralysis.
Eiffela piece paralyses an opposing piece of the next higher level according to the scheme P - N - B - R - Q - P

Crisan, V.
2019

white Kf1 Bb1 black Pd3f3 Ke4

h#4 2sol. leffie(2+3)

Solution

{

} 1.f3-f2 Bb1-a2 2.d3-d2 Kf1-e2 3.f2-f1=R Ba2-b1 + 4.Rf1-f5 {avoids check because Be4 would paralyse Rf5} Ke2-e3 # {: BK is "pinned".

} 1.Ke4-e3 Kf1-g1 2.d3-d2 Bb1-e4 3.Ke3-e2 Be4*f3 + 4.d2-d1=R {(Be2 would paralyse Rd1)} Kg1-f2 #

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