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1 - 2# Anda
Anda(invented by the author of this problem), any unit (except King)
performing a direct check immediately becomes neutral. If it is already neutral, it becomes white or black, depending on which side plays it.
Petkov, P.2019
white Pc4g3 Sa3c2 Be1g6 Kb6 Rf5
black Pe2g4 Kd3 Re4
{Try :}
1.Kb6-c5 ? Re4-e6 ! {}
1.Kb6-c6 ! {}
1...Re4-e6=n + 2.nRe6-e3=w # {}
1...Re4*c4=n + 2.nRc4-d4=w # {}
1...Re4-d4 2.Rf5-d5 # {: the Bishop does not become neutral because his check is indirect}
1...Re4-e3 2.Rf5-f3 # {}
1...Re4-f4 2.Rf5*f4 # {}
1...Re4-e8 2.Rf5-e5 # {(} 2.Rf5-d5=n + ? nRd5-f5=b ! {}
2.Rf5-f3=n + nRf3-f5=b {)}
1...Re4-e5 2.Rf5*e5 #
2 - hs#4,5 reverse anda
reverse anda any unit making a move that is not a direct check becomes immediately neutral.
If it is already neutral, it becomes white or black, depending on which side plays it.
{}
1...Kh1-h2 2.Kc8-b8 d2-d1=nR { : the Rook does not give check and therefore becomes neutral.}
3.Kb8-a8 nRd1-g1=b {Becomes a Black Rook.} 4.b7-b8=Q + {Remains a White Queen because of check.} 4...Kh2-h1 5.b6-b7=w
{Become a white pawn.} Rg1-a1 # {Other Rook moves are illegal, because the Rook that has become neutral would check the Black King.
(and there} 6.Qb8-a7=n {? is illegal because becoming a neutral Queen.
Please note that on } 4.b7-b8=R ? Kh2-h1 5.b6-b7=w {is prevented by } Kh1-h2 !
3 - 2# bicolores
bicolores In Bicolore, the Kings are so sensitive that they cannot tolerate being " checked " by the units of their own side.
locuste Grasshopper that eats its hurdle (which is necessarily an opponent's piece)
rose Extended and rounded knight e.g. ROf8 can go to d7, c5, d3, f2, h3, h7, g6, f4, d3, b4, a6, b8
{}
1.ROd1-e3 ROf8-a6 2.Qe1-d1 Lh1*d1-c1 {=}
1.Kd2-c2 ROf8-h3 2.Qe1-c3 Lh1*d1-c1 {=It should be noted that apparently there are other solutions such as :}
1.ROd1-c3 ROf8-b4 2.Qe1-f1 Lh1*f1-e1 {but it's not pat ...because of the "null" move 3.ROc3-c3 via b5, c7, e8, g7, h5, g3 and e2 !!}
7 - #4 single combat & circé
single combat a unit that has just played continues, until it is impossible.
circe a captured piece reborn on its original square if it is free, otherwise it disappears.
Rittirsch, M.1990
white Pd7e6g4a2b3b4b5c4 Sg5a3 Bf7g3 Kh2 Rf3
black Pb7c7e7g7g6 Kh8 Bd8
{}
1.b5-b6 ! {}
1...c7*b6[+wPb2] {(pb2 being blocked, an other unit can play.)}
2.Bf7*g6
2...b6-b5
3.Bg6-b1 zugzwang.
3...b5*c4[+wPc2]
4.Rf3-f8 # {(Bb1 being blocked, an other unit can play.)}
1...c7-c5
2.Rf3-f1 zugzwang.
2...c5*b4[+wPb2]
3.Rf1-h1 zugzwang.
3...b4*a3[+wSg1]
4.Kh2-g2 # {(Rh1 being blocked, an other unit can play)}
1...c7-c6
2.Bg3-e5 zugzwang.
2...c6-c5
3.Be5-a1 zugzwang.
3...c5*b4[+wPb2]
4.Rf3-h3 # { (Ba1 being blocked, an other unit can play)}
8 - h#4 2 solutions leffie
leffieLeffie is to the Eiffel what the Isardam is to the Madrasi: it is illegal to put oneself in a situation of Eiffel paralysis.
Eiffela piece paralyses an opposing piece of the next higher level according to the scheme P - N - B - R - Q - P
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