py_20180703

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or directly on the move in the solution

1 - h#2 2 sol circe

circé : une pièce prise renaît sur sa case originelle si celle-ci est libre, sinon, elle disparaît

Caillaud, M.
2012

white Qd1 Pb7 Ka1 black Qg8 Pc7 Sc6 Kf4

h#2 circe(3+4)

Solution

{

} 1.Kf4-e3 b7-b8=S 2.Sc6*b8[+wSg1] Qd1-d4 # {

} 1.Kf4-e4 b7-b8=B 2.Qg8*b8[+wBc1] Qd1-d5 # {

Chameleon-echo.
Not too bad for a problem composed, it seems, under the shower. !}

2 - h#2 circe

Rimkus, M.
2012

white Se1 Bf1 Kb3 black Pf2 Kd1

h#2 circe(3+2)
b) move everything one column left

Solution

{

} a) {
} 1.Kd1-d2 Bf1-e2 2.Kd2*e1[+wSg1] Sg1-f3 # {(no promotion !)

} b) shift b1 ==> a1 {Twin: move everything one column left.
} 1.e2*d1=B[+wSb1] Sb1-c3 2.Bd1-c2 Be1-d2 #

3 - serial h#5 2 sol circe

serial helpmate : black plays n moves in a row, after which white checks in 1 move

Bakcsi, G & Zoltan L
2002

white Rh6 Ka2 Bb1e3 Sf1 black Pe5 Sd2 Kd5

ser-h#5 2sol.(5+3)

Solution

{

} 1.Sd2*b1 {No rebirth, f1 square being occupied.} 2.Sb1-d2 3.Sd2*f1[+wSb1] 4.Sf1-d2 {
} 5.Sd2-c4 Sb1-c3 # {

} 1.Sd2*f1 {(wN disappears, b1 being occupied)} 2.Sf1-d2 3.Sd2*b1[+wBf1] 4.Sb1-d2 {
} 5.Sd2-e4 Bf1-c4 #

4 - h#2 exclusive chess with locust

exclusive chess : a mat is only legal if it is unique

Cheylan, Y.
2016

white Pa7f7 Kd2 black Pg4c2 Sf5f2 Bg3 Kf3 Lg1

h#2 exclusive chess(3+7)
g1: Locust

Solution

{

} 1.Sf5-e3 ! f7-f8=L {Nf2 is now pinned by Locust f8.
} 2.c2-c1=L ! a7-a8=L # {
Black has two tricks that both checkmate the wK and are therefore illegal :
} 3.Se3-d5 {and} 3.Se3-g2 {

Let's go back to the 2nd black move.
If } 2.Se3-g2 {, then white now has 2 mates at his disposal :} 2...a7-a8=Q {et} 2...a7-a8=B {so no mat !}

5 - h#2 mars circe

mars circe : to capture, a piece "virtually" passes through its native square if it is free

Trillon, J.M.
1984

white Pe6 Ka6 black Pg3 Ke1

h#2 mars circe(2+2)
b) pg3-->d3

Solution

{

} a) {
} 1.g3-g2 e6-e7 2.g2-g1=B e7-e8=Q # {(from d1 and square f2 is controlled by the bK)
Note that } 2.g2-g1=S ? {check by b8
. To complete, on } 2.g2-g1=R ? e7-e8=Q {don't mate because of } 3.Rg1*e8 ! {by h8

} b) bPg3-->d3 {pg3-->d3
} 1.d3-d2 e6-e7 2.d2-d1=S ! e7-e8=R # {(depuis h1)
Note also that} 2.d2-d1=B ? {check by c8
. Also for completeness, on } 2.d2-d1=Q ? e7-e8=R {don't mate because of } 3.Qd1*e8 ! {by d8} {

AUW}

6 - h#2 2 sol couscous anti-circe

couscous anti-circe : the capturing piece is reborn on the native square of the captured piece

Tritten, P.
2016

white Qh4 Pc4 Kh3 Rg4 black Pg5f5d7d6c6 Sb7 Kc7

h#2 couscous anti-circe(4+7)
2sol.

Solution

{

} 1.g5*h4-d1=R Rg4-g8 2.Rd1-d5 c4*d5-a8=S #! {

} 1.f5*g4-h1=B Qh4-d4! 2.Bh1-d5 c4*d5-c8=Q # {
bK cannot capture the Q because it would have to be reborn in d1 ;
which explains that} 1...Qh4-f2 ? {don't work

A try is :} 1.Kc7-d8 ? Rg4*g5-g7 2.Kd8-e8 Qh4-h8 {which would demolish in anti-circle Calvet, but Qxe8(Qe8) is impossible.

AUW.}

7 - 9# with siren & marine mao

Siren : Queen capturing as a Locust

. Mao marin : Mao capturing the unit during its rook step
. Reminder: the Mao is a creeping Knight doing a rook step, then a bishop step.

Tribowski, M.
2003

white Pd7d6g7c4f3g3h4 Se8f8 Bb3 Ka1 MSe6e1 black Bb8 Kf5 Ph7h5d4d3e3 SIc1 Rg8d8 MSb4

#9(13+11)
e6, e1, b4: marine Maos
c1: Siren

Solution

{

If we consider the MM as coming from a promotion, the position is illegal since there are 7 white pawns!
But in fairy composition, we apparently allow ourselves some liberties.
} 1.Bb3-c2 ! {threatens } 2.Bc2*d3# {

and here 2 defences :
} 1...d3*c2 2.MSe6-f4+ {(Threatens} 3.MSf4*f5-e6 {)} 2...Kf5-e5 3.MSf4-d5+ {( Threatens} 4.MSd5*e5-f6 {)
} 3...Ke5-f5 4.MSe1-d3! {this move is allowed by the leaving of Pd3. (Threatens } 5.MSd3*d4-e5# {)} 4...Bb8*d6 5.MSd5-f6+ Kf5-e5 {
} 6.MSf6-e4+ Ke5-f5 7.MSe4-g5+ Kf5-e5 8.MSg5-e6+ {(Return.)} Ke5-f5 9.Se8*d6# {

} 1...SIc1*c2-c3 2.MSe6-g5 + {(threatens} 3.MSg5*f5-e6 {)} 2...Kf5-e5 3.MSg5-e4 + Ke5-f5 4.MSe1-g2 ! {(threatens} 5.g3-g4 + {then} 6.MSg2-f4# {
; leaving of the c1 Siren makes the defence meaningless. ...e2)
(here, on} 4...Bb8*d6 {, we have} 5.MSe4-f6 + {as in the other main variation)
} 4...Rg8*g7 5.MSe4-f6 + Kf5-e5 6.MSf6-d5+ Ke5-f5 7.MSd5-f4+ Kf5-e5 8.MSf4-e6+ {(retour)
} Ke5-f5 9.Se8*g7# {

Two complete circuits of the Marine Mao e6.}

8 - losing chess

losing chess : In losing chess, the aim is to lose all his units knowing that the capture, when it is possible, is mandatory.

Beasley, J.
1997
(Après G. Evseev 1992)

white Sc2g1 black Pd3

losing chess(2+1)

Solution

{

} 1.Sg1-e2 ! {

} 1...d3*c2 {(Here, the symmetrical method of the other variant will not fit :} 2.Se2-d4 ? c2-c1=B ! 3.Sd4-c6 Bc1-h6 {!!!)
} 2.Se2-c3 ! c2-c1=B ! 3.Sc3-a2 ! {A square to the left of a4 is missing.
} 3...Bc1-h6 4.Sa2-c1! Bh6*c1 {
(sur } 3.Sc3-e2 ? {on a } Bc1-f4 ! 4.Se2*f4 {)

} 1...d3*e2 {(and here, not the symmetric of 1...dxc2 :} 2.Sc2-e3 ? e2-e1=B ! 3.Se3-g2 Be1-h4 {!!!)
} 2.Sc2-d4! e2-e1=B ! 3.Sd4-e6 {!!!} 3...Be1-h4 4.Se6-g5 {ou} 3...Be1-a5 4.Se6-d8 {(or on c7)} Ba5*d8 {)}

9 - 2# functionnaries

functionnaries : to move (and a fortiori capture) a unit must be "observed" by an opponent unit

Gockel, H.
2015

white Sc8c3 Rf8b3 Kb1 black Qe5 Pe6a4b5c6e4e3 Bg7f5 Rc7g3 Kd7

#2 functionnaries(5+12)

Solution

{

} 1.Sc3-e2 ? {threatens} 2.Rb3-d3 # {but} 1...Rg3-g1 + ! 1.Sc3-d1 ? {threatens} 2.Rb3-d3 # {but} 1...e3-e2 ! 1.Sc3*a4 ? {threatens} 2.Sa4-c5 # 1...b5*a4 2.Rb3-d3 # {but} 1...b5-b4 ! 1.Sc3-a2 ? {threatens} 2.Rb3-d3 # {but} 1...e3-e2 ! {

} 1.Sc3*e4 ! {threatens} 2.Se4-f6 # {
} 1...Bf5*e4 2.Rb3-d3 # {
} 1...Bf5-h7 2.Se4-c5 # {

The threats of both tries are found in the variations of the real play.
"Tertiary threat correction", say the experts.}

10 - h#2 2 sol isardam einstein

Isardam : It is illegal for 2 opposing pieces of the same kind to "observe" each other
. Einstein: a unit (other than the King) changes at each move into the unit immediately stronger in case of capture,
immediately less strong in case of no capture.

The bR is in check by the wQ, but not by the Bishop, which would become a R after BxK. Similarly, the wK is not in check by the bQf6

Harris, P.
2007

white Qc8 Kc6 Bc4 black Qf6 Rg4 Kg8 Be7

h#2 isardam einstein(3+4)

Solution

{

} 1.Kg8-h7 Bc4-f7=S 2.Qf6-h4=R Qc8-h8=R # {

} 1.Qf6-f8=R Bc4-d5=S 2.Kg8-f7 Qc8-f5=R # {
We cannot have cover with the bB, which would become a Knight.}

11 - inv 9# with Royal Grasshoppers

Grasshopper: moves along the Queen's lines with the help of a sautoir behind which it lands
. Royal Grasshopper: piece invested with royal prerogatives with the grasshopper march

Turner, N.
2007

white Bf8 Rg3d8 white Royal gd1 black Pd2 Bg6 black Royal gg8

s#9(4+3)
d1, g8: Royal Grasshoppers

Solution

{

Try : } 1.Rd8-d6 ? rGg8-e8 2.Rd6-e6+ rGe8-h5! {

} 1.Bf8-g7 + ! Bg6-e8 2.Rg3-d3 rGg8-g6 3.Rd3-d6 + rGg6-g8 4.Rd6-d4 rGg8-g6 {
} 5.Rd4-g4 + rGg6-g8 6.Bg7-f8 + Be8-g6 {Diagram with wR on g4 instead of g3.
} 7.Rd8-d6 rGg8-e8 8.Rd6-e6 + rGe8-g8 9.Rg4-g2 ! rGg8-d5 # {
Please note that } 9.Rg4-g1 ? {would provide an escape route for the Royal Grasshopper d1 } rGg8-d5 + 10.rGd1-h1

12 - aidé 2# isardam

Smits, G.
2010

white Pe2 Sg2c6 Ra7 Kd8 Be8 black Bd5g5 Ke4 Qb3 Pf6 Sa8h1 Re5

h#2 Isardam(6+8)
b) Nc6-->e7

Solution

{

} a) {
} 1.Bg5-h4 ! Be8-g6 2.Re5-h5 Ra7-e7 # {
3.Th4, 3.Te5 et 3.Fe6 ((no longer protecting his King) are impossible.
Note the following try : } 1.Re5-f5 ? Ra7-a3 2.Qb3-f3 e2*f3+ {
et} 3.Rf5*f3 {is illegal but not } 3.Ke4*f3! {

} b) wSc6-->e7 {Nc6-->e7
} 1.Qb3-b1 Ra7-a4 {(no check)} 2.Bd5-a2 Be8-c6 # {
3.Bb1, 3.Bd5 and 3.Rd5 are impossible}

13 - 2# with rose

rose : Rounded nightrider.
If there was nothing on d7 and f6, the Rose a4 would check through b6, d7 and f6

Quah, J.
2015
Version J. Dupin & M. Kerhuel

white Bh7 Kg7 Qf6 Pe3 Sg1d6 Rh3d7 ROa4 black Sc4f8 Pg5h6e6c2c3 Be2e1 Rd1f2 Kg4

#2(9+12)
a4: Rose

Solution

{

} 1.Sd6-f7 ! {threatens} 2.Sf7*h6 # {(for example } 1...c2-c1=Q 2.Sf7*h6 # {)
} 1...Rd1*d7 {(pinning f2)} 2.Qf6-d4 # {(pinning d7 via b6-d7-f6-g4 while f2 remains pinned: a4-b2-d1-f2-g4
} 1...Rf2*f6 {(pinning d1)} 2.Rd7-d4 # {(pinning f6, while d1 remains pinned)

No try or Apparent Play, and only two variants (besides the threat-variant). Isn't this restful ?}

14 - h=12 2 solutions with nightriders hopper

nightrider hopper: moves like a Nightrider, but only with the aid of a sautoir,
behind which it lands at a knight's step
. For example, NHh1 controls f5 by passing by g3.

Kotesovec, V.
2016

white NHh1d1a8e8f7 black Kg3

h=12 2sol.(5+1)
h1, d1, a8, e8, f7: nightriders hopper

Solution

{

} 1.Kg3-g4 NHe8-h2 2.Kg4-g5 NHf7-h3 3.Kg5-g4 NHh2-f6 4.Kg4-f4 NHh3-d5 {
} 5.Kf4-e3 NHd5-f1 6.Ke3-d3 NHh1-b4 7.Kd3-c4 NHa8-d2 8.Kc4-d5 NHf1-c7 {
} 9.Kd5-e6 NHb4-h7 10.Ke6-f7 NHh7-d5 11.Kf7-g7 NHc7-e3 12.Kg7-h8 NHd1-f5 {
model stalemate: d5 control h7 (sautoir f6), d2 control g8 (idem), e3 control g7 (sautoir f5).

} 1.Kg3-f2 NHh1-d3 2.Kf2-e3 NHd1-f5 3.Ke3-f4 NHd3-h5 4.Kf4-g3 NHf5-h1 {
} 5.Kg3-f4 NHh5-d3 6.Kf4-f5 NHh1-e7 7.Kf5-e6 NHa8-g5 8.Ke6-d5 NHf7-h3 {
} 9.Kd5-c4 NHe8-b2 10.Kc4-b3 NHb2-f4 11.Kb3-a2 NHh3-d5 12.Ka2-a1 NHe7-c3 {
model stalemate: d5 control b1 (sautoir c3), g5 control a2 (ditto), f4 control b2 (sautoir d3).

Echo from one corner to the opposite corner.}

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