py_20180703
Click in the right part of the chessboard to move forward, left to move backward... or directly on the move in the solution
1 - h#2 2 sol circe
Caillaud, M.2012
white Qd1 Pb7 Ka1
black Qg8 Pc7 Sc6 Kf4
h#2 circe(3+4)
{}
1.Kf4-e3 b7-b8=S 2.Sc6*b8[+wSg1] Qd1-d4 # {}
1.Kf4-e4 b7-b8=B 2.Qg8*b8[+wBc1] Qd1-d5 # {Chameleon-echo.
Not too bad for a problem composed, it seems, under the shower. !}
2 - h#2 circe
Rimkus, M.2012
white Se1 Bf1 Kb3
black Pf2 Kd1
h#2 circe(3+2)b) move everything one column left
{}
a) {}
1.Kd1-d2 Bf1-e2 2.Kd2*e1[+wSg1] Sg1-f3 # {(no promotion !)}
b) shift b1 ==> a1 {Twin: move everything one column left.}
1.e2*d1=B[+wSb1] Sb1-c3 2.Bd1-c2 Be1-d2 #
3 - serial h#5 2 sol circe
Bakcsi, G & Zoltan L2002
white Rh6 Ka2 Bb1e3 Sf1
black Pe5 Sd2 Kd5
ser-h#5 2sol.(5+3)
{}
1.Sd2*b1 {No rebirth, f1 square being occupied.} 2.Sb1-d2 3.Sd2*f1[+wSb1] 4.Sf1-d2 {}
5.Sd2-c4 Sb1-c3 # {}
1.Sd2*f1 {(wN disappears, b1 being occupied)} 2.Sf1-d2 3.Sd2*b1[+wBf1] 4.Sb1-d2 {}
5.Sd2-e4 Bf1-c4 #
4 - h#2 exclusive chess with locust
Cheylan, Y.2016
white Pa7f7 Kd2
black Pg4c2 Sf5f2 Bg3 Kf3 Lg1
h#2 exclusive chess(3+7)🨐g1: Locust
{ }
1.Sf5-e3 ! f7-f8=WL {Nf2 is now pinned by Locust f8.}
2.c2-c1=L ! a7-a8=WL # {
Black has two tricks that both checkmate the wK and are therefore illegal :}
3.Se3-d5 {and} 3.Se3-g2 {Let's go back to the 2nd black move.
If } 2.Se3-g2 {, then white now has 2 mates at his disposal :} 2...a7-a8=Q {and} 2...a7-a8=B {so no mat !}
5 - h#2 mars circe
Trillon, J.M.1984
white Pe6 Ka6
black Pg3 Ke1
h#2 mars circe(2+2)b) ♟g3-->d3
{
} a) {} 1.g3-g2 e6-e7 2.g2-g1=B e7-e8=Q # {(from d1 and square f2 is controlled by the bK)Note that } 2.g2-g1=S ? {check by b8
. To complete, on } 2.g2-g1=R ? e7-e8=Q {don't mate because of } 3.Rg1*e8 ! {by h8} b) bPg3-->d3 {pg3-->d3} 1.d3-d2 e6-e7 2.d2-d1=S ! e7-e8=R # {(depuis h1)Note also that} 2.d2-d1=B ? {check by c8. Also for completeness, on } 2.d2-d1=Q ? e7-e8=R {don't mate because of } 3.Qd1*e8 ! {by d8} {AUW}
} a) {} 1.g3-g2 e6-e7 2.g2-g1=B e7-e8=Q # {(from d1 and square f2 is controlled by the bK)Note that } 2.g2-g1=S ? {check by b8
. To complete, on } 2.g2-g1=R ? e7-e8=Q {don't mate because of } 3.Rg1*e8 ! {by h8} b) bPg3-->d3 {pg3-->d3} 1.d3-d2 e6-e7 2.d2-d1=S ! e7-e8=R # {(depuis h1)Note also that} 2.d2-d1=B ? {check by c8. Also for completeness, on } 2.d2-d1=Q ? e7-e8=R {don't mate because of } 3.Qd1*e8 ! {by d8} {AUW}
6 - h#2 2 sol couscous anti-circe
Tritten, P.2016
white Qh4 Pc4 Kh3 Rg4
black Pg5f5d7d6c6 Sb7 Kc7
h#2 couscous anti-circe(4+7)2sol.
{}
1.g5*h4-d1=R Rg4-g8 2.Rd1-d5 c4*d5-a8=S #! {}
1.f5*g4-h1=B Qh4-d4! 2.Bh1-d5 c4*d5-c8=Q # {bK cannot capture the Q because it would have to be reborn in d1 ;
which explains that} 1...Qh4-f2 ? {don't workA try is :}
1.Kc7-d8 ? Rg4*g5-g7 2.Kd8-e8 Qh4-h8 {which would demolish in anti-circle Calvet, but Qxe8(Qe8) is impossible.AUW.}
7 - 9# with siren & marine mao
Tribowski, M.2003
white Pd7d6g7c4f3g3h4 Se8f8 Bb3 Ka1 WMe6e1
black Bb8 Kf5 Ph7h5d4d3e3 SIc1 Rg8d8 BMb4
#9(13+11)
🨷e6, e1, 🨽b4: marine Maos🨺c1: Siren
{
If we consider the MM as coming from a promotion, the position is illegal since there are 7 white pawns!
But in fairy composition, we apparently allow ourselves some liberties.}
1.Bb3-c2 ! {threatens } 2.Bc2*d3# {and here 2 defences : }
1...d3*c2 2.WMe6-f4+ {(Threatens} 3.WMf4*f5-e6 {)} 2...Kf5-e5 3.WMf4-d5+ {( Threatens} 4.WMd5*e5-f6 {)}
3...Ke5-f5 4.WMe1-d3! {this move is allowed by the leaving of Pd3. (Threatens } 5.WMd3*d4-e5# {)} 4...Bb8*d6 5.WMd5-f6+ Kf5-e5 {}
6.WMf6-e4+ Ke5-f5 7.WMe4-g5+ Kf5-e5 8.WMg5-e6+ {(Return.)} Ke5-f5 9.Se8*d6# {}
1...SIc1*c2-c3 2.WMe6-g5 + {(threatens} 3.WMg5*f5-e6 {)} 2...Kf5-e5 3.WMg5-e4 + Ke5-f5 4.WMe1-g2 ! {(threatens} 5.g3-g4 + {then} 6.WMg2-f4# {
; leaving of the c1 Siren makes the defence meaningless. ...e2)
(here, on} 4...Bb8*d6 {, we have} 5.WMe4-f6 + {as in the other main variation)}
4...Rg8*g7 5.WMe4-f6 + Kf5-e5 6.WMf6-d5+ Ke5-f5 7.WMd5-f4+ Kf5-e5 8.WMf4-e6+ {(retour)}
Ke5-f5 9.Se8*g7#
{Two complete circuits of the Marine Mao e6.}
8 - losing chess
Beasley, J.1997(Après G. Evseev 1992)
white Sc2g1
black Pd3
losing chess(2+1)
{}
1.Sg1-e2 ! {}
1...d3*c2 {(Here, the symmetrical method of the other variant will not fit :} 2.Se2-d4 ? c2-c1=B ! 3.Sd4-c6 Bc1-h6 {!!!)}
2.Se2-c3 ! c2-c1=B ! 3.Sc3-a2 ! {A square to the left of a4 is missing.} 3...Bc1-h6 4.Sa2-c1! Bh6*c1 {
(sur } 3.Sc3-e2 ? {on a } Bc1-f4 ! 4.Se2*f4 {)}
1...d3*e2 {(and here, not the symmetric of 1...dxc2 :} 2.Sc2-e3 ? e2-e1=B ! 3.Se3-g2 Be1-h4 {!!!)}
2.Sc2-d4! e2-e1=B ! 3.Sd4-e6 {!!!} 3...Be1-h4 4.Se6-g5 {ou} 3...Be1-a5 4.Se6-d8 {(or on c7)} Ba5*d8 {)}
9 - 2# functionnaries
Gockel, H.2015
white Sc8c3 Rf8b3 Kb1
black Qe5 Pe6a4b5c6e4e3 Bg7f5 Rc7g3 Kd7
#2 functionnaries(5+12)
{}
1.Sc3-e2 ? {threatens} 2.Rb3-d3 # {but} 1...Rg3-g1 + !
1.Sc3-d1 ? {threatens} 2.Rb3-d3 # {but} 1...e3-e2 !
1.Sc3*a4 ? {threatens} 2.Sa4-c5 # 1...b5*a4 2.Rb3-d3 # {but} 1...b5-b4 !
1.Sc3-a2 ? {threatens} 2.Rb3-d3 # {but} 1...e3-e2 ! {}
1.Sc3*e4 ! {threatens} 2.Se4-f6 # {}
1...Bf5*e4 2.Rb3-d3 # {}
1...Bf5-h7 2.Se4-c5 # {
The threats of both tries are found in the variations of the real play.
"Tertiary threat correction", say the experts.}
10 - h#2 2 sol isardam einstein
Harris, P.2007
white Qc8 Kc6 Bc4
black Qf6 Rg4 Kg8 Be7
h#2 isardam einstein(3+4)
{}
1.Kg8-h7 Bc4-f7=S 2.Qf6-h4=R Qc8-h8=R # {}
1.Qf6-f8=R Bc4-d5=S 2.Kg8-f7 Qc8-f5=R # {
We cannot have cover with the bB, which would become a Knight.}
11 - inv 9# with Royal Grasshoppers
Turner, N.2007
white Bf8 Rg3d8
white Royal WGd1
black Pd2 Bg6
black Royal BGg8
s#9(4+3)🨟d1, 🨥g8: Royal Grasshoppers
{Try : }
1.Rd8-d6 ? rBGg8-e8 2.Rd6-e6+ rBGe8-h5! {}
1.Bf8-g7 + ! Bg6-e8 2.Rg3-d3 rBGg8-g6 3.Rd3-d6 + rBGg6-g8 4.Rd6-d4 rBGg8-g6 {}
5.Rd4-g4 + rBGg6-g8 6.Bg7-f8 + Be8-g6 {Diagram with wR on g4 instead of g3.}
7.Rd8-d6 rBGg8-e8 8.Rd6-e6 + rBGe8-g8 9.Rg4-g2 ! rBGg8-d5 # {
Please note that } 9.Rg4-g1 ? {would provide an escape route for the Royal Grasshopper d1 } rBGg8-d5 + 10.rWGd1-h1
12 - aidé 2# isardam
Smits, G.2010
white Pe2 Sg2c6 Ra7 Kd8 Be8
black Bd5g5 Ke4 Qb3 Pf6 Sa8h1 Re5
h#2 Isardam(6+8)b) ♘c6-->e7
{}
a) {}
1.Bg5-h4 ! Be8-g6 2.Re5-h5 Ra7-e7 # {
3.Th4, 3.Te5 et 3.Fe6 ((no longer protecting his King) are impossible.
Note the following try : } 1.Re5-f5 ? Ra7-a3 2.Qb3-f3 e2*f3+ {
et} 3.Rf5*f3 {is illegal but not } 3.Ke4*f3! {}
b) wSc6-->e7 {Nc6-->e7}
1.Qb3-b1 Ra7-a4 {(no check)} 2.Bd5-a2 Be8-c6 # {
3.Bb1, 3.Bd5 and 3.Rd5 are impossible}
13 - 2# with rose
Quah, J.2015Version J. Dupin & M. Kerhuel
white Bh7 Kg7 Qf6 Pe3 Sg1d6 Rh3d7 ROa4
black Sc4f8 Pg5h6e6c2c3 Be2e1 Rd1f2 Kg4
#2(9+12)a4: Rose
{}
1.Sd6-f7 ! {threatens} 2.Sf7*h6 # {(for example } 1...c2-c1=Q 2.Sf7*h6 # {)}
1...Rd1*d7 {(pinning f2)} 2.Qf6-d4 # {(pinning d7 via b6-d7-f6-g4 while f2 remains pinned: a4-b2-d1-f2-g4}
1...Rf2*f6 {(pinning d1)} 2.Rd7-d4 # {(pinning f6, while d1 remains pinned)
No try or Apparent Play, and only two variants (besides the threat-variant). Isn't this restful ?}
14 - h=12 2 solutions with nightriders hopper
Kotesovec, V.2016
white NHh1d1a8e8f7
black Kg3
h=12 2sol.(5+1)🨷h1, d1, a8, e8, f7: nightriders hopper
{}
1.Kg3-g4 NHe8-h2 2.Kg4-g5 NHf7-h3 3.Kg5-g4 NHh2-f6 4.Kg4-f4 NHh3-d5 {}
5.Kf4-e3 NHd5-f1 6.Ke3-d3 NHh1-b4 7.Kd3-c4 NHa8-d2 8.Kc4-d5 NHf1-c7 {}
9.Kd5-e6 NHb4-h7 10.Ke6-f7 NHh7-d5 11.Kf7-g7 NHc7-e3 12.Kg7-h8 NHd1-f5 {
model stalemate: d5 control h7 (sautoir f6), d2 control g8 (idem), e3 control g7 (sautoir f5).}
1.Kg3-f2 NHh1-d3 2.Kf2-e3 NHd1-f5 3.Ke3-f4 NHd3-h5 4.Kf4-g3 NHf5-h1 {}
5.Kg3-f4 NHh5-d3 6.Kf4-f5 NHh1-e7 7.Kf5-e6 NHa8-g5 8.Ke6-d5 NHf7-h3 {}
9.Kd5-c4 NHe8-b2 10.Kc4-b3 NHb2-f4 11.Kb3-a2 NHh3-d5 12.Ka2-a1 NHe7-c3 {
model stalemate: d5 control b1 (sautoir c3), g5 control a2 (ditto), f4 control b2 (sautoir d3).
Echo from one corner to the opposite corner.}
Add a comment