{}
1.QNc5-a4 ! {threatens} 2.Qh6*g6 # {}
1...Rb3-c3 2.Qh6-f8 # {}
1...Bb2-c3 2.Qh6*h3 # { because f4 is controlled by Qua4 via c5-d3}
1...QNb5-c3 {controls f7 via e4 & d6, as well as h3 via e2 & f4, so both wQ checks are avoided} 2.Sc6-d4 # {}
1...QNd1-c3 {same remark} 2.QNh2-e3 #{}
1...h3*g2 2.Qh6*g6 #{Queen is supported by the Quintessence a4 via c3, d5 & f4.
Quadruple Grimshaw.
The author specifies that he dedicated this problem to J.-M. Loustau in memory of an article by him, 19 years earlier,
on the triple Grimshaw with a rook, a bishop and a "normal" nightjar. Strangely, I was reading at the same time an
article by Mark Gordian (page 342 of Themes/64 1961) mentioning one of his problems on this theme dating from... 1928!
No, the fairy is not new.}
2 - h#5 circe
Circe : a captured piece is reborn on its native square if it is free, otherwise it disappears
{ }
1.h7-h8=B 2.Bh8*g5 3.Bg5-f6 4.g4-g5 {}
5.g5-g6 6.g6-g7 7.g7-g8=S 8.Sg8*c3 {}
9.Sc3-e4 10.c2-c4 11.c4-c5 12.c5-c6 {}
13.c6-c7 14.c7-c8=Q 15.Qc8*h5 16.Qh5-f5 {}
17.h4-h5 18.h5-h6 19.h6-h7 20.h7-h8=R {}
21.Rh8*a6 22.Ra6-e6 {pat !It is surprising that this problem has not already been composed since 1980, when the Mars circe was invented.}
6 - aidé 4# Clone Circe
Clone Circe : the captured unit takes the nature of the capturing unit and is reborn accordingly.
Captures by the King follow the rules of normal Circe
Chameleon Circe : a captured piece rises in rank before being reborn, according to the N-B-R-Q pattern.
Pawns are reborn as in normal Circe
{}
a) {Clone Circe}
1.Rd2*c2[+wRh1] 0-0 2.d3-d2 Kg1-h2 3.d2-d1=Q + Kh2-g3 4.Qd1*f1[+wQd1] Qd1-d5 # {}
b) wSc2-->b3 {Cc2-->b3 Chameleon Circe}
1.Rd2-f2 Sb3-d4 2.Ke4*d4[+wBc1] Bc1*e3[+bPe7] + 3.Kd4*e3[+wRa1] 0-0-0 4.Ke3-e2 Rd1-e1 # {
taking this rook would resurrect a white Queen on d1Castle in each phase.}
7 - serial h#69 Circe Exchange with roses
Rose : Extended knight with rounded path.
Exchange circe: the captured piece returns to the starting square of the capturing piece.
This masterpiece, which would have deserved a first prize, was under-ranked by the judges,
talking slyly about "computer-assisted composition".
As if the others were not...
Furthermore, the said judges botch the problem in two lines without explaining anything.
{Essai :}
1.Kh3-g3 ? {leads to a deadlock, f2 being controlled by Rose f6 and f3 by Rose b7, via d8-f7-g5}
1.Kh3-g2 ! 2.Kg2-f1 3.Kf1-e2 4.Ke2-d3 5.Kd3-c4 6.Kc4-b5 7.Kb5-c6 8.Kc6*b7[+wROc6] {}
9.Kb7-a6 10.Ka6-b5 11.Kb5*c6[+wROb5] 12.Kc6-c5 13.Kc5-c4 14.Kc4*b5[+wROc4] {}
15.Kb5-c6 {For a4 is controlled by the Rose f6, via d7-b6.} 16.Kc6-c7 {}
17.Kc7-d8 18.Kd8-e7 19.Ke7-f8 {For f7 is controlled by the Rose c4.} 20.Kf8-g7 {
} 21.Kg7-g6 {For h6 is controlled by the Rose c4, via d6-f7.} 22.Kg6-g5 23.Kg5-h4 24.Kh4-g3 {}
25.Kg3-f3 26.Kf3-e2 27.Ke2-d3 28.Kd3-c2 29.Kc2-b3 {The judges, after having started at the 7th move (!)
went directly from the 14th to the 29th move! A way to show their contempt for this problem.}
30.Kb3*a2[+wSb3] 31.Ka2-b1 32.Kb1-c2 {}
33.Kc2-d3 34.Kd3*c4[+wROd3] 35.Kc4-b5{Here the judges go straight to the 47th !} 36.Kb5-c6 37.Kc6-c7 38.Kc7-d8 39.Kd8-e7 {}
40.Ke7-f7 {Contrary to the 19th move, we no longer pass through f8, controlled by the d3 Rose, via c5-d7.}
41.Kf7-g7 42.Kg7-h6 43.Kh6-g5 44.Kg5-h4 45.Kh4-g3 46.Kg3-f3 47.Kf3-e2 48.Ke2*d3[+wROe2] {}
49.Kd3-c4 50.Kc4*b3[+wSc4] 51.Kb3-b4 {Here the judges go straight to the 64th !}
52.Kb4-c5 {And not by b5, as the 3 previous times, because it is controlled by the Rose e2.}
53.Kc5-c6 54.Kc6-b7 {For c7 is also controlled by the Rose e2.} 55.Kb7-c8 56.Kc8-d8 {}
57.Kd8-e7 58.Ke7-f7 59.Kf7-g6 {Unlike the 41st move, this square is free.}
60.Kg6-g5 61.Kg5-h4 62.Kh4-h3 63.Kh3-g2 64.Kg2-f3 {}
65.Kf3*e2[+wROf3] 66.Ke2-d3 67.Kd3-c2 {For c3 is controlled by the Rose f6.}
68.Kc2-b1 ! {Because b2 is controlled by the c4 Knight, but also by the f6 Rose, via g4-f2-d1.} 69.Kb1-a2 ROf6-c3 # !
{Rose c3 controls a2 & b1, Knight c4 controls a3 & b2, Rose f3 controls b3 & a1. Congratulations to the author !}
8 - #2 Calvet anti-circe with lions
Lion : moves on the Queen's lines but with the help of a sautoir .
The squares must be free between the starting square and the sautoir and between the sautoir and the landing square
which may be free or occupied by an opposing piece.
Calvet anti-circe: the capturing piece is reborn on its original square .
In Calvet anti-circe, the capturing and rebirth square can be the same.
A fairy piece being promoted is reborn on the promotion square
Caillaud, M.2008
white Pf7f6a3d5 Kb3 Bg4 Re2 LIh5f8e1g1b7d7
black Pe7g2g5 Kf4 Be8 LIf3h4
{a few things to start with : }
1...Be8*f7[bBf7->c8] { is illegal because of Lion f8 ; } 1...LIh4*f6[bLIf6->f1] {display-departure-file} { i illegal with same reason
noter that } 1.Re2-e4 + ? {don't mat because of} 1...LIf3*a3[bLIa3->a1] !{}
1.Re2-f2 ! 1...e7-e6 { or } 1...e7-e5 {(threat-variation)} 2.f7*e8=B[wBe8->f1] # {
the square f1 being now occupied prevents LIh4xf6->f1 }
1...Kf4-e3 + 2.f7*e8=S[wSe8->b1] # {car} 2...LIf3*b3 { and rebirth on b1 is impossible,
as} 2...Ke3*f2[bKf2->e8] {because of Lion e1}
1...Kf4-e4 2.f7*e8=Q[wQe8->d1] # {car} 2...LIf3*d5 { and rebirth in d1 is impossible}
1...Kf4-e5 2.f7*e8=R[wRe8->h1] # {car} 2...LIf3*h5 { and rebirth in h1 is impossible}
1...Be8*d7[bBd7->c8] 2.Bg4*f3[wBf3->f1] # {: e3 is controlled by Lg1 (also g4), e5 by Lh5, e4 by Lb7
all these Lions can now be reborn in e8}
1...LIh4*e1 {in Calvet, the capture is allowed on the rebirth square} 2.f7*e8=LI # {same remark
it's really mat because} 2...Kf4*g4 {is impossible, the nature of the promotion having retained the occupation of e8;
on the other hand, the Lion e8 recovers the squares e3, e4 & e5.AUW to 5.
One of the few relatively digestible problems in the competition, yet ranked... 13th !}
Add a comment