py_20171024

1 - parry-series selfmate 9 moves circe

Predrag, N.
2015

white Pc2 Kb6 Bf8 Sd6 black Be3f1 Kd5 Qe2 Pe6e5d4d3b3 Sc7 Rc1

pser-s#9 Circé(4+11)

: in "parry" White is allowed to check,
but then Black must parry it before the series resumes.

Solution

{
try :
} 1.c2-c4 + d4*c3 ep.[+wPc2]+ {and no mat

solution
} 1.c2-c3 2.c3-c4 + Rc1*c4[+wPc2] 3.c2*d3[+bPd7] 4.d3*c4[+bRa8] + Qe2*c4[+wPc2] {
} 5.c2*b3[+bPb7] 6.b3*c4[+bQd8] + Bf1*c4[+wPc2] 7.Sd6*c4[+bBc8] 8.Sc4-d6 {
} 9.c2-c4 + d4*c3 ep.[+wPc2] # {
Albino theme in one line of play.}

2 - h#2,5 with Apparent Play and lions

Loerinc, J.
2013

white Sa4 Kf8 WLa8 black Pd4 Kb4 Re6 BLb6b2

h#2.5(3+5)
🨴a8, 🨺b6, b2: Lion

: piece moving on the Queen's lines and needing a sautoir.
the path must be clear between the starting square and the sautoir and between the sautoir and the landing square

Solution

{
Apparent Play :
} 1... ... 2.BLb6-b3 Sa4-c5 3.Kb4-a3 Sc5-a6 # {

Solution
} 1...WLa8-a1 2.BLb2-b5 Sa4-c3 3.Kb4-a5 Sc3-a2 #

3 - 2# Transmuted Kings with Grasshoppers & Nightriders

Dulbergs, I.
2004

white Bc8e1 WGb1b6g7 Ka7 Na1 Qh8 Pd7e2g3h2 Sb4 black Qg2 Pd6f3d3c4 Ke5 BGe8h7

#2 Rois transmutés(13+8)
🨟b1, b6, g7, 🨥e8, h7: Grasshoppers
🨢a1: Nightrider

: moves on the Queen's lines with the help of a sautoir.
the finishing square is just behind the sautoir and must be free or occupied by an opposing piece which is then captured.
: extended knight
. : when checked, the King captures the march of the piece that is attacking it for the time of the aggression

Solution

{

} 1.WGg7-c7 + ! {In double check, bK acquires the march of the two pieces putting him in check, a Queen and a Grasshopper.}} 1...Ke5-f5 2.d7*e8=Q # {
} 1...Ke5*e1 2.d7*e8=WG # {(e3 is controlled by NIa1, a5 by Gc7)
} 1...Ke5*h2 2.d7*e8=N # {(f1 is controlled by Gb1)
} 1...Ke5-g5 2.h2-h4 # {(g4 is controlled by NIa1)
} 1...Ke5*h8 2.Be1-c3 # {(c3 is controlled by Gc7) and not} 2.d7*e8=R+? Kh8*e8! {
} 1...Ke5*e2 2.d7*e8=R # {(making a Queen would give bK the square d1)
} 1...Ke5-h5 2.d7*e8=B # {
} 1...Ke5*c7 2.d7*e8=S # {(b5 is controlled by Gb1)

. Super AUW of 6 promotions.}

4 - serial h=87

Tuengler, A.
2010

white Pa6f6e5f5g4e3g2c3 Kd6 Ra2 Sb3b1 Bd1 black Pf7 Ke4

ser-h=87(13+2)

If the b3-Knight and c3-pawn disappear, the Ra2-a3 move stalemates, doesn't it?
But the black King can't capture them without also exterminating the other knight and the bishop. So...

Solution

{

} 1.Ke4-d3 2.Kd3-c4 3.Kc4-b5 4.Kb5-b6 5.Kb6-a7 6.Ka7-b8 7.Kb8-c8 8.Kc8-d8 {
} 9.Kd8-e8 10.Ke8-f8 11.Kf8-g8 12.Kg8-h7 13.Kh7-h6 14.Kh6-g5 15.Kg5-h4 16.Kh4-g3 {
} 17.Kg3-h2 18.Kh2-g1 19.Kg1-f1 20.Kf1-e1 21.Ke1*d1 22.Kd1-e1 23.Ke1-f1 24.Kf1-g1 {
} 25.Kg1-h2 26.Kh2-g3 27.Kg3-h4 28.Kh4-g5 29.Kg5-h6 30.Kh6-h7 31.Kh7-g8 32.Kg8-f8 {
} 33.Kf8-e8 34.Ke8-d8 35.Kd8-c8 36.Kc8-b8 37.Kb8-a7 38.Ka7-b6 39.Kb6-b5 40.Kb5-c4 {
} 41.Kc4*b3 42.Kb3-c4 43.Kc4-b5 44.Kb5-b6 45.Kb6-a7 46.Ka7-b8 47.Kb8-c8 48.Kc8-d8 {
} 49.Kd8-e8 50.Ke8-f8 51.Kf8-g8 52.Kg8-h7 53.Kh7-h6 54.Kh6-g5 55.Kg5-h4 56.Kh4-g3 {
} 57.Kg3-h2 58.Kh2-g1 59.Kg1-f1 60.Kf1-e1 61.Ke1-d1 62.Kd1-c1 63.Kc1*b1 64.Kb1-c1 {
} 65.Kc1-d1 66.Kd1-e1 67.Ke1-f1 68.Kf1-g1 69.Kg1-h2 70.Kh2-g3 71.Kg3-h4 72.Kh4-g5 {
} 73.Kg5-h6 74.Kh6-h7 75.Kh7-g8 76.Kg8-f8 77.Kf8-e8 78.Ke8-d8 79.Kd8-c8 80.Kc8-b8 {
} 81.Kb8-a7 82.Ka7-b6 83.Kb6-b5 84.Kb5-c4 85.Kc4*c3 86.Kc3-d3 87.Kd3-e4 Ra2-a3 {stalemate}

5 - h#3 Checkless chess

McDowell, M.
2016

white Pf2g2h2 Rh1 Bc1 Ke1 black Pc5e4b2 Kg4

h#3 Checkless chess(6+4)

The only checks allowed are checkmates

Solution

{

} 1.b2-b1=Q f2-f4 2.e4*f3 ep. 0-0 3.Qb1-g6 g2*f3 # {

Valladao theme: a castling, a promo, an ep. capture
. Pity that the rook is not used for the mate (which even without it would not be a model because of the double impediment of 4...Kf4).
More clever would have been to present the problem without the Th1, provided the solutionist was warned (April Fish).
Thus one considers to be in a game with advantage of the King-Rook, which authorizes "castling" in the form Ke1-g1,

. as in a 1962 AV problem.}

6 - 6# with rose

Kampmann, B.
2015

white Kc1 ROd7 black Pa2c2e7 Ka1 Bd1 Rg6

#6(2+6)
󼎜d7: Rose

Extended knight in rounding
. the Rose d7 can go for example to h3 via c5, d3 and f2

Solution

{

Try :
} 1.ROd7-h3 ? {via c5, d3 and f2 threatening} 2.ROh3-b3 # {via g5, e6 and c5
} 1...Rg6-b6 2.ROh3-g1 + {
} 1...Rg6-g3 2.ROh3-e6 {
but} 1...e7-e6 !{

Solution :
} 1.ROd7-c5 ! {threatens} 2.ROc5-b3 # {
} 1...Rg6-g3 2.ROc5-e6 {threatens} 3.ROe6-d4 + {
} 2...Rg3-d3 {and there, } 3.ROe6-g1 + {is parried by } Bd1-f3 {and} 4.ROg1-d4+ {doesn't work because of the rook
the right move is} 3.ROe6-g5 {which threatens } 4.ROg5-a5 + {via f7, d8 et b7 and followed by mat
} 3...Rd3-a3 4.ROg5-g1 + {
} Bd1-f3 {(this variant is the most interesting, as it justifies the the thematic try, but ends with a dual mat, justifying a certain reluctance to set it up as a main variation)
} 5.ROg1-d4 + Ra3-b3 6.ROd4*b3 # {ou} 6.ROd4*c2 # {
} 4...Ra3-f3 5.ROg1-d4 + Rf3-b3 6.ROd4*b3 # {
} 4...Ra3-b3 5.ROg1*b3 # {
} 1...Rg6-b6 ? 2.ROc5-g1 + Bd1-f3 3.ROg1*f3 + Rb6-b3 4.ROf3*b3 # {ou
} 3.ROg1-d4 + Rb6-b3 4.ROd4*b3 # {ou} 4.ROd4*c2 #

7 - 2# with locusts

Loustau, JM.
2015

white Ka2 WLa7 Qb3 Pa5f6d2 Sa8c4 Rb5 black Pb6b7d7 Kc6 BLf8f4d5

#2(9+7)
🨊a7, 🨐f8, f4, d5: Locust

: Like the Grasshopper, except that it eats the sautoir.
The sautoir must be on the opponent's side and the finishing square just behind must be free

Solution

{

You can't checkmate in one by } 1.WLa7*b6-c5 + ? BLf8*c5-b4 ! {
neither by } 1.WLa7*b7-c7 + ? BLf4*c7-b8 ! {

Tries :
} 1.Sc4-b2 ? {or elsewhere threatening } 2.Qb3*d5 # {is parried by} 1...BLd5*d2-d1 ! {preventing} 2.Qb3-d5 {by} BLd1*d5-d6! {
} 1...BLf8*f6-f5 2.WLa7*b6-c5 # {A
} 1...BLf4*f6-f7 2.WLa7*b7-c7 # {B
} 1...d7-d6 2.WLa7*b7-c7 # {

Solution :
} 1.Sc4-d6 ! {menace} 2.Qb3*d5 # {
} 1...BLf8*f6-f5 2.WLa7*b7-c7 # {B (on } 2.WLa7*b6-c5 BLf4*d6-c7 ! {)
} 1...BLf4*f6-f7 2.WLa7*b6-c5 # {A (on } 2.WLa7*b7-c7 BLf8*d6-c5 ! {)
} 1...BLf8*d6-c5 2.Rb5*b6 # {
and the moves do not parry the threat :
} 1...b6*a5 {or} 1...Kc6*d6 2.Qb3*d5 # {
} 1...BLd5*d2-d1 ! 2.Qb3-d5 # {

Mats exchanged (AB-BA).
As in a 1959 Kopnine problem: times change, but so little...
One of the few fairy compositions by JML, a regular on the Saint-Lazare course, that I managed to understand !}

8 - hs#4,5 2 solutions köko

Rallo, V.
2012

white Pe3 Ke4 black Sg6 Bh2 Kh5

hs#4.5 Köko(2+3)

on the landing of a move, a unit must be in contact with another unit

Solution

{

} 1...Bh2-f4 2.Ke4-f3 Sg6-e5 + 3.Kf3-g3 Se5-g4 + 4.e3*f4 {and here, not} Sg4-h6 5.Kg3-h4 {which would be parried by } Kh5-g6 ! {
} 4...Sg4-e3 5.Kg3-h4 {and the only legal move is } Se3-f5 # {
Note also that } 4...Sg4-e5 {, to get closer to the second solution, does not work :} 5.Kg3-h4 Se5-f3 + 6.Kh4-g3 {

} 1...Sg6-e5 2.Ke4-f5 Kh5-g4 + 3.Kf5-g5 Kg4-h3 4.Kg5-h4 + Bh2-f4 5.e3*f4 Se5-f3 # {

Echo.}

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