py_20170627

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1 - s#9 AntiCirce

AntiCirce : the capturing piece is reborn on its original square if it is free,
otherwise the capture is illegal. The captured piece disappears

Millour, RJ.
2013

white Bh3a5 Ka6 Qe7 Pg6h4d5 Sh2c4 Ra2a7 black Pg7c5d6 Sd1 Bh8 Ke1 Rb4

s#9 AntiCircé(11+7)

Solution

{tries :
} 1.Qe7-e3 ? Sd1*e3[bSe3->b8] + 2.Ka6-b6 {because bR cannot be reborn in h8.
} 1.Ra2-f2 ? Ke1*f2[bKf2->e8] {because wQ cannot be reborn on d1.

} 1.Bh3-g4! Sd1-e3 2.Ra2-f2 Se3-d1 3.Rf2-f8 ! {3.h5 ? Kxf2 (Ke8) because once again 4 Qxe8 (Qd1) is impossible
} 3... Sd1-e3 4.h4-h5 ! {4.Rxh8 ? (Ra1)+ Kf2} Se3-d1 5.Qe7-h4 ! {Not check, but only leaves } 5...Sd1-f2 {
} 6.Rf8*h8[wRh8->a1]+ Sf2-d1 7.Ra1-a2 {return
} 7... Sd1-f2 8.Qh4-g3! {8 Qe7+? Ne4!} Sf2-d1 {and, now that the Bh8 is gone :} 9.Qg3-e3 Sd1*e3[bSe3->b8]# {

"High precision mechanics" (M. Kerhuel).}

2 - h#4,5 AntiCirce

Sobrecases, G.
2010

white Kg3 Bd1 Sb1 black Pe6g5g4f3e3d3c2b2 Kc4 Re2 Sh2

h#4,5 AntiCirce(3+11)

Solution

{

Apparent Play
} 1... ... 2.c2-c1=B Bd1-a4 3.Re2-d2 Ba4-e8 {or} 3... Ba4-d7 {or} 3... Ba4-c6 {or} 3... Ba4-b5 + 4.Kc4-b3 Kg3*h2[wKh2->e1] {tempo} 5.Kb3-c2 Bb5-a4 # {

Try :
} 1...Sb1-c3 ? 2.c2-c1=B Bd1-a4 3.Re2-d2 Ba4-b5 + 4.Kc4-b3 Kg3*h2[wKh2->e1] 5.Kb3-c2 Bb5-a4 {and} 6.Kc2-b1 { would demolish in AntiCirce Calvet, but by default, we are in Cheylan type where captures on rebirth square are illegal.} Sc3*b1 {is therefore impossible

Real play
} 1...Sb1-d2 + 2.Kc4-c3 Sd2-f1 3.c2-c1=B Bd1-a4 4.Kc3-c2 Sf1-d2 + 5.Sh2-f1 + Sd2*f1[wSf1->b1] # {
Double round trip}

3 - h=2,5 Duplex Masand

duplex : the statement is valid for both sides

. masand: a unit that checks causes the units it observes to change colour, Kings excepted

Stun, J.
2016

white Ke5 Sh1 black Kc3 Ra2

h=2,5 duplex masand(2+2)
b) Ch1-->e1

Solution

{

} a) {
} 1... Sh1-f2 2.Ra2-b2 Sf2-d1[b2=w] + 3.Kc3-d3 Ke5-d5 {pat
} 1...Ra2-a1 2.Ke5-f4 Ra1-f1[h1=b] + 3.Kf4-e3 Sh1-g3 {pat

} b) wSh1-->e1{Nh1-->e1
} 1...Se1-d3 2.Kc3-c2 Sd3-b4[a2=w] + 3.Kc2-d1 Sb4-d3 {pat
} 1...Kc3-b4 2.Se1-g2 Ra2-e2[g2=b] + 3.Ke5-d4 Sg2-f4 {pat}

4 - h#2,5 Ghost Chess swapping Kings

Ghost chess a piece can play normally or from its original square

. swapping Kings put in check, Kings swap places

Foster, G.
2016

neutral Pe7a7 black Ke5 white Kd8

h#2.5 fantômes Rois permutant(1+1+2)
2 sol.

Solution

{

} 1... nPe7-e8=nB 2.Ke5-d4 nPa7-a8=nQ[wKd8->d4][+bKd8] + 3.nQa8-a3 Kd4-c4[bKd8->c4][+wKd8] #{
Even if bB plays h3, it will will continue to give check from f1.

} 1... nPa7-a8=nB 2.Ke5-d6 nPe7-e8=nQ[bKd6->d8][+wKd6] + 3.nQe8-b5 Kd6-c6[bKd8->c6][+wKd8] # {
b5 & d6 are covered by the B and Q respectively

Reciprocal promotions.}

5 - serial #5 Köko

Köko : at the end of a move, the unit that has played must be in contact with another piece

Glass, G.
1999

white Pg7 Ke5 Bf8 black Ka8

ser-#5 Köko(3+1)
b) Tf8

Solution

{

} a){
} 1.g7-g8=Q 2.Bf8-d6 {(no check !)} 3.Bd6-b8 4.Qg8-c8 5.Bb8-a7 #{

} b) +wRf8 {Rf8
} 1.Rf8-h8 {(critical move)} 2.g7-g8=Q 3.Qg8-b8 4.Rh8-c8 5.Qb8-a7 #

6 - serial s#7 Circe

circe captured unit is reborn on its native square

Laborczi, Z.
2004

white Pb7h7e5 Ke3 black Qb8 Pg4 Ke1

ser-s#7 Circe (4+3)
2 sol.

Solution

{

} 1.h7-h8=Q 2.Qh8*b8[+bQd8] 3.Qb8-a8 {(pawn e5 prevents 3.Qh2)} 4.b7-b8=S {
} 5.Sb8-c6 6.Sc6-d4 7.Qa8-h1 + Qd8*d4[+wSg1] #{

} 1.h7-h8=R 2.Rh8*b8[+bQd8] 3.Rb8-a8 4.b7-b8=B {
} 5.Bb8-a7 {(le pion e5 empêche 5.Fe5)} 6.Ba7-d4 7.Ra8-a1 + Qd8*d4[+wBc1] # {
AUW}

7 - h#5 with Double Grasshopper

Grasshopper : moves on the Queen's lines with the help of a sautoir behind which it lands.
. It is necessary that the arrival square is free or occupied by an opposing piece
. Double Grasshopper: makes 2 grasshopper steps in a row.

Kotesovec, V.
2015

white DGf5h3a3c1 black Ke6

h=5(4+1)
4 sol.
f5, h3, a3, c1: Double Sauterelle

Solution

{

} 1.Ke6-f6 DGh3-g6 {(via e6)} 2.Kf6-e7 DGa3-f4 {(via f8)} 3.Ke7-f6 DGc1-e7 {(via g5)} 4.Kf6-g7 DGf5-f7 {(via h7)} 5.Kg7-h8 DGf4-f6 {(via f8)stalemate

} 1.Ke6-e5 DGh3-e4 2.Ke5-f4 DGc1-e5 3.Kf4-g3 DGa3-e6 4.Kg3-g2 DGe4-f3 + 5.Kg2-h1 DGe6-g2 {stalemate

} 1.Ke6-d7 DGf5-e6 2.Kd7-d6 DGa3-e5 3.Kd6-c7 DGc1-c6 4.Kc7-b8 DGh3-f5 5.Kb8-a8 DGf5-b7 {stalemate

} 1.Ke6-d5 DGh3-g4 2.Kd5-c4 DGg4-b3 3.Kc4-c3 DGc1-c2 4.Kc3-b2 DGa3-c3 5.Kb2-a1 DGf5-b4 {stalemate

the four corners.}

8 - #2 Annan

Annan A unit acquires the march of the friendly unit below it. For example the Na3,
because of Ba2, is momentarily a bishop that nails Rb4. But the Bc1, now a pawn (because of c2)
does not nail Nf4, any more than bQ pinss wR.

Gockel, H.
2015

white Be2a2 Kh6 Qd3 Pc4b2 Sf4a3 Re6 black Bc1 Kc5 Qb6 Pf5c2b7d4 Sh4f1 Rb4

#2 Annan(9+10)

Solution

{

essais
} 1.Qd3-f3 ? {threatens} 2.Qf3-d5 # 1...Sh4*f3 2.Sf4-d3 # but 1...Sf1-e3 !{Please note that } 2.Sf4-d3 {is not possible since the Knight now has the Queen's march !
} 1.Qd3-d2 ? {threatens} 2.Qd2*b4 # 1...Sf1*d2 2.Sf4-d3 # 1...d4-d3 2.Qd2-c3 # but 1...Qb6-b5 ! {and there} 2.Sf4-d3 {does not even check since the Knight now has the Queen's march !
} 1.Qd3-h3 ? {menace} 2.Sf4-d3 # but 1...d4-d3 !{
} 1.Qd3-b3 ? {threatens} 2.Sf4-d3 # but 1...d4-d3 !{one might think that} 2.Qb3-c3 {checkmates by taking the Queen's moving way on pc4, but this move is impossible, since on b3, the Q has the march of a pawn !
} 1.Qd3-c3 + ? but 1...d4*c3 !{
} 1.Qd3-g3 ? {threatens} 2.Sf4-d3 # but 1...d4-d3 !{

} 1.Qd3*c2 ! {threatens} 2.Qc2-a4 # {Queen moves as Na3
} 1...Bc1*b2 2.Sf4-d3 #{
} 1...d4-d3 2.Qc2-c3 # {pc4 moves as Qc3
} 1...Qb6-b5 2.c4*b5 #

9 - #2 vertical cylinder with Nightriders

vertical cylinder the chessboard is a cylinder whose columns a and h are the contact lines
Nightrider : extended Knight

Chicco, A.
1940

white Qd7 Ph5h4g4c5 Kh8 Ng1d8 black Bg6 Kh6 Nc1d1e1 Pg5b7b6a5b4 Sb1 Rf7b3

#2 vertical cylindric (8+13)
g1, d8, c1, d1, e1: Nightriders

Solution

{

} 1.Qd7*b7 ? Nd1-f5! {pinning wQ

} 1.Qd7-d6 ! {Pinning Pb6.
} 1... Sb1-d2 {or} 1... Sb1-h2 {or Rb3-b3 -sic- (threat variation)} 2.h4*a5# {
Seven interceptions of the Nightriders by the bR, leading to 7 separate mats.
} 1... Rb3-a3 {(interception of NIe1 via g2 !) or } 1... Ne1*g4 {abandonment of guard)} 2.Qd6*g6# {
} 1... Rb3-c3 {(interception of NId1)} 2.Qd6-b8 # {
} 1... Rb3-d3 {(interception of NIc1)} 2.Nd8*f7# {
} 1... Rb3-e3 {(interception of NId1)} 2.Qd6-f8# {
} 1... Rb3-f3 {(interception of NIe1)} 2.h4*g5# {(supported by NIg1 via a4 or a2)
} 1... Rb3-g3 {(interception of NIc1)} 2.Ng1-a4# {
} 1... Rb3-h3 {ou} 1... Rb3-b2 {(interception of NId1 via b2 !)} 2.Qd6*b6# {
} 1... g5*h4 {(ouverture de ligne)} 2.Ng1-a8# !! {via a4-g5 : seven steps of Knight! and not} 2.Qd6-f4 + ? Ne1-g5 {
} 1... a5-a4 {or} 1... a5*h4 2.Ng1*b7# {via h3-a5
} 1... Nd1-e3 2.Qd6*b6# {or} 2.Qd6-b8# {
} 1... Nd1-f2 2.Qd6-f8# {or} 2.Qd6-b8 #

10 - h#4 Functionnaries

Dietrich, St
2010

white Kc3 Bd4 Sc2 black Sc4d2 Kc1

h#4 Functionnaries(3+3)
b) Kings moved one square right

Functionnaries : a unit can only move, and "a fortiori" capture, if it is threatened (observed) by an opposing unit

Solution

{

} a) {

} 1.Sd2-b1 {no check} Kc3-b3 2.Sc4-d2 {display-departure-file} {no check} Kb3-a2 3.Sb1-a3 Sc2-e3 4.Sa3-c2 {oberve Ne3} Bd4-b2 #{

} b) wKc3-->d3 bKc1-->d1 {the 2 Kings moved one square right}{

} 1.Sd2-f3 Bd4-e5 {tempo} 2.Sc4-e3 Be5-f6 3.Se3-d5 Sc2-e3 + {checks as observed by Nd5 which also observes Bg5} 4.Kd1-e1 Bf6-h4 #

11 - #2 Isardam

Caillaud, M.
1997

white Kg1 Pd3g7h7 Rc2 Ba4 Sb1a1 black Pd2c5 Kc3 Rc4 Se4 Ba2

#2 Isardam(8+6)

Isardam : Il est illégal que 2 pièces adverses de même nature s'observent

Solution

{

} 1.h7-h8=B ! {threatens} 2.g7-g8=Q # 2.g7-g8=S # 2.g7-g8=R # 2.g7-g8=B #{

} 1...Ba2*b1 {or} 1...d2-d1=S {these 2 moves free the Ne4 to intercept the check with Nf6, but it remains} 2.g7-g8=S #{

} 1...d2-d1=Q + 2.g7-g8=Q #{

} 1...d2-d1=R + 2.g7-g8=R #{

} 1...d2-d1=B {paralyses Rc2 and thus releases Rc4 making Rc4-d4 possible, but there is } 2.g7-g8=B # {

Babson task.}

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