W.: Kc5, Qc4, Ra1 and h1, Bb1 and e3, Nd2 and g1, pa3, b2, b5, d3, d5 and e4
B.: Ke8, Qd8, Ra8, Bc8 and f8, Nb8 and g6, pa7, b7, c7, d7, e5 and g7
This PG was composed by the Grand Master, hang on.
Let's continue the warm-up with the next PG in the Circe rules
.
2 - PG in 9,5 moves Circe Rex inclusiv
Circe : the captured piece is reborn on its original square except if this one is occupied in which case it disappears
Kings included : Kings are also concerned by the condition Circe
.

W.: Kg1, Qd1, Ra1 and f1, Bc1 et c6, Ne3 and f3, pa2, b2, c2, d3, f2 and g2
B.: Kd7, Qd8, Ra8, g3 and h8, Bc8 and f8, Nb8 and g8, pa7, b7, c7, e5, f7, g7 and h7
Note that Black King is "en prise" but not in check, since he can reborn in e8!
Still in the Circe Rex inclusiv rules, a reflex problem.
3 - r#2 Circe Rex inclusiv
Reflex : when a checkmate in 1 move is presented to one of the 2 sides, he must play it
white Ka4 Rc8 Sa5 Be8
black Bc3a6 Ka2 Qb7 Pb2c4d4g3g2 Sa1 Rb1e5
r#2(4+12)Circé Rex inclusiv
{}
1.Ka4-b3 + !{}
1...Sa1*b3[+wKe1] +
2.Ke1-e2
2...Bc3-e1 #{}
1...c4*b3[+wKe1] +
2.Ke1-d1
2...Re5-e1 # {display-departure-file} {}
1...Qb7*b3[+wKe1] +
2.Ke1-d2
2...Rb1-e1 # {display-departure-file}
A totally destabilising problem.
Rest and aesthetics with the next problem
4 - h#4 3 solutions with Grasshopper and Wazir
helpmate : Black plays and help the White to mate them
3 solutions : there are three distinct solutions (which therefore start with different moves)
Grasshopper : Piece that moves on Queen's lines and needs a hurdle to move. It lands just behind the hurdle if the square is free or
occupied by an opponent's piece, otherwise the move is not possible.
Wazir : piece moving as a Rook but only one step
white Kh1 WEa8 Gd5
black Ka5 Rb6 Sc5
h#4 3 solutions(3+3)d5: Grasshopper
a8: Wazir
{
}
1.Sc5-b3 Gd5-a2 2.Rb6-b4 Ga2-c4 3.Sb3-d4 WEa8-a7 4.Sd4-b5 WEa7-a6 # {
}
1.Sc5-d7 Gd5-d8 + 2.Ka5-a6 Gd8-a5 3.Rb6-b5 Ga5-c5 4.Sd7-b6 WEa8-a7 # {
}
1.Sc5-b7 WEa8-b8 2.Ka5-b5 Gd5-a8 3.Kb5-a6 Ga8-c6 + 4.Ka6-a7 WEb8-a8 # {
mate on all floors !}
Very clean composition
Now, the Transmuted Kings
5 - h#2 Transmuted Kings
Transmuted Kings : a checked King takes the step of the piece which puts it in check for the time it takes to make its move. Of course, in the case of a double chess, he chooses which piece he will take the step from.
white Kd1 Ba8 Sd5
black Qh3 Kh1 Rd7g6
h#2 Transmuted Kings(3+4)
{}
1.Qh3-f1 + Kd1-h5 2.Qf1-f7 Sd5-c7 #
Great art
Again with the same rules
6 - h#2,5 Transmuted Kings
h#2,5 : White begins
white Rb5 Kh8 Bg4
black Qa1 Kd4 Bg5
h#2 Transmuted Kings(3+3)
{}
1...Rb5-d5 + 2.Kd4-a4 + Kh8-a8 3.Bg5-c1 Bg4-d1 #
Also a very nice composition, a true pleasure.
To keep the fun running
7 - h#3 Transmuted Kings with Nightrider b) Qh6-->a6
Nightrider : Extended Knight
white Qh6 Kd5
black Pf5g5 Kf4 Nd1
h#2 Transmuted Kings(2+4)b) Qh6-->a6
{}
a) {}
1.Nd1-h3 Qh6*g5 + 2.Kf4-h2 + Kd5-f1 3.Pf5-f4 Qg5-g2 # {}
b) wQh6-->a6 {Qh6-->a6}
1.Pg5-g4 Kd5-e6 2.Kf4-g5 Ke6-f7 3.Nd1-h3 Qa6-h6 #
For those who are not familiar with the Nightrider, NRd1 can jump to b2, c3, b5, a7, e3, f2 and h3
For the continuation, now that the neuron is warmed up, we begin to work on Chinese pieces.
8 - h#2 Circe 2 solutions with Pao
Pao : moves on the Rook lines but needs a hurdle to capture
white Ke1 Bh6 PAh5 Sf6
black Qd7 Kg6
h#2 Circe(4+2)2 solutionsh5: Pao
{}
1.Qd7-g4 Sf6-h7 2.Kg6*h5[+wPAh8] Sh7-f8 #
{}
1.Qd7-g7 PAh5-g5 2.Kg6*h6[+wBc1] PAg5-g6 #
A little clarification : when a fairy piece is taken, it is reborn on the capture column and on the promotion row of its side.
Now a small look at Functionnary Chess
9 - #2 Functionnary Chess
Functionnary Chess : a piece can only move and a fortiori capture if it is under attack by an enemy piece
white Sf3e8 Re4b7 Kc8 Bc5
black Qa1 Pg2f5d5 Sb1e5 Bc1c6 Ke6
#2(6+9)Functionary Chess
{}
1.Rb7-g7 ! zugzwang.
1...g2-g1=Q
2.Rg7-e7 #{}
1...g2-g1=S
2.Re4*e5 #{}
1...g2-g1=R
2.Sf3-d4 #{}
1...g2-g1=B
2.Sf3-g5 #
Good luck
Help yourself with a drink, if you haven't already done so for the next one.
10 - s#9 Isardam
selfmate : Whites plays and forces Black to mate them.
Isardam : it is totally illegal to place 2 opposing pieces of the same nature in mutual control
white Pb7h7 Ka5
black Pa2d6 Ka1
s#9 Isardam(3+3)
{}
1.b7-b8=Q d6-d5 2.Qb8-b3 d5-d4 3.Ka5-b4 d4-d3 4.Qb3-d1 + Ka1-b2 {}
5.h7-h8=B + a2-a1=B 6.Qd1-a4 d3-d2 7.Kb4-b3 + d2-d1=Q 8.Bh8-c3 ! Qd1-c2 {(Kxc3#)} {}
9.Qa4-a3 + ! {(9 Qb4#? etc.)} Qc2*c3 #
To help you a little, this condition does not apply to Kings. Moreover, the capture of a King is illegal if it puts 2 opposing pieces in mutual control as indicated in the
Isardam rule
A short excursion in the Köko
11 - h#3 2 solutions Köko
Köko : in order for a move to be legal, the piece must be in contact with another element (friend or opponent, no matter) at the end of the move.
white Ke2 Bc4
black Qc3 Pf5f4g4 Ke4 Ba6 Rd5
h#3 Köko(2+7)2 solutions
{}
1.Qc3-e1 Ke2-f1 2.Qe1-e3 Bc4-d3 + 3.Ke4-f3 Kf1-g2 #
{}
1.Rd5-b5 Bc4-b3 2.Qc3-f6 Ke2-d3 + 3.Ke4-e5 Kd3-d4 #
A little rest with another beautiful problem
12 - h#2 Circe with Grasshopper
white Pf3 Kb1 Gf4
black Bh6 Kh8 Qf5 Pe4g3 Sg8d5 Rh7g7
h#2 Circé(3+9)b) Ng8=B
{}
a) {}
1.Sg8-f6 Pf3*e4[+bPe7] 2.Qf5*f4[+wGf8] Pe4*d5[+bSg8] # {}
b) +bBg8 {Bg8}
1.Rg7-g6 Gf4-f6 2.Qf5*f3[+wPf2] Pf2*g3[+bPg7] # {}
To finish off your neuron's connections, the Andernach rule
13 - h=2 Andernach
Andernach : a piece changes colour after capturing (Kings are not affected)
white Pg5g7g4c7a6c4 Kf3 Bf7 Sf5
black Pc2a7 Ke5 Rb8
h=2 Andernach(9+4)b) Rb8-->h8
{}
a) {}
1.c2-c1=R c7*b8=B=b 2.Rc1*c4=w Rc4-c7 [+wRc7] {stalemate}
b) bRb8-->h8 {}
1.c2-c1=Q g7*h8=S=b 2.Qc1*g5=w Qg5-g6 [+wQg6] {stalemateAUW}
Very nice
Rule is now reversed with the anti-Andernach
14 - h#2 anti-Andernach
anti-Andernach : when a piece move without capturing, it changes colour (Kings are not included)
white Qb8 Pc5e7g7g5 Sh8f5 Rc7e1 Ke4
black Ph5 Ke6 Bb6 Rb3
#2(6+9)AntiAndernach
{}
1.e7-e8=B=b ! threat:
2.Qb8*e8 # {}
1...Bb6*c5
2.Qb8*b3 # {}
1...Be8-a4=w
2.Ba4*b3 # {}
1...Be8-b5=w
2.Qb8*b6 # {}
1...Be8-c6=w
2.Ke4-f4 # {}
1...Be8-g6=w
2.Ke4-d4 #
Very nice problem too
A new incursion into Chinese pieces
15 - h#4,5 with Pao and Vao
4,5 moves : White begins
Pao : see 8
Vao : as Pao, but on Bishop lines
white Pb4b2f3 Kg1 PAf4 VAb6
black Pb5e3 Sh1c4 Bd6e6 Ke7 Rf6
h#4,5(6+8)b) b2-->e2f4: Paob6: Vao
{}
a) {}
1...VAb6-d4 2.Bd6-e5 VAd4-c3 3.Ke7-d6 PAf4-d4 4.Kd6-d5 PAd4-d1 5.Kd5-d4 VAc3-d2 #{}
b)wPb2-->e2{pb2-->e2}
1... PAf4-d4 2.Be6-d5 PAd4-d2 3.Ke7-e6 VAb6-d4 4.Ke6-e5 VAd4-a1 5.Ke5-d4 PAd2-b2 #
A series of helpmate in 7, but from remembering, so there will be mistakes from hand or head.
16 - h#7
white Ph2 Sh8 Kh4
black Kf3
h#7(3+1)
{}
1.Kf3-e4 Kh4-g4 {}
2.Ke4-e5 h2-h4 {}
3.Ke5-f6 h4-h5 {}
4.Kf6-g7 h5-h6 + {}
5.Kg7*h8 h6-h7 {}
6.Kh8-g7 Kg4-f5 {}
7.Kg7-h6 h7-h8=Q #
17 - same énoncé
white Pa2 Kf8 Ba4
black Kb1
h#7(3+1)
{}
1.Kb1-c1 Ba4-e8 {}
2.Kc1-d2 a2-a4 {}
3.Kd2-e3 a4-a5 {}
4.Ke3-f4 a5-a6 {}
5.Kf4-g5 a6-a7 {}
6.Kg5-h6 a7-a8=Q {}
7.Kh6-h7 Qa8-h1 #
18 - s.é.
white Pb3b2 Kh2
black Ka7
h#7(3+1)
{}
1.Ka7-b6 Kh2-h3 {}
2.Kb6-c5 b3-b4 + {}
3.Kc5-d4 b4-b5 {}
4.Kd4-e3 b5-b6 {}
5.Ke3-f2 b6-b7 {}
6.Kf2-g1 b7-b8=Q {}
7.Kg1-h1 Qb8-h2 #
19 - s.é.
white Pd2 Kd3 Bc3
black Kh3
h#7(3+1)
{}
1.Kh3-g4 Kd3-c2 {}
2.Kg4-f5 d2-d4 {}
3.Kf5-e6 d4-d5 + {}
4.Ke6-d7 d5-d6 {}
5.Kd7-c6 d6-d7 {}
6.Kc6-b5 d7-d8=Q {}
7.Kb5-a4 Qd8-a5 #
And to conclude, a splendid helpmate
20 - h#2 Circe
white Pe3f6 Sd1 Be2 Kh7
black Qd3 Pe6e5f5 Ke4 Rh2 Sg2h3
h#2 Circe(5+8)2 solutions
{}
1.Rh2-h1 Be2*d3[+bQd8] + {}
2.Qd8*d3[+wBf1] Bf1*g2[+bSg8] #{}
1.Qd3*e2[+wBf1] Bf1*e2[+bQd8] {}
2.Qd8*f6[+wPf2] Sd1-c3 #
Saving time by seeming to lose time and vice versa, this is the solutionist's guiding principle for this beautiful problem.
It remains for me to wish you good reading and good holidays, during which I am sure you will not fail to take the various reports
to read them on the beach.
Rendez-vous very soon for the corrections.
Kindly yours
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