december 13 2011


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or directly on the move in the solution

Small delay in the report; cause of the great richness of the material proposed by the Master. A little more assembly than usual for this parenthesis is fairy session.
We have noted the return of the great Ricou and of our composer (and solutionist), in the person of the immense Michel. I take advantage of the intro to give you the date of the next session which will be held on the first Tuesday of the year, that is to say the January 3rd.
In the absence of the aforementioned, Master took the opportunity to deliver two remarkable compositions of a relatively new genre.
To warm up, a first composition

series s#10 reversible Promotion

Bell, A & Caillaud M
2011

white Ra3 Qb3 Pb2d2 Bb5 Se2g1 Kd1 black Ba4 Kb1
ser-s#10 reversible Promotion(8+2)
: White plays n moves in a row and force Black to checkmate them in one move
: a promotion piece that returns to an initial pawn square becomes a pawn again
A small help :
the last moves could only be Ba2xQ(or B)b1+, ...Ka1xb1.
Ba2, remaining Bishop, was necessarily the original f1 Bishop and so Bb5 comes from a promotion.

Comments on some problems for New Year's Eve.
Three #2. The first one solves itself in 3 seconds, at least when you have a certain practice. But that doesn't prevent you from enjoying it. The second shows a "reciprocal correction". A bit abstruse? All this will be clear when you have solved it, in just a little more time. The 3rd has a real JA ("apparent play"), i.e. motivated by a try. He may ask you for two more minutes.

The #3 shouldn't give you a headache either. It is a kind of praise for idleness. The #9 is a bit stronger, but the #10 is obvious: its purpose is to explain a useful rule to the beginner.
A Gamnitzer s#5 is always a party. Very well, precisely between two "parties", during the recovery.
I've saved the helpmates for the end, contrary to what I'm used to. Of the 4 solutions of the first one, one may embarrass you. One of the h#4 is easy, the other difficult: guess which one. Finally a long and lovely walk.

The fairies will be presented by the master-tabellion. Here's one of them, which had an unexpected success on a usually lethargic forum... as soon as interesting things are discussed.
Following a conversation about the tournament which has just ended, I enclose a quick overview of the key game, emblematic example of the difference between human analysis and computer copies. For those who are decidedly resistant to the world of the problem, it will be a bit of reading for Christmas.
See you in three weeks time for a course that will be back to "normal" on 3 January. Merry Christmas then. God bless you.
And have a good time.
AV

 

Now that the neuron is warm, let's move on to a more serious piece!

1 - series s=44 reversible Promotion

Michel CAILLAUD
11è Saké jesi, 2011
2nd Prize

white Pa2b4d6c7 Kc1 black Qg2 Pc2c3b5 Kc8 Rb6d7 Bf5
ser-s=44 reversible Promotion(5+8)
: White plays n moves in a row and force Black to checkmate them in one move
: a promotion piece that returns to an initial pawn square becomes a pawn again A small help : if there was no Rb6, we could do 5.a8=Q+ QxQ stalemate, it must be eliminated beforehand (and it takes 39 moves!). A problem that is completely understandable and therefore accessible, so look for it, you won't waste your time.


In the same thematic competition, here is the first prize.

2 - series s#48 reversible Promotion

Ofer COMAY & Mark ERENBURG
11è Saké jesi, 2011
1st Prize

white Pb2g2 Kb6 black Qa8 Pd6e6b3 Kb8 Rc7c5f7 Sf4b5
ser-s#48 reversible Promotion(3+10)

It can be noted that Rc5 is necessarily a promotion piece.
we are beginning to see some "out of the ordinary" pieces and other conditions

3 - #2 with Grasshoppers and Nightrider hopper

Vaclav KOTESOVEC
The Problemist, 2011

white WNb5 Bc3 Ga2c1d2e4b6 Kd7 Pc4a3 Sd5 black BNc8b2 Pd6 Sd1g5 Rg4 Kb3
#2(11+7)
a) Andernach
b) Circé Couscous
🨟a2, c1, d2, e4, b6: Grasshoppers
🨢b5, 🨨c8, b2: Nightrider hopper
a) : a capturing piece changes colour
b) : a captured piece is reborn on the original square of the capturing piece .
. : Prolonged Knight needing a jumper to perform his first movement (ex: NHb5 can go to f7 or h8).)
: moves to the Queen's lines needing a sautoir behind which it lands if that square is free or occupied by an opponent's piece.

A little relaxation with the following problem

4 - h#2,5 Couscous Circe

Vito RALLO
The Problemist supplément, 2008

white Pc5 Kd2 Sc4 black Pb6 Ke7 Se8
h#2,5 Couscous Circe(3+3)
2 solutions

now, a good head grip in Circe swinger

5 - series helpmate #9 Exchange Circe (PWC)

Chris FEATHER

neutral Pg8g7 black Ph8 Kf6 white Kb1
ser-h#9 Exchange Circe (PWC)(1+2+2)
b) neutral pawn h8
(PWC) : the captured piece is reborn on the starting square of the capturing piece's move.
: can be played by one side or the other

The bestiary is now open with the following composition from 1970

6 - h#2 with Grasshopper, Nightrider, Zebra et Camel

Venelin ALAIKOV
The Problemist, 1970

white WGh3f7 Ka8 Ne1 Ph2h6h7 Zg7e7 CAf5 black Pb5b4c2f6 Kf4 Ra5e3 BGa6
h#2(10+8)
2 solutions
b) -♜e3
🨟h3, f7, 🨥a6: Grasshoppers
🨢e1: Nightrider
🨍g7, e7: Zebra
🨷f5: Camel
: rider (2,3)
: rider (1,3)
: extended knight

7 - exact h#2 with Mao and Moa

Juraj LORINC
Jubilé C. Lytton-70
The Problemist, 2009
6th HM

white Pe5e2 MOg3g5 WMf6 Kd8 black Pe3d5 Ke6 BMg4
h#2 exact(6+4)
g3, g5: Moa
f6, g4: Mao
b) h#1,5 exact
c) h#1 exact
d) h#0,5 exact
: Crawling knight that first makes an orthogonal step and then a diagonal one
. The square of the first step must be empty
; Diagonal and then orthogonal creeping knight
A very nice problem.

A Peter Harris to seize head in your hands

8 - h#4 - AntiAndernach Maximum white

Peter HARRIS
The Problemist Supplément, 2011

white Ka8 black Qh2 Pe2f2g2 Kh1 Bg1f1 Re1
h#4 AntiAndernach(1+8)
Maximum white
b) -Re1
: a piece changes colour if it moves without capturing
: only White has to play the geometrically longest moves

9 - h#4 - Einstein

Lee POISSANT
The Problemist Supplément, 2011

white Ka2 Ba1 Sd1 black Pb2c6 Ke8 Rb1 Bc3
h#4 Einstein(3+5)
: a piece progresses by capturing and regresses by not capturing i.e. p -> N -> B -> R --> Q and in the opposite direction

10 - s#8 with Royal Grasshopper

Neal TURNER
The Problemist Supplement, 2007

white Sd2c4 white Royal WGe4 black Pe6d3 black Royal BGe8
s#8(3+3)
🨟e4, 🨥e8: Royal Grasshoppers
A very pure composition

An old problem since it dates back to 1931.

11 - #3 with Grasshoppers

Mark F. GORDIAN
Die Schwalbe, 1931
Prize

white Ph7 Kc2 black Pa2c4c6d6 Ka1 BGb1h2b8
#3(2+8)
🨥b1, h2, b8: Grasshoppers
  

12 - h#2 AntiSuperCirce with Lions

Vlaicu CRISAN
The Problemist, 2005

white Pc4 Kh7 Sf1 WLa3 black Pg5g3d4d6 Kf5 Bd3 Rc5 BLh1
h#2 AntiSuperCircé(4+8)
b) ♘f1-->c8
🨴a3, 🨺h1: Lion
: the capturing piece is reborn wherever it wants to be
: extended Grasshopper
  

13 - series h#11 Parrain Circe with Royal Queen

Brian CHAMBERLAIN

white Sa4 Kc1 black Pa6b7d7d6 black Royal Qe2
h#2(2+5)
: a captured piece remains in suspension and performs an equipollent movement on the next move.
: plays like a Queen but can be checkmated
  

14 - h#2 - Take&Make

Pierre TRITTEN

white Rh4 Kb2 Bc6 Se5 black Rh1 Kf6 Ba4 Pc5d4e3f3g3
h#2 Take&Make(4+8)
b) ♟c5-->e2
: when a piece captures, it replays a second move with the march of the captured piece

For the restauration part, we are facing a magnificent problem.

15 - s#2 - AntiCirce with Leos

Mario PARRINELLO
StrateGems, 2009
6th Prize

white Rg1 Sf7 WLc8 Kc2 Be1 black Pa5b2c4d4h3h5 Kh6 Ra2 BLd8
hs#2 AntiCirce(5+9)
3 solutions
c8, d8: Leos
: the capturing piece is reborn on its original square if it is free, otherwise the move is illegal.
: piece moving on the Queen's lines and needing a sautoir to capture
  

16 - h=10 coups - Ultra-Maximum with Grasshopper et Grasshopper-2

Andreas THOMA

white Kb4 Sd5 black Kc2 DGa8 Gc6
h=10 Ultra-Maximum(2+3)
🨥c6: Grasshopper
🨐a8: Grasshopper-2
: both sides are obliged to play the geometrically longest moves
: like a Grasshopper, but it lands 2 squares after the sautoir.
  
And to finish, a simple and magnificent work

17 - h#4 with Grasshopper

Tosten LINSS, Dieter MULLER &
Juraj LORINC
19è T.T. Chess Composition
Microweb, 2006 - 1st Prize

white Kf4 WGd1e1 black Kh8 BGf1c1g6g8
h#4(3+5)
2 solutions
🨟d1, e1, 🨥f1, c1, g6, g8: Grasshoppers

It remains for me to wish you all a good reading, to thank the Master for his course and his electronic report.
And to finish, have a good holiday season and start the course on January 3rd in good conditions.

Yours sincerely.
Le greffier

Master's rectifications

Problem 3: I think it is useful to specify that by "original square of the capturing piece", it is understood that the original square is determined by the finishing square. For example, after ...Nxe4, the grasshopper is reborn in g8, which would be the rebirth square of the BN in anti-circe.
Thanks to the greffier for the difference between "cuckoo" and "couscous" which I didn't know.
Problem 7: there is also a h#0.5, in other words an BK mat in one move.
Problem 16 : the "grasshopper-2" is in a8.
I can't see anything else.
Merry Christmas.

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